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With the arrival of a child, Silas transformed completely. He thought that his litter sister had come back to him. This child was quite like her. He was so shaken with this thought that he sank into his chair as memories from the past came rushing forward. All the suppressed memories came up and all the feelings he had tried to bury surfaced. And he felt quite placid about it. It was as if the little girl had brought with her all the hope, love, feeling and emotion that Silas had put away for many years. All that change happened instantly as he stared at the child. It was a forgiving look into the past and a hopeful look into the future. 

Nancy Lammeter, the daughter of a wealthy landowner is the pretty, caring, and stubborn young lady whom Godfrey pursues and then marries. Like Godfrey, Nancy comes from a family that is wealthy by Raveloe standards. Nancy has inherited the strict values of her father. However, the striking feature of Nancy Lammeter is her beauty, her height, her straight posture, and her moral code of ethics which she refused to detour from. There are several flaws in Nancy Lammeter’s character. She also believes in hard work and does not believe in showing off his wealth. However she does not want to associate the any man of poor reputation. She has feelings and emotions. She is dutiful, noble and loves her husband. She is understanding and defends her husband now and then. She leads a regulated life with dedication, devotion and faithfulness. Instead of leaving Godfrey upon knowing his treachery, she decides to remain with him. She is a dutiful and loyal wife. Because of these characteristics she is loved by all. 

• the protagonist of the novel

• simple, honest, and kind-hearted linen-weaver

• has mysterious looking enormous eyes, slightly bent back

• is wrongly accused of killing a town deacon and robbing the deacon's money.

• Having been hurt and betrayed by his faith in his religion, Silas leaves his hometown and settles in Raveloe.

• For fifteen years, he lives as a solitary miser.

• he is feared by the townspeople, as he has a reputation of being connected with the devil.

• Has knowledge of various medicinal herbs

• is isolated from the rest of the village, living at the edge of town, working as a weaver, and not attending church.

• Keeps himself busy working at his loom

• the money he earns from weaving fills him with happiness and satisfaction

• when his money is stolen, the villagers feel sorry for him.

• what changes his life is the child Eppie that he finds sitting in front of his fireplace. 

• Eppie brings him more happiness and joy than he ever received from the gold.

• his faith and trust are restored by his adopted daughter, Eppie

• At the end, the villagers agree that he brought a blessing to his life when he took Eppie in as his child.

• With Eppie in his life, Silas is able to unite his old faith with his new one, and believe that there is goodness and justice in this world.

• Chance and coincidence play an important role in the novel Silas Marner. They influence the action in this novel.

• Silas is proved guilty of the theft at Lantern Yard by a draw of lots

• Silas' gold is stolen by Dunstan by chance as Silas had left the door open

• Molly Farren's chance death leaves Godfrey free to marry Nancy and his secret remains unrevealed

• Eppie comes into Silas' life

• Discovery of Dunstan's skeleton and the bags of gold

Godfrey’s character is summed up by Eliot in the beginning of the novel as ‘irresolution and moral cowardice,’ a state in which he continues until almost the end. Godfrey is not evil in any way but he does not have the courage to take responsibility for his acts nor to give up his desires when they conflict with duty. His early marriage was not really his fault; he has good intentions about caring for Eppie; he really wants to lead a better life. There is no true test of his character except his failure to own Eppie as his daughter. This shows that Godfrey is unchanged—he wants to do the right things, but not badly I enough to risk his happiness. Godfrey at last comes to some self-realization. He takes the easy way out, deciding to own Eppie only in his will. But at least he does it from nobler motives—from consideration for others rather than for himself.

Griffin was a very intelligent scientist who put his heart and soul into achieving invisibility. Unfortunately, his passion warped into an obsession. Griffin was a student of medicine at the University College where he won a medal for excellence in chemistry. His keen interest in light drew him to physics. Fascinated by optical density, he moved to Chesilstowe after leaving London. He worked as a demonstrator in a provincial college while carrying out his research on making things invisible. He cut himself off from normal social life.

His depraved existence coaxed him to the extent of robbing his own father. Griffin grew short-tempered, intolerant and vindictive. 

Embittered by his pseudo success Griffin continued to fall morally. He made life miserable for the people of Iping. The absence of human sensitivity in Griffin became clear when he forced a vulnerable Marvel to be his accomplice. The brutal manner in which he killed Wick steed and chased Kemp to avenge treachery marked the eventual destruction of goodness in him.

The stranger remained locked in the parlour all morning. He sent for Mrs. Hall and asked her why his meals had not been sent to him. She told him that his bill had not been paid. He gave her some money, but she refused to accept it, saying that she first wanted to know why he didn’t enter by doorways and move about like normal people. For his answer, the stranger removed all his head wrappings, including his nose and moustache. He thus looked like a person with a missing head. At the sound of screams a crowd of people ran towards the inn. ‘Eye-witness’ suddenly babbled hysterical stories of the man attacking the servant girl, and brandishing a knife. Bobby Jaffers, the village constable, appeared with a warrant. The stranger slapped Jaffers with his glove but then said he would surrender. As they watched, the stranger removed the rest of his clothes, becoming invisible before them.

The town folk hoped that the spirit of greatness that accompanies the two families of Godfrey and Nancy will be perpetuated by joining their children in matrimony. The town people saw the way Godfrey and Nancy were together at the party, although at the same time they were not so intimate that their actions would be too obvious. They referred to this behavior as ‘sweet-hearting’. Basically, in traditional ‘townfolk talk’ the people are noticing both young persons want to get closer to each other. They see that they are getting closer physically and emotionally. The dynamics that could later turn into a full-fledged relationship are all there. Marriages and celebrations are big deals in traditional settings, so the blossoming of a relationship between the rich Nancy Lammeter and Godfrey, is always a topic of choice in a cohesive place such as Raveloe.

Mr. Marvel was a short, fat man. He gave the impression of a tramp – the shabby hat, the charity boots, his clothes and his homeless lifestyle. He was a lazy guy and did everything in a lazy manner. Griffin makes him his accomplice, even though he himself considered him stupid and good–for–nothing, as no one else was available to help him when he had been exposed. Marvel is basically a coward and is unable to stand up to Griffin. He becomes Griffin’s partner in crime but cheats him ultimately. He is an opportunist. At the first moment, he tries to sneak away but is caught. The second time, he succeeds and runs away with Griffin’s money and his three books. He gets himself arrested since he knew that the best way to save himself from Griffin was to remain in custody. Rather than giving away the books, he kept them for himself, hoping to solve its mystery someday. 

After the plan to get Griffin arrested failed, Dr. Kemp informed Colonel Adye that Griffin was mad. He further told him that Griffin must be stopped or he will next turn to killing people. Dr. Kemp used the knowledge given to him by Griffin against him. He wanted that every available man should be put to hunt. He wanted to stop Griffin from escaping. He knew that the only thing that could stop him from leaving the place was his three books. Dr. Kemp said that they must stop him from eating or sleeping and every single person should be on alert. Dr. Kemp further said that they should use dogs as they could smell him. Another important thing was that the food eaten by Griffin was visible until it had been absorbed. He also wanted powdered glass on the roads to trace Griffin's feet. But finally Dr. Kemp succeeds because of people's help. 

Marvel was a simple person, ill equipped in every sense, as compared to the all powerful invisible man. He had no choice but to obey each order coming from his maniacal master. Marvel was more of a slave than an accomplice in crime. When he succeeded in sneaking away, it was actually to save his life rather than cheat upon Griffin.

Of course, towards the end he showed smartness by hiding the entire money and the three books of Griffin. However, he exhibited his keen business acumen by wisely investing this money to open an inn. His decision to name this venture after the invisible man again showed that Marvel knew how to turn circumstances in his favour. He never revealed to anyone that the three books of Griffin were in his possession. He pondered over them in private trying to figure out the coded message. Thus Griffin’s loss proved to be Marvel’s gain.

4 times will the loop execute.

Refers to the below link

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Given: Area of parallelogram = 1470 cm²

Base (AB) = 35 cm and base (AD) = 49 cm

Since Area of parallelogram = base x height

⇒1470 = 35 x DL

⇒DL = 1470/35

⇒ DL = 42 cm

Again,

Area of parallelogram = base x height

⇒1470 = 49 x BM

⇒ BM = 1470/49

⇒ BM = 30 cm

Thus, the lengths of DL and BM are 42 cm and 30 cm respectively.

In right angles triangle BAC, AB = 5 cm and AC = 12 cm

Area of triangle =1/2 x base x height 

= 1/2x AB x AC

= 1/2 x 5 x 12 = 30 cm²

Now, in Δ ABC,

Area of triangle ABC =1/2 x BC x AD

⇒ 30 = 1/2 x 13 x AD

⇒ AD = (30 x 2)/13

= 60/13 cm

 In Δ ABC, AD = 6 cm and BC = 9 cm 

Area of triangle = 1/2 x base x height 

= 1/2 x BC x AD 

= 1/2  x 9 x 6 = 27 cm²  

Again, Area of triangle = 1/2 x base x height 

=1/2 x AB x CE 

⇒ 27 = 1/2 x 7.5 x CE 

⇒ CE = (27 x 2) / 7.5 

⇒ CE = 7.2 cm 

Thus, height from C to AB i.e., CE is 7.2 cm.

(i) The positively charged colloidal particles of Fe(OH)₃ get coagulated by the negatively charged ions provided by electrolyte.
(ii) The path of light becomes visible due to scattering of light by colloidal particles (Tyndall effect).
(iii) Electrophoresis takes place in which colloidal particles move towards the oppositely charged electrode where they lose their charge and get coagulated.

(i) Ethanol undergoes intermolecular hydrogen bonding due to the presence of a hydrogen attached to oxygen atom. As a result, ethanol exist as associated molecules and hence it has higher boiling point than methoxy ethane which does not form hydrogen bonds.
(ii) Phenol is stronger acid than ethanol because the phenoxide ion left after the release of proton is stabilized by resonance but ethoxide ion is not. Moreover, ethoxide ion is destabilised by +I effect of ethyl group.

(iii) Due to –I effect or –R effect of –NO₂ group, the resulting phenolate ion is more stable than phenoxide ion. Therefore o- and p--nitrophenols are more acidic than phenol

Electric field intensity is zero inside the hollow spherical charged conductor. So, no work is done in moving a test charge inside the conductor and on its surface. Therefore, there is no potential difference between any two points inside or on the surface of the conductor.

Here, RBCD = 5Ω + 10Ω = 15Ω
Effective resistance between B and E

1/R_BE = 1/30 + 1/10 + 1/15 => R_BE = 5Ω

Applying Kirchhoff’s Law
5 × 0.2 + R × 0.2 + 15 × 0.2 = 8 – 3​

=> R =5Ω
Hence
V_BE = IR_BE
= 0.2 × 5 = 1volt

ΔADE~ ΔGBD and ΔADE~ ΔFEC

⇒ΔGBD ~ ΔFEC (AA criterion)

⇒GD/FC = GB/FE 

⇒GD x FE 

= GB x FC  

or FG² = BG x FC

110, 120, 130, … , 990

a_n = 990 ⇒ 110 + (n − 1) × 10 = 990

∴ n = 89.

D = (2√2k)² -4(1)(18) = 0 ⇒ k = ±3.

b,c and 2b are in A.P ⇒ C = 3B/2

∴ b:c = 2 ∶ 3

= vector (a - b).[{vector(b - c) x (c - a)}]

= vector (a - b).[{vector(b x c - b x a - c x c + c x a)}]

= vector (a - b).[{vector(b x c - b x a + c x a)}] ......{(vector(c x c) = 0}

= vector (a - b).[{vector(b x c + a x b + c x a)}]

= vector [{a.(b x c)} + {a.(a x b)} + {a.(c x a)} - {b.(b x c)} - {b.(a x b)} - {b.(c x a)}]

= vector [{a.(b x c)} + 0 + 0 - 0 - 0 - {b.(c x a}]

= vector [{a.(b x c)} - {b.(c x a)}]

= 0

(STP remains same if vectors (a, b, c) are changed in cyclic order)

Length of Tangent = 2 × √(5² − 4²) = 2 × 3cm ܿ= 6 cm.

It is most well-known for the structural role it plays in the body. It is present in large quantities in connective tissue and provides tendons and ligaments with tensile strength and skin with elasticity. It often works in conjuction with other important proteins such as keratin and elastin.

Radioactive isotopes have many useful applications. In medicine, for example, cobalt-60 is extensively employed as a radiation source to arrest the development of cancer. Other radioactive isotopes are used as tracers for diagnostic purposes as well as in research on metabolic processes.

tan θ = \(\frac{3}{5}\)

Now,

\((\frac{5 sin θ \,-\, 3 cos θ}{4 sin θ \,+\, 3 cos θ})\)

= \((\frac{5 sin θ \,-\, 3}{4 sin θ \,+\, 3})\) [Dividing numerator and denominator by cosθ]

= \(\frac{3 - 3}{12 + 15}\over{5}\)

= 0

LHS = (1 + tan A – sec A) × (1 + tan A + sec A)

(x – y) (x + y) = x² – y² 

here x = 1 + tan A 

y = sec A 

LHS = (1 + tan A)² – (sec A)²

= 1 + tan² A + 2 tan A – sec² A 

= sec² A + 2 tan A – sec² A (1 + tan² A = sec² A) 

= 2 tan A = RHS

Hence, proved.

S = {(1,1), (1,2), (1,3), (1,4), (1,5), (1,6), (2,1), (2,2), (2,3), (2,4), (2,5), (2,6), (3,1), (3,2), (3,3), (3,4), (3,5), (3,6), (4,1), (4,2), (4,3), (4,4), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6),}

n(S) = 36

Let Event A : At least one of the two is greater than 4.

A = { (1,5), (1,6), (2,5), (2,6), (3,5), (3,6), (4,5), (4,6), (5,1), (5,2), (5,3), (5,4), (5,5), (5,6), (6,1), (6,2), (6,3), (6,4), (6,5), (6,6)}

n (A) = 20

P(A) = n(A)/n(S) = 20/36 = 5/9

P(A) = 5/9

Negation: “ There exists a real number x such that x is not less than x+1.”

The surface area of sphere = 616cm²

Since, the surface area of sphere = 4πr²

Therefore,

\(4\pi r^2 = 616\)

\(4\times\frac{22}{7}\times r^2= 616\)

\(r^2=616\times\frac74\times\frac1{22}\)

r² = 49

r = 7 cm

∴ Required radius, r = 7cm

It was a dark night. As usual, I was studying in my room. It was severe cold out side so I was comfortable in my quilt and busy in studies. Suddenly, the door opened slowly. First, I did not pay any attention towards it but, then, there was a loud knock at the door. The light outside was dim so nothing was visible clearly. There was a repeated knocking at the gate. I was trying to find out what this strange sound was because it became louder and louder. Then, the curtain began to move side to side but I was quite helpless to see anything or any person. My heart began to beat fast. I wanted to go there to find out the reality but my fear did not allow me even to move. I wanted to cry but could not do so as my throat was blocked. My mother was trying to wake me up. In fact, I saw a horror movie yesterday. I realised that it was a dream. Even on getting up I was sweating bitterly and my family members laughing. After some time, I also began to laugh.

Climate change is a real and serious issue. We need to act promptly to mitigate its effects.

1. Phasing out fossil fuels by switching to low - carbon- energy sources, such as renewable and nuclear energy.

2. Expanding forests and other "sinks" to remove greater amounts of carbon dioxide from the atmosphere.

(a) from 

(b) Hence 

(c) disposal 

(d) therefore 

(e) be happy 

(f) to receive 

(g) a 

(h) with

(a) all 

(b) from 

(c) scheduled 

(d) has been cancelled 

(e) to 

(f) convenient 

(g) looking 

(h) eager

(a) about 

(b) caused 

(c) among 

(d) readily  

(e) at 

(f) attracts 

(g) it 

(h) up

• The precipitation reaction undergoes in aqueous solutions or medium in an ionic state. 
• The reaction takes place between ions present in the aqueous solutions, forming the product 
• The products formed at the end of precipitation reaction are the precipitates which are insoluble in aqueous solutions 
• Precipitation reactions are known as ionic reactions since the ions actively take part in the reaction and form the product. 
• These reactions depend on the temperature, concentration of the solution, buffer solution, etc.

SO₂,NO₂ gases are released into the atmosphere from various sources. These dissolve in rain water to give acid which corrodes marble statues    

2SO₂ + O₂ → 2SO₃    

H₂O + SO₃ → H₂SO₄ 

2NO₂ + H₂O → 2HNO₃ 

CaCO₃ + H₂SO₄ → CaSO₄ + H₂O + CO₂    

CaCO₃ + 2HNO₃ → Ca(NO₃)₂ + H₂O + CO₂

Pauli exclusion principle- According to this principle, “No two electrons in an atom can have the same set of four quantum numbers.”

Half life period : It is the time required in which half of the reactant gets converted into product.

(i)

Fuel cell: The cells in which combustion energy of fuel directly get converted into electrical energy (also getting converted in any other form of energy viz. thermal energy, mechanical energy etc.) are known as fuel cell example – H₂-O₂ fuel cell, CH₄-O₂ fuel cell, NH₂NH₂-O₂ fuel cell etc.
Reaction involving in H₂-O₂ fuel cell:
At anode – 2H₂(g) + 4OH^– (aq) → 4H₂O(l) + 4e^–
At cathode – O₂(g) + 2H₂O(l) + 4e^– → 4OH^– (aq)
Overall reaction – 2H₂(g) + O₂(g) → 2H₂O (l)

Primary cell: The cell in which reaction occurs only once to give energy and hence cannot be reversed and recharged.
Cell reaction during discharging.
Anode: Zn(s) → Zn²⁺ + 2e^–
Cathode: (MnO₂ + NH⁺₄ + e^– → MnO (OH) + NH₃) × 2
Overall reaction
Zn(s) + 2 MnO₂ + 2 NH⁺₄ → Zn²⁺ + 2MnO(OH) + 2NH₃.

1. NO^–₂ < NO₂ < NO⁺₂
2. NH₃ < H₂O < HF
3. CO₂ < NO₂ < SO₂

In the static situation, vector E has to ensure that the free charges on the surface do not experience any force.