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II. y2 + 38y + 217 = 01). x < y2). x > y3). x = y OR the relationship cannot be determined4). x ≥ y |
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Answer» I. x2 – 15x – 154 = 0 ⇒ x2 – 22X + 7x – 154 = 0 ⇒ x(x – 22) + 7(x – 22) = 0 ⇒ (x – 22)(x + 7) = 0 Then, x = + 22 or x = - 7 II. y2 + 38Y + 217 = 0 ⇒ y2 + 31y + 7y + 217 = 0 ⇒ y(y + 31) + 7(y + 31) = 0 ⇒ (y + 31)(y + 7) = 0 Then, y = - 31 or y = - 7 So, when x = + 22, x > y for y = - 31 and x > y for y = - 7 And when x = - 7, x > y for y = - 31 and x = y for y = - 7 ∴ So, we can observe that x ≥ y. |
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