The sum of the ages of a Father and son is 38 years, Four years ago th

1.	The sum of the ages of a Father and son is 38 years, Four years ago the product of their ages was 3 times the father’s age at that time. The present age of the Father and son, respectively are1). 28 years, 10 years2). 32 years, 6 years3). 31 years, 7 years4). 34 years, 4 years
Answer» Let’s assume that present age of FATHER is X and age of son is Y ∴ Sum of their present ages = X + Y = 38 Four YEARS ago the age of Father was = X – 4 Four years ago the age of son was = Y – 4 ? Four years ago the product of their ages was 3 times the father’s age at that time ∴ (X – 4) × (Y – 4) = 3 (X – 4) ⇒ Y – 4 = 3 ⇒ Y = 7 ∴ present age of son is = 7 YRS & present age of Father is = 38 – 7 = 31 yrs

The sum of the ages of a Father and son is 38 years, Four years ago the product of their ages was 3 times the father’s age at that time. The present age of the Father and son, respectively are1). 28 years, 10 years2). 32 years, 6 years3). 31 years, 7 years4). 34 years, 4 years

Answer»

Let’s assume that present age of FATHER is X and age of son is Y

∴ Sum of their present ages = X + Y = 38

Four YEARS ago the age of Father was = X – 4

Four years ago the age of son was = Y – 4

? Four years ago the product of their ages was 3 times the father’s age at that time

∴ (X – 4) × (Y – 4) = 3 (X – 4)

⇒ Y – 4 = 3

⇒ Y = 7

∴ present age of son is = 7 YRS

& present age of Father is = 38 – 7 = 31 yrs