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If the sum of three numbers which have difference of 3 between them is 633, then find the largest number?1). 2202). 3203). 2144). 206 |
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Answer» Let ‘x’ be the first number. Other TWO numbers are (x + 3) & (x + 6) GIVEN that, x + x + 3 + x + 6 = 633 ⇒ 3x = 624, x = 624/3 = 208 ⇒ Third number = (x + 6) = 208 + 6 = 214 ∴ Answer is 214 |
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