In the circuit shown below, find voltage across inductive reactance.(a) 9.5(b) 10(c) 9(d) 10.5I had been asked this question by my college director while I was bunking the class.This interesting question is from Series Circuits in section Complex Impedence of Network Theory

In the circuit shown below, find voltage across inductive reactance.(a

1.	In the circuit shown below, find voltage across inductive reactance.(a) 9.5(b) 10(c) 9(d) 10.5I had been asked this question by my college director while I was bunking the class.This interesting question is from Series Circuits in section Complex Impedence of Network Theory
Answer» Right OPTION is (a) 9.5 Explanation: Voltage ACROSS inductor = IXL. The values of I = 3.03 mA and XL = 10000Ω. On SUBSTITUTING the values in the EQUATION, the voltage across inductor = 3.03×10^-3×1000 = 9.51V.

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