1.

II. y2 + 38y + 217 = 01). x < y2). x > y3). x = y OR the relationship cannot be determined4). x ≥ y

Answer»

I. x2 – 15x – 154 = 0

⇒ x222X + 7x – 154 = 0

⇒ x(x – 22) + 7(x – 22) = 0

⇒ (x – 22)(x + 7) = 0

Then, x = + 22 or x = - 7

II. y2 + 38Y + 217 = 0

⇒ y2 + 31y + 7y + 217 = 0

⇒ y(y + 31) + 7(y + 31) = 0

⇒ (y + 31)(y + 7) = 0

Then, y = - 31 or y = - 7

So, when x = + 22, x > y for y = - 31 and x > y for y = - 7

And when x = - 7, x > y for y = - 31 and x = y for y = - 7

∴ So, we can observe that x ≥ y.


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