1.

II. b2 + 54b + 53 = 01). a < b2). a > b3). a ≤ b4). a ≥ b

Answer»

I. a2 - 61A + 424 = 0

⇒ a2 - 53a - 8a + 424 = 0

⇒ a(a - 53) - 8(a - 53) = 0

⇒ (a - 8) (a - 53) = 0

Then, a = 53 or a = 8

II. b2 + 54B + 53 = 0

⇒ b2 + 53b + b + 53 = 0

⇒ b(b + 53) + 1(b + 53) = 0

⇒ (b + 1) (b + 53) = 0

Then, b = (-53) or b = (-1)

So, when a = (53), a > b for b = (-53) and a > b for b = (-1)

And when a = 8, a > b for b = (-53) and a > b for b = (-1)

∴ we can OBSERVE that a > b.


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