K1 and K2 for oxalic acid are 6.5×10^-2and 6.1×10^-5respectively. What will be the [OH^–] in a 0.01M solution of sodium oxalate?(a) 9.6×10^-6(b) 1.4×10^-1(c) 1.2×10^-6(d) 1.3×10^-8I have been asked this question in an interview for internship.My query is from Ionization of Water, Weak acids and Weak Bases in section Water Basics of Biochemistry

K1 and K2 for oxalic acid are 6.5×10^-2and 6.1×10^-5respectively. Wh

1.	K1 and K2 for oxalic acid are 6.5×10^-2and 6.1×10^-5respectively. What will be the [OH^–] in a 0.01M solution of sodium oxalate?(a) 9.6×10^-6(b) 1.4×10^-1(c) 1.2×10^-6(d) 1.3×10^-8I have been asked this question in an interview for internship.My query is from Ionization of Water, Weak acids and Weak Bases in section Water Basics of Biochemistry
Answer» CORRECT OPTION is (C) 1.2×10^-6 To EXPLAIN: The hydrolysis of C2 O4^2- is as follows C2 O4^2-+ H2 O → HC2O^4- + OH^–

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