In an examination 62% of the examinees got passed in Mathematics, 52%

1.	In an examination 62% of the examinees got passed in Mathematics, 52% passed in English and 22% failed in both the subjects. If 108 is the number of examinees who passed in both the subjects then find out the total number of candidates –1). 9002). 3003). 4004). 1000
Answer» Let the total number of students be X. Then, according to question: Number of students passed in Mathematics = 0.62X Number of students passed in ENGLISH = 0.52X Number of students passed in both Mathematics and English = 108 Number of students fail in both Mathematics and English = 0.22X We know that, Number of students passed + Number of students FAILED = Total number of students Now, number of students passed = 0.62X + 0.52X – 108 (Because 108 factor got COUNTED twice) ∴ 0.62X + 0.52X – 108 + 0.22X = X ⇒ 1.36X – 108 = X ⇒ X = 300

In an examination 62% of the examinees got passed in Mathematics, 52% passed in English and 22% failed in both the subjects. If 108 is the number of examinees who passed in both the subjects then find out the total number of candidates –1). 9002). 3003). 4004). 1000

Answer»

Let the total number of students be X.

Then, according to question:

Number of students passed in Mathematics = 0.62X

Number of students passed in ENGLISH = 0.52X

Number of students passed in both Mathematics and English = 108

Number of students fail in both Mathematics and English = 0.22X

We know that, Number of students passed + Number of students FAILED = Total number of students

Now, number of students passed = 0.62X + 0.52X – 108 (Because 108 factor got COUNTED twice)

∴ 0.62X + 0.52X – 108 + 0.22X = X

⇒ 1.36X – 108 = X

⇒ X = 300