InterviewSolution
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II. y2 – 14y + 45 = 01). x < y2). x > y3). x = y OR the relationship cannot be determined4). x ≥ y |
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Answer» ⇒ x2 + 24x – 5x – 120 = 0 ⇒ x(x + 24) – 5(x + 24) = 0 ⇒ (x + 24)(x – 5) = 0 Then, x = - 24 or x = + 5 II. y2 – 14y + 45 = 0 ⇒ y2 – 9Y – 5y + 45 = 0 ⇒ y(y – 9) – 5(y – 9) = 0 ⇒ (y – 9)(y – 5) = 0 Then, y = + 9 or y = + 5 So, when x = - 24, x < y for y = + 9 and x < y for y = + 5 And when x = + 5, x < y for y = + 9 and x = y for y = + 5 ∴ So, we can observe that x ≤ y. |
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