For a plain scale, RF = \(\frac{1}{4}\) and M.L = 5decimeters, what is LOS?(a) 1.25 cm(b) 12.5 cm(c) 12.5 m(d) 12.5dmI got this question in my homework.My doubt is from Scales in section Lettering Practice, Scales & Curves of Civil Engineering Drawing

For a plain scale, RF = \(\frac{1}{4}\) and M.L = 5decimeters, what is

1.	For a plain scale, RF = \(\frac{1}{4}\) and M.L = 5decimeters, what is LOS?(a) 1.25 cm(b) 12.5 cm(c) 12.5 m(d) 12.5dmI got this question in my homework.My doubt is from Scales in section Lettering Practice, Scales & Curves of Civil Engineering Drawing
Answer» Right OPTION is (B) 12.5 cm The best I can explain: LOS = R.FM.L = \(\frac{1}{4}\)5 *10 cm (Since 1dm = 10 cm) = 12.5 cm.

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For a plain scale, RF = \(\frac{1}{4}\) and M.L = 5decimeters, what is LOS?(a) 1.25 cm(b) 12.5 cm(c) 12.5 m(d) 12.5dmI got this question in my homework.My doubt is from Scales in section Lettering Practice, Scales & Curves of Civil Engineering Drawing

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