1.

II. y2 – 14y + 45 = 01). x < y2). x > y3). x = y OR the relationship cannot be determined4). x ≥ y

Answer»

I. X2 + 19X120 = 0

⇒ x2 + 24x – 5x – 120 = 0

⇒ x(x + 24) – 5(x + 24) = 0

⇒ (x + 24)(x – 5) = 0

Then, x = - 24 or x = + 5

II. y2 – 14y + 45 = 0

⇒ y29Y – 5y + 45 = 0

⇒ y(y – 9) – 5(y – 9) = 0

⇒ (y – 9)(y – 5) = 0

Then, y = + 9 or y = + 5

So, when x = - 24, x < y for y = + 9 and x < y for y = + 5

And when x = + 5, x < y for y = + 9 and x = y for y = + 5

∴ So, we can observe that x ≤ y.


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