II. b2 - 53b + 702 = 01). a b3). a = b or the relationship cannot be determined4). a ≥ b

II. b2 - 53b + 702 = 01). a < b2). a > b3). a = b or the relationship

1.	II. b2 - 53b + 702 = 01). a < b2). a > b3). a = b or the relationship cannot be determined4). a ≥ b
Answer» I. a² - 25a – 26A + 650 = 0 ⇒ a² - 25a - 26a + 650 = 0 ⇒ a(a – 25) - 26(a - 25) = 0 ⇒ (a - 25)(a - 26) = 0 Then, a = 25 or a = 26 II. b² – 53b + 702 = 0 ⇒ b² - 27b – 26B + 702 = 0 ⇒ b(b - 27) - 26(b - 27) = 0 ⇒ (b - 27)(b - 26) = 0 Then, b = 27 or b = 26 So, when a = 25, a < b for b = 27 and a < b for b = 26 And when a = 26,a < b for b = 27 and a = b for b = 26 ∴ We can OBSERVE that a ≤ b.

Answer»

I. a² - 25a – 26A + 650 = 0

⇒ a² - 25a - 26a + 650 = 0

⇒ a(a – 25) - 26(a - 25) = 0

⇒ (a - 25)(a - 26) = 0

Then, a = 25 or a = 26

II. b² – 53b + 702 = 0

⇒ b² - 27b – 26B + 702 = 0

⇒ b(b - 27) - 26(b - 27) = 0

⇒ (b - 27)(b - 26) = 0

Then, b = 27 or b = 26

So, when a = 25, a < b for b = 27 and a < b for b = 26

And when a = 26,a < b for b = 27 and a = b for b = 26

∴ We can OBSERVE that a ≤ b.