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In the circuit shown below determine the total impedance.(a) 161(b) 162(c) 163(d) 164This question was addressed to me in homework.The question is from Series Circuits in portion Complex Impedence of Network Theory

Answer»

Correct option is (b) 162

The BEST explanation: Reactance across capacitor = 1/(6.28×50×10×10^-6) = 318.5Ω.

Reactance across inductor = 6.28×0.5×50=157Ω. In RECTANGULAR form, Z = (10+j157-j318.5) Ω = (10-j161.5)Ω. Magnitude=161.8Ω.



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