InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 1. |
A charge is distributed along an infinite curved line in space with linear charge distribution λ. What will be the amount of force on a point charge q kept at a certain distance from the line?(a) q∫\(\frac {\lambda}{r^2}\hat{r}\)dl(b) q∫\(\frac {\lambda}{r^2}\hat{r}\)dr(c) q∫\(\frac {\lambda}{r^3}\hat{r}\)dl(d) q∫\(\frac {\lambda}{r^2}\)I have been asked this question in an internship interview.Query is from Continuous Charge Distribution topic in section Charges and Fields of Physics – Class 12 |
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Answer» Correct CHOICE is (a) q∫\(\frac {\lambda}{r^2}\hat{r}\)dl |
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| 2. |
What is the dimension of the dipole moment?(a) [L T I](b) [L T I^2](c) [M L T I](d) [L T I^-1]This question was posed to me in an online interview.The doubt is from Electric Dipole topic in section Charges and Fields of Physics – Class 12 |
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Answer» Right option is (a) [L T I] |
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| 3. |
Which among the following molecule is not a dipole?(a) NH3(b) H2O(c) HCl(d) CH4The question was posed to me during a job interview.This key question is from Electric Dipole in chapter Charges and Fields of Physics – Class 12 |
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Answer» Right answer is (d) CH4 |
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| 4. |
The direction of electric field created by a negative charge is ___________(a) Directed outwards(b) Directed towards the charge(c) Maybe outwards or towards the charge(d) Circular in shapeI have been asked this question in exam.This question is from Electric Field in section Charges and Fields of Physics – Class 12 |
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Answer» Correct choice is (b) DIRECTED towards the CHARGE |
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| 5. |
An electric field E is present perpendicular to a square plate of side length L. What is the flux passing through the plate?(a) LE(b) L^2E(c) \(\frac {L^2}{E}\)(d) ZeroThe question was posed to me by my college professor while I was bunking the class.The query is from Gauss’s Law in section Charges and Fields of Physics – Class 12 |
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Answer» RIGHT option is (b) L^2E Best explanation: We KNOW that electric flux is equal to the product of the electric field and the surface AREA of a surface. In this CASE, the plate has surface area L*L = L^2 and hence the net flux passing through the surface is = L^2E. |
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| 6. |
Let B be the midpoint of AC. Two point charges Q are placed at A and C. What should be the value of charge placed at B so that the system remains at equilibrium?(a) –Q/2(b) –Q/4(c) +Q/2(d) +Q/4I have been asked this question in my homework.My question comes from Coulomb’s Law in section Charges and Fields of Physics – Class 12 |
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Answer» RIGHT option is (b) –Q/4 For EXPLANATION I would say: Whatever the value of q be, it will undergo equal force on both sides, hence q will be steady. Now, for stability of Q, NET force on Q must be ZERO. \(\FRAC {1}{4\pi\epsilon_o} \, \frac {Q^2}{d^2} + \frac {1}{4\pi\epsilon_o} \, \frac {Q.q}{(\frac {d}{2})^2}\) = 0 ⇒ \(\frac {Q^2}{d^2} = \frac {-Q q}{\frac {d^2}{4}}\) ⇒ Q = -49 ⇒ q = –\(\frac {Q}{4}\) |
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| 7. |
Electric field due to a uniformly charged hollow sphere at a distance of r (where r is greater than the radius of the sphere) is __________(a) Proportional to r(b) Inversely proportional to r(c) Proportional to r^2(d) Inversely proportional to r^2The question was asked in an interview for job.My question is based upon Electric Field in division Charges and Fields of Physics – Class 12 |
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Answer» Correct option is (d) INVERSELY proportional to r^2 |
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| 8. |
What is the dimension of volume charge density?(a) [MLAT^-2](b) [M^0 L^-3 A T](c) [M L^-3 A T](d) [M L^-2 A T]I had been asked this question in an online quiz.This is a very interesting question from Basic Properties of Electric Charge in section Charges and Fields of Physics – Class 12 |
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Answer» Correct OPTION is (B) [M^0 L^-3 A T] |
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| 9. |
An electric field \(3\hat{j} + 4\hat{k}\) N/C is present at a place. What will be the electric flux passing through a square plate if the plate is placed in the y-z plane?(a) 7 Nm^2C^-1(b) 25 Nm^2C^-1(c) Zero(d) 17 Nm^2C^-1I have been asked this question by my college director while I was bunking the class.This intriguing question comes from Gauss’s Law topic in chapter Charges and Fields of Physics – Class 12 |
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Answer» The correct answer is (c) Zero |
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| 10. |
Net inward and outward flux of a closed surface are φ1 and φ2. What is the charge enclosed inside the surface?(a) Zero(b) -(∅1-∅2)εo(c) (∅1-∅2)εo(d) \(\frac {(\emptyset_1 + \emptyset_2)}{\varepsilon_o}\)This question was addressed to me during an internship interview.This is a very interesting question from Gauss’s Law in division Charges and Fields of Physics – Class 12 |
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Answer» Correct option is (b) -(∅1-∅2)εo |
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| 11. |
What is the dimension of electric flux?(a) [M L^3 T^-3 I^-1](b) [M L^2 T^-3 I^-1](c) [M L^3 T^-3 I^1](d) [M L^3 T^3 I^-1]This question was posed to me by my college director while I was bunking the class.The doubt is from Electric Flux topic in division Charges and Fields of Physics – Class 12 |
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Answer» RIGHT option is (a) [M L^3 T^-3 I^-1] The best I can EXPLAIN: Electric flux=electric FIELD intensity* area. The dimension of field intensity is [M L T^-3 I^-1] and the dimension of the area is [L^2]. Therefore, the dimension of flux = [M L^3 T^-3 I^-1]. This can ALSO be justified that flux=potential*length. By PUTTING the dimensions of potential and length, we can get the same result. |
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| 12. |
A ball of 80mg mass and a 2*10^-8 charge is hung with a thread in a uniform horizontal electric field of 2*10^4V/m. What is the angle made by the thread with vertical?(a) 27 degree(b) 30 degree(c) 45 degree(d) 0 degreeThis question was posed to me in semester exam.This intriguing question originated from Electric Field topic in section Charges and Fields of Physics – Class 12 |
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Answer» CORRECT answer is (a) 27 degree To elaborate: ACCORDING to the diagram, Tsinθ = Eq; Tcosθ = mg. Where T is the TENSION in the thread, m is the mass of the ball, E is the electric field and q is the charge of the ball. Dividing these two, we get tanθ = \(\frac {Eq}{mg}\). Now substituting the value of E=2*10^4V/m, m=80mg, q=2*10^-8C, g=9.8m/s^2, we get tanθ = \(\frac {25}{49}\). Therefore θ=27 degree. |
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| 13. |
Two point charges of the same polarities are hung with the help of two threads and kept close. The angle between the threads will be _________ if the system is taken to space.(a) 180 degree(b) 90 degree(c) 45 degree(d) 60 degreeThis question was posed to me during a job interview.My question is from Electric Field topic in section Charges and Fields of Physics – Class 12 |
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Answer» Correct ANSWER is (a) 180 degree |
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| 14. |
According to Coulomb’s Law force between two charges is k*q1*\(\frac {q_2}{r^2}\). What will happen if one of the charges is zero?(a) No attraction or repulsion(b) Always attraction(c) Always repulsion(d) Cannot predict the nature of the forceI got this question in an interview for job.I want to ask this question from Coulomb’s Law topic in division Charges and Fields of Physics – Class 12 |
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Answer» RIGHT answer is (b) Always ATTRACTION The best I can explain: Though it seems from the formula that the force must be zero, an OPPOSITE CHARGE is induced on the uncharged body and then the TWO opposite charges will attract each other. This also proves that induction occurs before attraction. |
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| 15. |
Which among the following cannot be the charge of a charged body?(a) 4.8*10^-14 Coulomb(b) 6.4*10^-15 Coulomb(c) 5*10^-14 Coulomb(d) 3.2*10^-10 CoulombI got this question during a job interview.Asked question is from Electric Charges in division Charges and Fields of Physics – Class 12 |
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Answer» Correct answer is (C) 5*10^-14 Coulomb |
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| 16. |
Electric flux coming out of a single Na^+ ion is _________ Nm^2C^-1(a) 1.8*10^-8(b) 1.8*10^-10(c) 5.4*10^-8(d) 3.6*10^-8I had been asked this question in final exam.Asked question is from Application of Gauss’s Law in chapter Charges and Fields of Physics – Class 12 |
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Answer» Right ANSWER is (a) 1.8*10^-8 |
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| 17. |
The term ‘volume charge density’ is valid for a solid conducting sphere.(a) True(b) FalseThe question was posed to me in examination.I want to ask this question from Continuous Charge Distribution topic in chapter Charges and Fields of Physics – Class 12 |
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Answer» The correct answer is (b) False |
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| 18. |
1uC and -1uC are placed at a distance of 5 cm forming a dipole. What is the amount of torque required to place the dipole perpendicularly to an electric field of 3*10^5 N/C?(a) 5*10^-3 N. m(b) 15*10^-3 N. m(c) 1*10^-3 N. m(d) 10*10^-3 N. mThis question was addressed to me during an online exam.My question is based upon Dipole in a Uniform External Field topic in portion Charges and Fields of Physics – Class 12 |
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Answer» The CORRECT choice is (b) 15*10^-3 N. m |
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| 19. |
If an electric dipole is placed in a uniform electric field ______ will act on the dipole.(a) A force but no torque(b) Both force and torque(c) Torque but no force(d) No torque or forceI have been asked this question in an online quiz.My question is from Dipole in a Uniform External Field topic in chapter Charges and Fields of Physics – Class 12 |
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Answer» Correct option is (c) Torque but no force |
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| 20. |
It is observed that N number of field lines come out perpendicularly from the unit surface area of the sphere. What is the amount of charge inside the sphere? ∈ is the dielectric constant of the medium.(a) -4πR^2 N∈(b) 4πR^2 N∈(c) \(\frac {4\pi R^2}{N\epsilon}\)(d) –\(\frac {4\pi R^2N}{\epsilon}\)I had been asked this question by my college professor while I was bunking the class.My question comes from Electric Field Lines in portion Charges and Fields of Physics – Class 12 |
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Answer» The correct ANSWER is (b) 4πR^2 N∈ |
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| 21. |
Which one of the following is similar between electrostatic force and gravitational force?(a) Force can be attractive or repulsive(b) The force depends on the medium between the bodies(c) Both the forces are strong forces(d) Force is inversely proportional to the distance between the bodiesThis question was posed to me in an interview for internship.This intriguing question originated from Coulomb’s Law in division Charges and Fields of Physics – Class 12 |
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Answer» The correct option is (d) Force is inversely proportional to the distance between the bodies |
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| 22. |
1 Coulomb = ________ Electro Static Unit.(a) 3*10^9(b) 3*10^8(c) 1.602*10^-19(d) 2*10^9The question was asked during an interview.The question is from Electric Charges in portion Charges and Fields of Physics – Class 12 |
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Answer» CORRECT OPTION is (a) 3*10^9 The explanation is: 1 Coulomb means3*10^9 Electro Static Unit of CHARGE. Coulomb and ESU are two different units of charge and their conversion FORMULA is necessary. Coulomb is the unit of charge in the SI system and esu is the unit of charge in the CGS system. |
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| 23. |
Flux coming out from a balloon of radius 10 cm is 1.0*10^3 N.m^2.C-1^-1. If the radius of the balloon is doubled, the flux coming out from the balloon will be _______(a) 0.5 times(b) 2 times(c) Same(d) 4 timesThe question was posed to me during an internship interview.This interesting question is from Electric Flux in division Charges and Fields of Physics – Class 12 |
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Answer» Right OPTION is (c) Same |
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| 24. |
If the force acting on a point charge kept on the axis of an electric dipole is F, what will be the amount of force if the distance of the point charge is doubled from the dipole?(a) 2F(b) \(\frac {F}{8}\)(c) \(\frac {F}{2}\)(d) \(\frac {F}{4}\)I had been asked this question in quiz.My question is from Electric Dipole in section Charges and Fields of Physics – Class 12 |
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Answer» RIGHT option is (b) \(\frac {F}{8}\) Easiest explanation: If the distance of a point CHARGE, kept on the axis of a dipole, is sufficiently large than the SEPARATION between the charges of a dipole, then it can be shown that electric field E at a distance r from the dipole varies as E α \(\frac {1}{r^3}\). Now if the distance becomes 2R, electric field intensity will decrease by a factor of 2^3=8 times. Therefore the force F will now become \(\frac {F}{8}\). |
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| 25. |
If a charge is placed outside a closed surface, flux due to that charge inside the surface will be ________(a) Positive(b) May be positive or negative, depending on the nature of the charge(c) Negative(d) ZeroThis question was addressed to me during a job interview.The query is from Electric Flux in chapter Charges and Fields of Physics – Class 12 |
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Answer» The correct OPTION is (d) Zero |
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| 26. |
An electric charge q is placed at one of the corner points of a cube of side a. What will be the net outwards flux coming out of the cube due to the point charge?(a) \(\frac {q}{\varepsilon_o}\)(b) \(\frac {q}{2\varepsilon_o}\)(c) \(\frac {q}{4\varepsilon_o}\)(d) \(\frac {q}{8\varepsilon_o}\)The question was asked by my school principal while I was bunking the class.This key question is from Gauss’s Law topic in portion Charges and Fields of Physics – Class 12 |
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Answer» The correct CHOICE is (d) \(\frac {q}{8\varepsilon_o}\) |
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| 27. |
A non-conducting sphere has uniform charge density in it. The electric field at a point inside the sphere will be _______(a) Zero(b) Only due to the charge inside that point(c) Only due to the charge outside that point(d) Due to the entire charge of the sphereThis question was addressed to me in examination.My question is based upon Gauss’s Law in chapter Charges and Fields of Physics – Class 12 |
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Answer» Correct answer is (b) Only due to the charge INSIDE that point |
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| 28. |
How many electrons must be added to an isolated spherical conductor of radius 20cm to produce an electric field 1000N/C just outside the surface?(a) 2.77*10^20(b) 2.77*10^10(c) 1.77*10^10(d) 5.4*10^10I have been asked this question at a job interview.I'd like to ask this question from Continuous Charge Distribution topic in portion Charges and Fields of Physics – Class 12 |
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Answer» Correct choice is (b) 2.77*10^10 |
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| 29. |
If a non-polar substance is placed in an electric field, what will happen?(a) A net dipole moment will be observed(b) The substance will oscillate(c) The substance will orient itself perpendicular to the electric field(d) It will conduct electricityI got this question by my college professor while I was bunking the class.The query is from Dipole in a Uniform External Field in division Charges and Fields of Physics – Class 12 |
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Answer» Right CHOICE is (a) A net DIPOLE moment will be observed |
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| 30. |
If electric field intensity at a certain distance from a dipole on its axis is E1 and at the same distance but on the perpendicular bisector of the dipole is E2, then __________(a) E1=E2(b) E1=2 E2(c) E1=4 E2(d) E1=3 E2The question was posed to me in a national level competition.Enquiry is from Electric Dipole in chapter Charges and Fields of Physics – Class 12 |
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Answer» Correct CHOICE is (b) E1=2 E2 |
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| 31. |
Electric field inside a hollow conducting sphere ______(a) Increases with distance from the center of the sphere(b) Decreases with distance from the center of the sphere(c) Is zero(d) May increase or decrease with distance from the centerThis question was posed to me in a national level competition.My query is from Electric Field topic in chapter Charges and Fields of Physics – Class 12 |
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Answer» The correct choice is (C) Is zero |
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| 32. |
Which among the following is false?(a) Coulomb force is a central force(b) The force between two charges depend on the medium between them(c) Coulomb force is a weak force(d) The net force on a charge is the vector sum of the forces acting on it due to several other chargesThis question was addressed to me during an online exam.This key question is from Forces Between Multiple Charges in division Charges and Fields of Physics – Class 12 |
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Answer» Right choice is (c) Coulomb force is a weak force |
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| 33. |
Coulomb’s Law is valid for ______(a) Only point charge(b) For both point charge and distributed charge(c) Only distributed charges(d) Neither distributed nor point chargeThis question was addressed to me in my homework.My question is taken from Coulomb’s Law in division Charges and Fields of Physics – Class 12 |
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Answer» RIGHT option is (a) Only point charge Best explanation: COULOMB’s Law explains the force between TWO point charges only. A distributed charge can be considered as the sum of INFINITE point charges and thus the force between two distributed charge systems can be explained. |
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| 34. |
What is the C.G.S. unit of charge?(a) Stat Coulomb(b) Coulomb(c) EMU(d) PascalI got this question during an interview for a job.I would like to ask this question from Coulomb’s Law in chapter Charges and Fields of Physics – Class 12 |
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Answer» Correct choice is (a) Stat COULOMB |
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| 35. |
An electron of mass m is kept in a vertical electric field of magnitude E. What must be the value of E so that the electron doesn’t fall due to gravity?(a) m*g*e(b) \(\frac {e}{(m*g)}\)(c) \(\frac {(m*g)}{e}\)(d) \(\frac {1}{(m*g*e)}\)This question was addressed to me in quiz.The above asked question is from Electric Field in chapter Charges and Fields of Physics – Class 12 |
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Answer» The CORRECT OPTION is (c) \(\frac {(m*g)}{e}\) |
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| 36. |
The amount of force exerted on a unit positive charge in an electric field is known as _____(a) Electric field intensity(b) Electric flux(c) Electric potential(d) Electric lines of forceI had been asked this question during an online interview.The above asked question is from Electric Field in chapter Charges and Fields of Physics – Class 12 |
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Answer» The correct choice is (a) Electric field intensity |
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| 37. |
Find the electric field intensity at 10cm away from a point charge of 100 esu.(a) 1 dyne/esu(b) 10 dyne/esu(c) 100 dyne/esu(d) 9*10^9 dyne/esuThe question was asked in examination.This interesting question is from Electric Field in section Charges and Fields of Physics – Class 12 |
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Answer» The CORRECT option is (a) 1 dyne/esu |
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| 38. |
Current carrier in conductors is ____(a) Electron(b) Proton(c) Neutron(d) PositronThis question was addressed to me during an interview for a job.This intriguing question comes from Conductors and Insulators topic in chapter Charges and Fields of Physics – Class 12 |
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Answer» Correct option is (a) Electron |
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| 39. |
A lightning arrester must have the following property.(a) Discontinuity(b) Poor conductivity(c) Needle end(d) Low melting pointI had been asked this question at a job interview.I need to ask this question from Basic Properties of Electric Charge topic in section Charges and Fields of Physics – Class 12 |
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Answer» Correct choice is (c) NEEDLE END |
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| 40. |
A circular annulus of inner radius r and outer radius R has a uniform charge density a. What will be the total charge on the annulus?(a) a*(R^2-r^2)(b) π*a*(R^2-r^2)(c) a*(R-r)(d) π*a* R^2This question was addressed to me in final exam.My question comes from Continuous Charge Distribution topic in chapter Charges and Fields of Physics – Class 12 |
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Answer» Right answer is (B) π*a*(R^2-r^2) |
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| 41. |
The CO2 molecule is a dipole. The statement is ______(a) True(b) FalseThis question was posed to me in an internship interview.Question is from Electric Dipole in section Charges and Fields of Physics – Class 12 |
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Answer» The correct answer is (a) True |
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| 42. |
Three equal positive charges are kept at the corners of an equilateral triangle. What will be the vector sum of the forces acting on the particles?(a) Directed towards the center(b) Directed radially outside(c) Acts along one of the sides of the triangle(d) ZeroThe question was posed to me in unit test.Query is from Forces Between Multiple Charges topic in division Charges and Fields of Physics – Class 12 |
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Answer» Correct choice is (d) ZERO |
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| 43. |
1 dyne/esu = _____ N/C(a) 3*10^4(b) 10^5(c) 3*10^5(d) 9*10^4This question was posed to me in an online interview.This key question is from Electric Field Lines in section Charges and Fields of Physics – Class 12 |
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Answer» RIGHT OPTION is (a) 3*10^4 Best explanation: 1 N/C = \(\frac {1 N}{1 C} = \frac {10^5 dyne}{3*10^9 esu} = \frac {1}{3*10^4}\)dyne/esu. Therefore 1 dyne/esu=3*10^4 N/C. Both of them are the UNIT of electric field INTENSITY. But N/C is the unit of electric field intensity in the SI system while dyne/esu is the unit of field intensity in the CGS system. |
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| 44. |
A 1C charge is placed at the origin. Other infinite numbers of unit charges are placed at √2, √4, √8, √16,….(up to infinite) distances from the origin in a straight line. What will be the total force acting on the 1^st charge?(a) 9*10^9 N(b) 18*10^9 N(c) Infinite(d) 1 NThe question was posed to me in unit test.The origin of the question is Forces Between Multiple Charges topic in chapter Charges and Fields of Physics – Class 12 |
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Answer» Right choice is (a) 9*10^9 N |
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| 45. |
An electric dipole will be in stable equilibrium if the angle between the axis of the dipole and the electric field is ________(a) 0 degree(b) 180 degree(c) 90 degree(d) 45 degreeThis question was posed to me in my homework.Origin of the question is Dipole in a Uniform External Field topic in section Charges and Fields of Physics – Class 12 |
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Answer» The correct choice is (a) 0 degree |
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| 46. |
The band gap between the valence band and conduction band is the measure of ______(a) The conductivity of the material(b) The resistivity of the material(c) Charge density(d) Ease of ionizationI had been asked this question in my homework.My question is based upon Conductors and Insulators topic in section Charges and Fields of Physics – Class 12 |
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Answer» Right choice is (a) The conductivity of the material |
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| 47. |
If a 10C charge is placed in a medium having relative permittivity 5.4, what will be the amount of flux coming out of that charge?(a) 1*10^11 Nm^2C^-1(b) 2.1*10^11 Nm^2C^-1(c) 2.1*10^10 Nm^2C^-1(d) 7.1*10^11 Nm^2C^-1I had been asked this question during an interview for a job.I need to ask this question from Application of Gauss’s Law in section Charges and Fields of Physics – Class 12 |
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Answer» CORRECT answer is (B) 2.1*10^11 Nm^2C^-1 The explanation: GAUSS’s Law states that electric flux coming out of a charge is=\(\frac {AMOUNT \, of \, charge}{permittivity \, of \, the \, medium}\). In this case, the charge is 1C and permittivity of the medium=5.4*8.85*10^-12. Substituting the values, we get the total flux coming out of the charge is 2.1*10^11 Nm^2C^-1. |
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| 48. |
In the CGS system, \(\frac {1}{\varepsilon_o}\) is replaced by _______ if k is the dielectric constant of the medium.(a) \(\frac {4\pi}{k}\)(b) \(\frac {2\pi}{k}\)(c) \(\frac {1}{k}\)(d) 1This question was posed to me in my homework.This question is from Gauss’s Law topic in division Charges and Fields of Physics – Class 12 |
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Answer» The correct choice is (a) \(\frac {4\pi}{k}\) |
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| 49. |
A dipole is placed in an electric field such that the axis of the dipole is parallel to the electric field. The torque acting on the dipole will be the maximum in this case. The statement is _____(a) True(b) FalseI got this question in an online quiz.I want to ask this question from Dipole in a Uniform External Field topic in division Charges and Fields of Physics – Class 12 |
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Answer» Right answer is (b) False |
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| 50. |
Flux linked to a surface is said to be positive if the flux lines are coming out of the surface. The statement is ______(a) True(b) FalseThe question was asked in unit test.Asked question is from Electric Flux in section Charges and Fields of Physics – Class 12 |
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Answer» CORRECT answer is (a) True The best I can explain: Depending on the DIRECTION of ELECTRIC flux lines i.e. electric field intensity, we can differentiate between POSITIVE and negative flux. If the flux lines are going inside a surface, the flux is SAID to be negative. But if the flux lines are coming out of the surface, the flux is said to be positive. |
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