Using ruler and compass how will you construct ∆ABC, if AB=3.5, BC=6 and angle ABC=60^o?(a) Draw line BC=6 cm and an angle CBA=600. Cut off AB=3.5. Join AC, triangle ABC is the required triangle(b) Draw line BC=6 cm and AB= 3.5 and then angle ABC=60o, ABC is the required triangle(c) Draw line AB= 3.5cm and cut off AB = 6 cm at any point and make angle CBA=600(d) Draw angle CBA= 600 and makeI got this question in a job interview.This interesting question is from Loci of Points in chapter Lettering Practice, Scales & Curves of Civil Engineering Drawing

Using ruler and compass how will you construct ∆ABC, if AB=3.5, BC=6

1.	Using ruler and compass how will you construct ∆ABC, if AB=3.5, BC=6 and angle ABC=60^o?(a) Draw line BC=6 cm and an angle CBA=600. Cut off AB=3.5. Join AC, triangle ABC is the required triangle(b) Draw line BC=6 cm and AB= 3.5 and then angle ABC=60o, ABC is the required triangle(c) Draw line AB= 3.5cm and cut off AB = 6 cm at any point and make angle CBA=600(d) Draw angle CBA= 600 and makeI got this question in a job interview.This interesting question is from Loci of Points in chapter Lettering Practice, Scales & Curves of Civil Engineering Drawing
Answer» The correct choice is (a) Draw line BC=6 cm and an angle CBA=600. Cut off AB=3.5. Join AC, triangle ABC is the required triangle To EXPLAIN I WOULD say: FIGURE below SHOWS the construction:- Draw line BC=6 cm with a ruler and an angle CBA=600 with the compass. Cut off AB=3.5 by compass. Join AC, triangle ABC is the required triangle.

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