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The impedance of the circuit shown below is?(a) R + jωC(b) R – jωC(c) R + 1/jωC(d) R – 1/jωCThis question was addressed to me in an interview.This question is from Impedence Diagram in portion Complex Impedence of Network Theory

Answer»

Right option is (C) R + 1/jωC

The best I can explain: The IMPEDANCE of the circuit SHOWN above is R + 1/jωC. Here the impedance Z consists RESISTANCE which is real part and capacitive reactance which is imaginary part of the impedance.



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