The sum of ages of a father and son is 45 years. Five years ago, the p

1.	The sum of ages of a father and son is 45 years. Five years ago, the product of their ages was four times the father’s age at that time. The present age of the father is1). 39 years2). 36 years3). 25 years4). 40 years
Answer» LET the AGES of father and son be x and y The SUM of ages of a father and son is 45 years. ∴ x + y = 45----(1) Five years ago, the product of their ages was FOUR times the father’s age at that time. Five years ago their ages would be (x - 5) and (y - 5) ∴ (x - 5) (y - 5) = 4(x - 5) ⇒ y - 5 = 4 ⇒ y = 9 Put the value in equation (1) ⇒ x + 9 = 45 ⇒ x = 45 – 9 = 36 years ∴ The present age of father will be = 36 years

The sum of ages of a father and son is 45 years. Five years ago, the product of their ages was four times the father’s age at that time. The present age of the father is1). 39 years2). 36 years3). 25 years4). 40 years

Answer»

LET the AGES of father and son be x and y

The SUM of ages of a father and son is 45 years.

∴ x + y = 45----(1)

Five years ago, the product of their ages was FOUR times the father’s age at that time.

Five years ago their ages would be (x - 5) and (y - 5)

∴ (x - 5) (y - 5) = 4(x - 5)

⇒ y - 5 = 4

⇒ y = 9

Put the value in equation (1)

⇒ x + 9 = 45

⇒ x = 45 – 9 = 36 years

∴ The present age of father will be = 36 years