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The current i(t) in the circuit shown below is?(a) i(t)=(Vm/(R-jωL))e^tjω(b) i(t)=(Vm(R+jωL)) e^tjω(c) i(t)=(Vm(R-jωL)) e^tjω(d) i(t)=(Vm/(R+jωL)) e^tjωThe question was asked during an interview.This interesting question is from Impedence Diagram in chapter Complex Impedence of Network Theory

Answer» RIGHT CHOICE is (d) i(t)=(VM/(R+jωL)) e^tjω

To EXPLAIN: i(t)=IM e^tjω. Vm e^tjω=RIm e^tjω+Ld/dt (Im e^tjω). Vme^tjω=RIm e^tjω+L Im(jω)e^tjω. Im = Vm/(R+jωL). i(t)=(Vm/(R+jωL)) e^tjω.


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