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The phase angle between current and voltage in the circuit shown below is?(a) tan^-1⁡ωL/R(b) tan^-1⁡ωR/(c) tan^-1⁡R/ωL(d) tan^-1⁡L/ωRThe question was asked during an online exam.The question is from Impedence Diagram topic in chapter Complex Impedence of Network Theory

Answer»

The correct ANSWER is (a) tan^-1⁡ωL/R

The best I can explain: The angle between impedance and REACTANCE is the phase angle between the CURRENT and voltage applied to the CIRCUIT. θ=tan^-1⁡ωL/R



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