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If pKb for fluoride at 25°c is 10.83, the ionization constant of hydrofluoric acid in water at this temperature is?(a) 3.52×10^-3(b) 6.75×10^-4(c) 5.38×10^-2(d) 1.74×10^-5The question was asked in an international level competition.Query is from Ionization of Water, Weak acids and Weak Bases in chapter Water Basics of Biochemistry

Answer»

The correct ANSWER is (b) 6.75×10^-4

To explain: KW = KA × Kb

Ka = Kw / Kb

Ka = 10^-14/-log (10.83) = 6.75 × 10^-4.



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