Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

Which of the following has maximum mass ? (i) 0.1 mole of KNO_(3) (ii) 1 xx 10^(23) molecules of CH_(4) (iii) 112 cm^(3) of hydrogen at S.T.P ?

Answer»


Solution :(i) Formula mass of `KNO_(3)=1 xx 39 + 1 xx 14 + 3 xx 16 = 101`
1 mole of `KNO_(3)=101 g`
0.1 mole of `KNO_(3)=(("0.1 MOL"))/(("1.0 mol"))xx(101g)=10.1g`
(ii) `6.022 xx 10^(23)` molecules of `CH_(4)=16 g`
`1 xx 10^(23)` molecules of `CH_(4)=((1xx10^(23)"molecules"))/((6.022xx10^(23)"molecules"))xx(16g)=2.657g`
(iii) `22400 cm^(3)` of `H_(2)` at S.T.P = 2g
`112 cm^(3)` of `H_(2)` at S.T.P `= (("112 cm"^(3)))/(("22400 cm"^(3)))xx2g=0.01g`
Thus, 0.1 mole of `KNO_(3)` has MAXIMUM mass.
Discussion
2.

Which of the following reactions can be used to prepare methane?

Answer»

Decarboxylation of sodium acetate
KOLBE's electrolysis
WURTZ REACTION
Hydrogenation of ALKENES

ANSWER :A
Discussion
3.

The solubility product constant of Ag_2CrO_4 and AgBr are 1.1xx10^(-12) and 5.0xx10^(-13) respectively. Calculate the ratio of the molarities of their saturated solutions.

Answer»

Solution :`{:(Ag_2CrO_(4(s))HARR, 2Ag_((aq))^(+)+, CrO_(4(aq))^(2-)),(S_1M,2S_1M +, S_1M):}`
`therefore K_(SP)=[Ag^+]^2 [CrO_4^(2-)]=(2S_1)^2 (S_1)=(4S_1)^3`
`therefore S_1=(K_(sp)/4)^(1/3) =root3(1.1/4 xx10^(-12))=0.6503xx10^(-4)` M
`{:(AgBr_((s))hArr, Ag_((aq))^(+)+ , Br_((aq))^(-)),(S_2M,S_2M,S_2M):}`
`K_(sp)=[Ag^+][Br^-]=(S_2)(S_2)=(S_2)^2`
`therefore S_2=SQRT(K_(sp))=sqrt(5.0xx10^(-13))=sqrt(50xx10^(-14))`
`=7.0711xx10^(-7)` M
RATIO of solubilities = `S_1/S_2=(0.6503xx10^(-4))/(7.0711xx10^(-7))`
`=0.091966xx10^(+3)M`
=91.966
Discussion
4.

The reducing property of alkali metals Na, K, Rb, Cs, Li follows the order________

Answer»

SOLUTION :NA LTK ltRb LTCS LTLI
Discussion
5.

The total numebr of electrons present in 18 mL of water density=1gmL^(-1) is

Answer»

`6.02 xx 10^(23)`
`6.02 xx 10^(23)`
`6.02 xx 10^(24)`
`6.02 xx 10^(25)`

Solution :C) 18 mL `H_(2)O` = 18g of `H_(2)O` = 1MOL
`=6.02 xx 10^(23)` molecules
`= 10 xx 6.02 xx 10^(23)` electrons
`6.02 xx 10^(24)` electrons
Discussion
6.

Write Lewis dot symbol for Br.

Answer»

SOLUTION :`[:UNDERSET(..)OVERSET(..)BR:]^(-)`
Discussion
7.

Toluene is o/p orienting with respect to an electrophilic substitution reactiondue to

Answer»

I effect of the methyl group
I as well as +m effect of the methyl group
hyperconjugation between the methyl group and the PHENYL RING
`+m` effect of the methyl group .

Answer :C
Discussion
8.

The solubility of Al(OH)_3 is S mol L^(-1) then what will be the K_(sp) ?

Answer»

108 `S^4`
27 `S^4`
27 `S^3`
`S^2`

ANSWER :B
Discussion
9.

Which of the following is a crystalline form of silica ?

Answer»

Jaspar
Crystobalite
Agate
Onyx

Answer :B
Discussion
10.

Which of the following reactions are disproportionation reactions ? (I)Cu^(+)toCu^(2+)+Cu (II)3MnO_4^(-)+4H^(+)to2MnO_4^(-)+MnO_2+2H_2O (III) 2KMnO_4 to K_2MnO_4+MnO_2+O_2 (IV)2MnO_4^(-)+3Mn^(2+)+2H_2Oto5MnO_2+4H^(+)

Answer»

(a), (C) and (d)
(a) and (d) only
(a) and (B) only
(d) (a), (b) and (c).

ANSWER :C
Discussion
11.

What is K_c for the following equilibrium when the equilibrium concentration of each substance is : [SO_2]=0.60 M, [O_2]= 0.82M and [SO_3] = 1.90 M ? 2SO_(2(g)) + O_(2(g)) hArr 2SO_(3(g))

Answer»

Solution :`{:("EQUILIBRIUM reaction:", 2SO_(2(g)) +,O_(2(g)) hArr , 2SO_(3(g))),("Concentration at equili. (M)",0.6, 0.82 , 1.90):}`
Equilibrium CONSTANT of reaction is `K_c` ,
`K_c=[SO_3]^2/([SO_2]^2[O_2])=(1.90M)^2/((0.6M)^2(0.82M))`
`= 12.229 M^(-1)`
`= 12.229 "L mol"^(-1)`
Discussion
12.

You are given the followingspecies :PH_(3), P_(2)H_(6)^(2+), P_(2) H_(5)^(+) and PH_(4)^(+)Which of these has least covalent P-H character and why ?

Answer»

Solution :GREATER the FORMAL charge distribution on each P-H BOND, less is the covalent character.
Formal charge distribution=`(" Total charge")/("Number of P-H bonds")`
THUS , the values for formal charge distribution will be
` PH_(3) = (0)/(3) = 0 ,P_(2) H_(6)^(2+) = (2)/(6) = 0.33, P_(2)H_(5)^(+) = (1)/(5) = 0.2, PH_(4)^(+) = (1)/(4) = 0 . 25`
As ` P_(2) H_(6)^(2+)`has highest formal charge distribution, it will have least covalent character.
Discussion
13.

What is the basic theme of organisation in the periodic table ?

Answer»

Solution :The basic theme of organisation of elements ir the PERIODIC table is to simplify and SYSTEMATIZE the study of the numerous properties of all the elements and their compounds.
The has been done by arranging the elements in such a way that similar elements are placed together while DISSIMILAR elements are separated from one another. This has MADE the study simple to remember because the properties of the elements are now studied in the form of GROUPS or families having similar properties other than studying the elements individually.
Discussion
14.

Which of the following element has second highest order in terms of its abundance in earth crust ?

Answer»

Carbon
Germenium
Silicon
Aluminium

ANSWER :C
Discussion
15.

Which of the following grouping represents a collection of iso-electionic species?

Answer»

`Ca^(2+),CS^(2+),Br`
`NA^(+),Ca^(2+),Mg^(2+)`
`N^(3-),F^(-),Na^(+)`
`Be,AL^(3+),Cl^(+)`

Answer :C
Discussion
16.

Which of the following has structure similar to graphite

Answer»

BN
B
`B_(4)C`
`B_(4)H_(6)`

SOLUTION :BN is a cubic & hexagonal structureit contains B-N-B and N-B-N bonds with `109^(@)C`bond angle
Discussion
17.

What is the effect of catalyst on K?

Answer»


ANSWER : K REMAINS UNAFFECTED
Discussion
18.

Which of the following is used to remove toxic and heavy metals from water?

Answer»

zeolites
magnesia
Bleaching agent
lime

ANSWER :a
Discussion
19.

Which is a covalent compound?

Answer»

RbF
`MgCl_(2)`
`CaC_(2)`
`NH_(3)`

ANSWER :D
Discussion
20.

X-rays

Answer»

are DEFLECTED in a MAGNETIC field
are deflected in an ELECTRIC field
remain undeflected by both the field
are deflected in both the field.

Answer :C
Discussion
21.

Which orbital's are equivalent in homonuclear molecule?

Answer»

`sigma_(1S) and sigma_(2s)`
`pi_(2PX) and pi_(2py)`
`pi_(2px) and sigma_(2pz)`
`sigma_(2px) and sigma_(2pz)^(**)`

Solution :`pi_(2px) and pi_(2py)`
Order of energy in molecular orbital :
`sigma_(1s) lt sigma_(1s)^(**) lt sigma_(2s) lt sigma_(2s)^(**) lt sigma_(2p_(Z)) lt pi_(2p_(x)) = pi_(2p_(y))lt sigma_(2pz) lt pi_(2p_(x))^(**) = pi_(2p_(y))^(**) lt sigma_(2p_(z))^(**)`
Discussion
22.

Which one of the following statements is not true ?

Answer»

Dissolved oxygen (DO) in cold water can reach a concentration up to 10 ppm.
Clean water would have a BOD value of 5 ppm.
Fluoride DEFICIENCY in drinking water is HARMFUL . Soluble fluoride is often used to bring its concentration UPTO 1 ppm.
When the pH of rain water is higher than 6. It is called acid rain.

Answer :D
Discussion
23.

What is pH of rain water ?

Answer»

` 5 . 6 `
` 4 . 6 `
`6 . 5`
`7 . 5 `
Discussion
24.

What is the ninth ionization potential of fluorine atom ?

Answer»

13.6 EV
`9xx13.6 eV`
`81xx13.6 eV`
`100xx13.6 Ev`

SOLUTION :I.E. `=+ (Z^2)/(n^2) `(13.6eV) /ATOM
Discussion
25.

Write the IUPAC name of the compound

Answer»

Solution :The given compound is a non-cyclic HYDROCARBON. It is an alkadiene.
The numbering is given, as shows, to include both the double BONDS, ethyl and methyl groups.

The IUPAC NAME is 3-Ethyl-4-methylpenta-1,3 - diene
Discussion
26.

Which one of the following is the isobaric process ?

Answer»

`DELTA H =0`
`Delta E =0`
`Delta P =0`
`Delta Q =0`

ANSWER :C
Discussion
27.

The state of a gas can be described by quoting the relationship between...........

Answer»

<P>pressure, volume, temperature
temperature, amount, pressure
amount, volume, temperature
pressure, volume, temperature, amount

Solution :`PV = nRT` Thus, p, V,T and n (amount) describe the STATE of the SYSTEM.
Discussion
28.

Which of the following will increase the BOD of water supply ?

Answer»

`CO_(2)`
`O_(3)`
`H_(2)O`
`C_(2)H_(5)OH`

ANSWER :D
Discussion
29.

What is the mass of hydrogen peroxide present in 1 litre of a 2M solution? Calculate the volume of oxygen a N.T.P. liberated upon the complelte decomposition of 100mL of the solution.

Answer»

Solution :STEP-I CALCULATION of mass of `H_(2)O_(2)`
According to available data:
Molarity=`2M("or 2 mol"L^(-1))`, Molecular mass of `H_(2)O_(2)`=34g/mol, VOLUME of solution=1L
`"Molarity"=("Mass of"H_(2)O_(2))/(("Molecular mass of")` `H_(2)O_(2))/("Volume of solution oin litres")),("2mol"L^(-1))=("Mass of"H_(2)O_(2))/("34gmol"^(-1)xx(1L))`
OrMass of `H_(2)O_(2)=(2mol L^(-1)xx(34gmol^(-))xx(1L)=68g`
STEP-II Calculation of volume of oxygen liberated at N.T.P.
Now, 1000ML of the solution CONTAINS `H_(2)O_(2)=68g`
100mL of the solution contains `H_(2)O_(2)`=6.8g
Now, according to the DECOMPOSITION equation, `68.0g "of" H_(2)O_(2) "`at N.T.P. evolve oxygen"`=22400mL`
`68.0g "of" H_(2)O_(2) "at N.T.P. evolve oxygen"=(22400)/(68.0)xx6.8=22400or 2.24L`
Discussion
30.

When silicon is boiled with caustic soda solution, the gas evolved is

Answer»

`O_(2)`
`SiH_(4)`
`H_(2)`
Both 1& 2

Answer :C
Discussion
31.

The type of overlap present in the bonds of hydrogen sulphide molecule is

Answer»

`SIGMA s-p`
`sigma s-s`
`sigmap-p`
`sigmasp^(3)-s`

ANSWER :A
Discussion
32.

Which ofthe following crystals does not exhibit Frenkel defect ?

Answer»

AgBr
AgCl
KBR
ZnS

Solution :KBr EXHIBITS SCHOTTKY DEFECT and not FRENKEL defect.
Discussion
33.

Which equation from the following is right ?

Answer»

`Delta U = q-w`
`w=Delta U +q`
`Delta U = w+q`
none of above

Answer :C
Discussion
34.

Which one of the following is not an allotrope of carbon?

Answer»

GRAPHITE 
DIAMOND 
CARBORUNDUM 
Coke

Answer :C
Discussion
35.

Write the resonance structures of crotonal-dehyle and indicate the stability order.

Answer»

SOLUTION :
The order of stability is `I GT II gt III`
Discussion
36.

Which among the following statements are true with respect to electronic displacement in a covalent bond? I) Inductive effect operates through a pi-bond II) Resonance effect operates through a sigma-bond III) Inductive effect operates through a sigma-bond IV) Resonance effect operates through a pi-bond V) Resonance and inductive effects operate through a sigma- bond

Answer»

I and II
I and III
II and III
III and IV

Solution :Inductive EFFECT operates through a o-BOND Resonance effect opearates through a `pi`-bond
Discussion
37.

Which one of the following is less soluble in water?

Answer»

LiCI
NaCl
KCI
CsI

ANSWER :A
Discussion
38.

The viscosity of an ideal gas is independent of pressure at constant temperature As the pressure is increased the effect of the increase in number density of molecules in compensated by a proportionate decrease in the mean free path .

Answer»

SOLUTION :EXPLANTION is CORRECT REASON for STATEMENT
Discussion
39.

Which among the following elements of groups-2 exhibits anomalous properties ?

Answer»

Be
Mg
Ca
Ba

ANSWER :A
Discussion
40.

What sorts of informations you can draw from the following reaction ? (CN)_(2)(g) + 2OH^(-) (aq) to CN^(-) (aq) + CNO^(-) (aq) + H_(2)O(1)

Answer»

SOLUTION :It is a disproportionation REACTION in which `(CN)_(2)` is SIMULTANEOUSLY reduced to `CN^(-)` ION and oxidised to `CNO^(-)` ion The reaction is taking place in basic medium.
Discussion
41.

What is wrong about transition metals?

Answer»

They are diamagnetic
They are PARAMAGNETIC
They FORM complexes
They SHOW variable OXIDATION state

Answer :A
Discussion
42.

Two mole of an ideal gas is expanded irreversibly and isothermally at 37^(@)C until its volume is doubled and 3.41 kJ heat is absorbed from surroundings. Delta S_("total") (system + surroundings) is

Answer»

`-0.52` J/K
0.52 J/K
22.52 J/K
0

Solution :`Delta S_("total") = Delta S + Delta S_("SURR")`
`=(N C_(V) = "LN" (T_(2))/(T_(1)) + nR "ln"(V_(2))/(V_(1))) + ((-Q)/(T))`
`=(2 xx 8.314 xx ln 2) + ((-3.41)/(310)) = 0.52J//K`
Discussion
43.

Why is the highest oxidation state of a metal exhibited in its oxide or fluoride only ?

Answer»

1
4
6
9

Answer :D
Discussion
44.

Which of the following compounds give precipitate with sulphide solution?

Answer»

`BaCI_(2)`
`KI_(3)`
Silver nitrate
`CD(OAC)_(2)`

ANSWER :B::C::D
Discussion
45.

Two voltameters containing copper sulphate and acidulated water respectively are connected in series and the same current is passed for some time. If the amounts of copper and hydrogen obtained at cathode are 0.3177 g and 1.008 xx 10^(-2) g respectively, calculate the of copper. (Eq. mass of hydrogen = 1.008).

Answer»


ANSWER :31.77
Discussion
46.

What is Irreversible Reactions ? Give examples.

Answer»

Solution :A REACTION which cannot take place in the REVERSE DIRECTION and amount of reactions complete converted into product is known as IRREVERSIBLE reaction. It is express by (`to` ).
Reactants `to` products
Example: `NaOH_((AQ))+HCl_((aq)) to NaCl_((aq))+H_2O_((l))`
Or `OH_((aq))^(+) + H_((aq))^(+) to H_2O_((l))`
Example : `AgNO_(3(aq)) + HCl_((aq)) to AgCl_((s)) + KNO_(3(aq))`
Or `Ag_((aq))^(+) + Cl_((aq))^(-) to AgCl_((s))`
Discussion
47.

Which of the following alcohols is the most acidic

Answer»




SOLUTION :Among GIVEN `OVERSET(NO_2)overset(|)CH_2-OH`is more ACIDIC than others due to more I effect
Discussion
48.

Write resonance structures of CH_(2)= CH-CHO. Indicate relative stability of the contributing structures

Answer»

Solution :The structures `CH_(2) = CH - overset(overset(O)(||))(C )-H` in which two alternate DOUBLE bond and one heteroatom ..O.. present and its three resonance structures are as under:

Stability : `(I) gt (II) gt (III)`
(I) Is the most STABLE, more number of COVALENT bond,each carbon and oxygen atom has an octet and no separation of opposite charge.
(II) There is negative charge on more electronegative atom and positive charge on more ELECTROPOSITIVE atom. Hence it is medium stable.
(III) It does not contribute of oxygen has positive charge and carbon has negative charge hence least stable (A) and (B) in resoance `(I) harr (II)`.
Discussion
49.

What are all the conditions for optical isomerism?

Answer»

Solution :i.A carbon ATOM whose tetravalency in SATISFIED by four different substituents (Atoms (or) GROUPS) is called asymmetric carbon (or) chiral cabon. The optical isomer should have one or more chiral carbon to show optical activity.
II. The molecules possessing chiral carbon atom and is non-superimposable its own mirror image is said to be chiral molecule and the PROPERTY is called chirality or dissymmetry.
Discussion
50.

What is the ratio between the energies of two types of radiation whose wavelengths are 6000 Å and 2000 Å respectively.

Answer»

Solution : `lambda_(1)=6000Å=6xx10^(-7)m`
`lambda_(2)=2000Å=2XX10^(-7)m`
`(E_(1))/(E_(2))=(hc)/(6xx10^(-7))XX(2xx10^(-7))/(hc)=(1)/(3)`
`therefore E_(1):E_(2)=1:3 or E_(2)=3E_(1)`
Discussion