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90801.

A chloride of fourth group cation in qualitative analysis gives a green coloured complex [A] in aqueous solution which when treated with ethane-1, 2-diamine (en) gives pale-yellow solution [B] which on subsequent addition of ethane-1, 2-diamine turns to blue/purple [C] and finally to violet [D]. Write the structures of complexes [A], [B], [C] and [D].

Answer»

SOLUTION :The FORMATION of COMPLEXES is EXPLAINED as under :
90802.

A chloride of fourth group cation in qualitative analysis gives a green coloured complex [A] in acqueous solution which when treated with ethane-1, 2-diamine (en) gives pale yellow solution [B] which on subsequent addition of ethane-1, 2-diamine turns to blue/purple [C] and finally to violet [D]. Write the structures of complexes [A], [B], [C], and [D]

Answer»

Solution :In fourth GROUP of qualitative analysis CONTAINING `Ni^(2+), Co^(2+), Zn^(2+)` and `MN^(2+)`, the green coloured complex in aqueous solution is FORMED only by `Ni^(2+)`, i.e., A = `[Ni(H_(2)O)_(6)]^(2+)`
`[Niunderset(("A"))((H_(2)O)_(6))]^(2+)+enrarr[Niunderset(("B"))((H_(2)O)_(4))en]^(2+)overset(+en)rarr[Niunderset(("C"))((H_(2)O)_(2))(en)_(2)]^(2+)overset(+en)rarr[Niunderset(("D"))((en)_(3))]^(2+)`
90803.

A chloride of an element contains 49.5% chlorine. The specific heat of the element is 0.056. calcualte the equivalent mass, valency and atomic mass of the element.

Answer»

Solution :Mass of chlorine in the metal chloride =49.5%
Mass of meta `=(100-49.5)=50.5`
EQUIVALENT mass of the metal `=("Mass of metal")/("Mass of chlorine")xx35.5
`=(50.5)/(49.5)xx35.5=36.21`
ACCORDING to Dulong and PETIT's law.
Approximate ATOMIC mass of the metal `=(6.4)/("specific heat")`
`=(6.4)/(0.056)=114.3`
`"velency"=("Approximate atomic mass")/("Equivalent mass")=(114.3)/(36.21)=3.1=3`
HENCE, exact atomic mass `=36.21xx3=108.63`.
90804.

A chloride dissolves appreciably in cold water when placed on a platinum wire in bunsen flame, no distinctive colour is noted, which cation could be present

Answer»

`MG^(2+)`
`Ba^(2+)`
`Pb^(2+)`
`Ca^(2+)`

ANSWER :C
90805.

A chloride dissolves appreciably in cold water when placed on the tip of platinum wire and heated in the bunsen flame, no distinctive colour is obtained. Which cation could be present ?

Answer»

`Be^(2+)`
`BA^(2+)`
`SR^(2+)`
`CA^(2+)`

ANSWER :A
90806.

A chiria compound'X' hasmolecularformula C_(4)H_(6)O_(3) . Itevolves CO_(2)with aq. NaHCO_(3)'X' reactswith LiAIH_(4)to givean achiral product. Thestrcuture of 'X' is .

Answer»

`H_(3)C- UNDERSET(CH_(2)OH)underset(|)(CH)-COOH`
`H_(3) C - underset(OH) underset(|)(CH) - COOH`
`H_(2)CH_(3) - underset(OH)underset(|)(CH) - COOH`
`H_(3)C - underset(OME)underset(|)(CH)- COOH`

ANSWER :A
90807.

(A) Chloral reacts with phenyl chloride to form DDT (R) It is an electrophilic substitution reaction.

Answer»

Both (A) and (R) are correct and (R) is the correct EXPLANATION of (A) 
Both (A) and (R) are correct but (R) is not the correct explanation of (A) 
(A) is TRUE but (R) is False 
Both (A) and (R) are false 

ANSWER :A
90808.

A : Chloral reacts with phenyl chloride to form DDT.R : It is an electrophilic subtitution reaction.

Answer»

Assertion and reason both are CORRECT and reason is correct explanation of assertion.
Assertion and reason both are WRONG statements.
Assertion is correct but reason is wrong statement.
Assertion is wrong but reason is correct statement.

Solution :When chlorobenzene is heated with chloral in the presence of conc. `H_(2)SO_(4)` a powerful INSECTICIDE, DDT is FORMED with the elimination of water molecule.
90809.

A chiralC_7H_(16)O_2 diol is oxidized by PCC in CH_2Cl_2 to an achiral C_7H_(12)O_2compound. Which of the following would satisfy these facts?

Answer»




ANSWER :B
90810.

A chiral carbon is_____.

Answer»


ANSWER :OPTICALLY In ACTIVE
90811.

A chiral C_(5)H_(10)O alcohol is reduced by catalytic hydrogenation to an achiral C_(5)H_(12)O alcohol. The original alcohol is oxidized by activated MnO_(2) to an achiral carbonyl compound (C_(5)H_(8)O) Which of the following might be the chiral alcohol ?

Answer»

1- peten-3-ol
4- peten-2-ol
3-methyl-2-buten-1-ol
2-methyl-2-buten-1-ol

Answer :A
90812.

A child is diagnosed with bleeding gums, is likely to have the deficiency of which vitamin?

Answer»

SOLUTION :VITAMIN C
90813.

A chiral C_(7)H_(16)O_(2) diol is oxidized by PCC in CH_(2)Cl_(2) to an achiral C_(7)H_(12)O_(2) compound. Which of the following would satisfy these facts ?

Answer»




ANSWER :B
90814.

A chemistry student trying to detect the metallic ion in a salt, makes a paste on a clean platinum wire loop of the salt with concentrated with HCl. When he takes a small amount of this paste and keeps it in a non-luminous Bunsen flame,t he colour of the flame changes to grassy green. he should, therefore, conclude that the metal is

Answer»

Barium
Calsium
Potassium
Strontium

Solution :Ba' GIVES CHARACTERISTIC GREEN flame in BUNSEN burner.
90815.

A chemist wants to prepare diborane by the reaction "" 6 LiH + 8BF_(4)to 6LiBF_(4) + B_(2)H_(6) If he starts with 2.0 moles each of Lih & BF_(3) .How many moles of B_(2)H_(6) can be prepared.

Answer»


ANSWER :`0.25` MOLE
90816.

A chemist opened a cupboard to find four bottles containing water solutions, each of which has lost its label. Bottles 1,2,3 contained colourless solutions,Whilst bottle 4 contained a blue solution. The labels from the bottles were lying scattered ont he floor of the cupboard. They were copper (II) sulphate sodium carbonate lead nitrate hydrochloric acid By mixing sammples of teh contents of the bottles, in pairs, the chemist made the following observations: (i) Bottle 1 + Bottle 2white precipitate (ii) Bottle 1 + bottle 3white precipitate (iii) Bottle 1 + Bottle 4white precipitate (iv) Bottle 2 +Bottle 3colourless gas evolved (v) Bottle 2+ Bottle 4no visible reaction (vi) bottle 3 +bottle 4blue precipitate Q. Chemical formula of white ppt. formed in observation (iii) is:

Answer»

`PbCl_(2)`
`PbCO_(3)`
`CuCO_(3)`
`PbSO_(4)`

SOLUTION :`Pb(NO_(3))_(2)+CuSO_(4) to Cu(NO_(3))_(2)+underste("white ppt.")(PbSO_(4)DARR)`
90817.

A chemist opened a cupboard to find four bottles containing water solutions, each of which has lost its label. Bottles 1,2,3 contained colourless solutions,Whilst bottle 4 contained a blue solution. The labels from the bottles were lying scattered ont he floor of the cupboard. They were copper (II) sulphate sodium carbonate lead nitrate hydrochloric acid By mixing sammples of teh contents of the bottles, in pairs, the chemist made the following observations: (i) Bottle 1 + Bottle 2white precipitate (ii) Bottle 1 + bottle 3white precipitate (iii) Bottle 1 + Bottle 4white precipitate (iv) Bottle 2 +Bottle 3colourless gas evolved (v) Bottle 2+ Bottle 4no visible reaction (vi) bottle 3 +bottle 4blue precipitate Q. Nature of gas evolved in observation (iv) is:

Answer»

Acidic
Neutral
Basic
Amphoteric

Solution :`Na_(2)CO_(3)+2HCL to 2NaCl+underset("Acidic CHARACTER")(CO_(2)uarr)+H_(2)O`
90818.

A chemist opened a cupboard to find four bottles containing water solutions, each of which has lost its label. Bottles 1,2,3 contained colourless solutions,Whilst bottle 4 contained a blue solution. The labels from the bottles were lying scattered ont he floor of the cupboard. They were copper (II) sulphate sodium carbonate lead nitrate hydrochloric acid By mixing sammples of teh contents of the bottles, in pairs, the chemist made the following observations: (i) Bottle 1 + Bottle 2white precipitate (ii) Bottle 1 + bottle 3white precipitate (iii) Bottle 1 + Bottle 4white precipitate (iv) Bottle 2 +Bottle 3colourless gas evolved (v) Bottle 2+ Bottle 4no visible reaction (vi) bottle 3 +bottle 4blue precipitate Q. Colourless solution present in bottle-1 is:

Answer»

`CuSO_(4)`
`HCL`
`Pb(NO_(3))_(2)`
`Na_(2)CO_(3)`

Solution :`Pb(NO_(3))_(2) to `COMPLETELY soluble in water.
90819.

A chemist opened a cupboard and found four bottles containing water solutions, each of which had lost its label.Bottles 1,2,3 contanied colourless solution, while bottle 4 contained a blue solution.The labels from the bottles were lying scattered on the floor of the cupboard.They were: copper (II) sulphate, Hydrochloric acid lead nitrate , Sodium carbonate By mixing samples of the contents of the bottles, in pairs , the chemist made the following observations : Bottle 1 +Bottle 2 to White precipitate is formed. Bottle 1 +Bottle 3 to White precipitate is formed. Bottle 1 +Bottle 4 to White precipitate is formed. Bottle 2 +Bottle 3 to Colourless and odourless gas is evolved. Bottle 2 +Bottle 4 to No visible reaction is observed. Bottle 3 +Bottle 4 to Blue precipitate is formed. With the help of the above observations answer the following questions. Which of the following statements is correct for salts contained in bottle 1 and 4 ?

Answer»

Bottle 4 gives white PRECIPITATE with EXCESS of KI solution
Bottle 4 gives white precipitate with excess of `K_4 [Fe (CN)_6]` solution
Bottle 1 and 4 both gives precipitate with excess of NaOH solution
Bottle 1 gives white precipitate with concentrated HCl solution

Solution :(A)`2Cu^(2+)+4I^(-)toCu_2I_2 darr ("white")+I_2`
(B)`2Cu^(2+)+[Fe(CN)_6]^(4-)toCu_2[Fe(CN)_6]darr` (chocolate brown)
(C )`Pb^(2+)+4OH^(-)to[Pb(OH)_4]^(2-)`(colourless soluble complex) , `Cu^(2+)+2OH^(-)TOCU(OH)_2darr`(blue)
(D)`Pb^(2+)+4Cl^(-)to[PbCl_4]^(2-)darr` (colourless soluble complex)
90820.

A chemist opened a cupboard and found four bottles containing water solutions, each of which had lost its label.Bottles 1,2,3 contanied colourless solution, while bottle 4 contained a blue solution.The labels from the bottles were lying scattered on the floor of the cupboard.They were: copper (II) sulphate, Hydrochloric acid lead nitrate , Sodium carbonate By mixing samples of the contents of the bottles, in pairs , the chemist made the following observations : Bottle 1 +Bottle 2 to White precipitate is formed. Bottle 1 +Bottle 3 to White precipitate is formed. Bottle 1 +Bottle 4 to White precipitate is formed. Bottle 2 +Bottle 3 to Colourless and odourless gas is evolved. Bottle 2 +Bottle 4 to No visible reaction is observed. Bottle 3 +Bottle 4 to Blue precipitate is formed. With the help of the above observations answer the following questions. Which of the following bottles will give white precipitate with bottle 1?

Answer»

Bottle 2
Bottle 3
Bottle 4
All of these

Solution :`Pb^(2+)+CO_3^(2-) to PbCO_3 DARR` (WHITE)
`Pb^(2+)+2Cl^(-)toPbCl_2darr`(white)
`Pb^(2+)+SO_4^(2-)toPbSO_4 darr`(white)
90821.

A chemist opened a cupboard and found four bottles containing water solutions, each of which had lost its label.Bottles 1,2,3 contanied colourless solution, while bottle 4 contained a blue solution.The labels from the bottles were lying scattered on the floor of the cupboard.They were: copper (II) sulphate, Hydrochloric acid lead nitrate , Sodium carbonate By mixing samples of the contents of the bottles, in pairs , the chemist made the following observations : Bottle 1 +Bottle 2 to White precipitate is formed. Bottle 1 +Bottle 3 to White precipitate is formed. Bottle 1 +Bottle 4 to White precipitate is formed. Bottle 2 +Bottle 3 to Colourless and odourless gas is evolved. Bottle 2 +Bottle 4 to No visible reaction is observed. Bottle 3 +Bottle 4 to Blue precipitate is formed. With the help of the above observations answer the following questions. Which one of the following bottles develops deep blue with aqueous ammonia ?

Answer»

Bottle 1
Bottle 2
Bottle 3
Bottle 4

Solution :Bottle 4 is `CuSO_4` and that GIVE deep BLUE colouration with excess of ammonia solution.
`Cu^(2+)(AQ)+4NH_3(aq)to[Cu(NH_3)_4]^(2+)` (intensive deep blue colour)(aq)
90822.

A chemist opened a cupboard to find four bottles containing water solutions, each of which has lost its label. Bottles 1,2,3 contained colourless solutions,Whilst bottle 4 contained a blue solution. The labels from the bottles were lying scattered ont he floor of the cupboard. They were copper (II) sulphate sodium carbonate lead nitrate hydrochloric acid By mixing sammples of teh contents of the bottles, in pairs, the chemist made the following observations: (i) Bottle 1 + Bottle 2white precipitate (ii) Bottle 1 + bottle 3white precipitate (iii) Bottle 1 + Bottle 4white precipitate (iv) Bottle 2 +Bottle 3colourless gas evolved (v) Bottle 2+ Bottle 4no visible reaction (vi) bottle 3 +bottle 4blue precipitate Q. Chemical formula of white precipitate in observation (i) is:

Answer»

`CuCl_(2)`
`PbCl_(2)`
`PbCO_(3)`
`CuSO_(3)`

SOLUTION :`Pb(NO_(3))_(2)+2HCl to underset("WHITE")(PbCl_(2))darr+2HNO_(3)`
90823.

A chemist opened a cupboard and found four bottles containing water solutions, each of which had lost its label.Bottles 1,2,3 contanied colourless solution, while bottle 4 contained a blue solution.The labels from the bottles were lying scattered on the floor of the cupboard.They were: copper (II) sulphate, Hydrochloric acid lead nitrate , Sodium carbonate By mixing samples of the contents of the bottles, in pairs , the chemist made the following observations : Bottle 1 +Bottle 2 to White precipitate is formed. Bottle 1 +Bottle 3 to White precipitate is formed. Bottle 1 +Bottle 4 to White precipitate is formed. Bottle 2 +Bottle 3 to Colourless and odourless gas is evolved. Bottle 2 +Bottle 4 to No visible reaction is observed. Bottle 3 +Bottle 4 to Blue precipitate is formed. With the help of the above observations answer the following questions. Bottle 3 contains :

Answer»

COPPER (II) sulphate
Hydrochloric acid
Lead nitrate
Sodium carbonate

Solution :As bottle 2+ bottle 3 gives colourless and odourless gas, it may be carbon dioxide. Generally CARBONATES are decomposed by acids giving `CO_2` gas.It suggests that bottle 2 and 3 contains sodium carbonate and HCl. Bottle 3+4 gives blue precipitate which confirms the `Cu^(2+)` in either of bottles, `CuSO_4 , CuCl_2 and Cu(NO_3)_2`are soluble and `CuCO_3` is insoluble in water as evident from the reaction.
`Cu^(2+)+CO_3^(2-)toCuCO_3 DARR` (blue).Thus blue precipitate MUST be of copper carbonate.
Hence, bottle 4 is `CuSO_4` , 3 is `Na_2CO_3`, 2 is HCl (from above ) and 1 is `Pb(NO_3)_2` as it gives WHITE precipitate of `PbCl_2` with bottle (2).
90824.

A chemist isolated a compound A with molecular formula C_(7)H_(13) Br. A undergoes very fast S_(N)1 reaction. Spectroscopic evidence indicatedthat compound A has the following structural characteristics. . It contains fnive sp_(3) hybridised carbon atoms. Among those five SP^(3 ) carbon atoms are three methyl groups, one CH_(2)groupand one CH group. . It also contains two SP_(2)-hybridised carbonatoms . Alsothere is onlyone hydrogen atom attched to sp^(2)carbons. . The compound contains a total of six allylic hydrogen atoms. . The carbon atom that holds the Br has one H attached to it. When compound A reacts with boiling water , it undergoes an S_(N)1 reaction and produces. two principal products B and C . Both B andC are alcohols with their molecular formula C_(7)H_(14)O. Among the two alcohols, B has the --OH group attached to an sP_(3) carbon atom that has no H atoms bonded to it . If the starting compound A is brominated in gas phase in presence of a Lewis acidcatalys, a tribromide would result from addition of Br_(2) to C=C . How many different structures of stereo isomers isomers canbe drawn for this tribromide ?

Answer»

2
4
8
NONE of these

Answer :B
90825.

A chemist isolated a compound A with molecular formula C_(7)H_(13) Br. A undergoes very fast S_(N)1 reaction. Spectroscopic evidence indicatedthat compound A has the following structural characteristics. . It contains fnive sp_(3) hybridised carbon atoms. Among those five SP^(3 ) carbon atoms are three methyl groups, one CH_(2)groupand one CH group. . It also contains two SP_(2)-hybridised carbonatoms . Alsothere is onlyone hydrogen atom attched to sp^(2)carbons. . The compound contains a total of six allylic hydrogen atoms. . The carbon atom that holds the Br has one H attached to it. When compound A reacts with boiling water , it undergoes an S_(N)1 reaction and produces. two principal products B and C . Both B andC are alcohols with their molecular formula C_(7)H_(14)O. Among the two alcohols, B has the --OH group attached to an sP_(3) carbon atom that has no H atoms bonded to it . If the original compound A is treated with "LiAlH"_(4) , anew compound D (C_(7)H_(14)) would be produced.How many differentstructure (s) can be drawn for this D ?

Answer»

One
Two
Three
Four

Answer :A
90826.

A chemist isolated a compound A with molecular formula C_(7)H_(13) Br. A undergoes very fast S_(N)1 reaction. Spectroscopic evidence indicatedthat compound A has the following structural characteristics. . It contains fnive sp_(3) hybridised carbon atoms. Among those five SP^(3 ) carbon atoms are three methyl groups, one CH_(2)groupand one CH group. . It also contains two SP_(2)-hybridised carbonatoms . Alsothere is onlyone hydrogen atom attched to sp^(2)carbons. . The compound contains a total of six allylic hydrogen atoms. . The carbon atom that holds the Br has one H attached to it. When compound A reacts with boiling water , it undergoes an S_(N)1 reaction and produces. two principal products B and C . Both B andC are alcohols with their molecular formula C_(7)H_(14)O. Among the two alcohols, B has the --OH group attached to an sP_(3) carbon atom that has no H atoms bonded to it . What can be said about the isomerism shown by the two alcohols B and C ?

Answer»

Both B and C show STEREO isomerism and can be resolved into enantiomers
B and C are stereoisomers
Both B andC show STEREOISOMERISM but only CCan be resolved into enantiomers
Neither B or Ccan be resolvedintoenantiomers

Answer :C
90827.

A chemist involves mining process and he got two ores mixed together. If one is tinstone and another one is chromite, which type of process will be used to separate that two ores?

Answer»

Leaching process
Froth floatation process
Zone REFINING process
Magnetic SEPARATION process

Solution :Magnetic separation process
90828.

A chemist has one mole of X-atoms.He finds that on absorption of 4.10 kJ, half of X-atoms transfer one electron to the other half.It all the resulting X ions are subsequently converted to X^+ ions, an addition of 735 kJ is required.Find the electron affinity of X.

Answer»


SOLUTION :`X/2toX^(+)/2+e " " 1/2I.E.`…(i)
`e+X/2toX^(-)/2 " " 1/2 E.A. (-ve)`….(II)
(i)+(ii)
`Xto1/2X^(+)+1/2X^(-) " " 1/2(I.E.-E.A.)=410 kJ`
I.E.-E.A.=820 kJ
Now `1/2X^(-)to1/2X^(+)+2E^(-)`….(iii) `DeltaH=735`
Now equation (ii) can be achieved by (i)+reverse (ii) and we will get
`1/2I.E.+1/2E.A.=735`
`I.E.+E.A.=1470`...(iv)
2E.A.=650
E.A.=325 kJ/mol.
90829.

A chemist involves mining process and he got tow ores together .Ifoneis tinstone and another one is chromite,which type of process will be used to separate that two ores?

Answer»

LEACHING process
Froth FLOATATION process
Zone REFINING process
Magnetic SEPARATION process

Answer :D
90830.

A chemicla reaction is said to attain equilibrium when

Answer»

reactants GET completely converted into products
equal AMOUNTS of reactants and prodects are formed
the rate of forward reaction BECOMES equal to the rate of reverse reaction
the CONCENTRATION of reactants and products are same

Answer :C
90831.

A chemical reaction has catalyst X. Hence X

Answer»

Reduces enthalpy of the REACTION
DECREASES rate constant of the reaction
Does not affect equlibrium constant of reaction
Of the following which CHANGE will SHIFT the reaction towards the product

SOLUTION :Catalyst does not affect equlibrium constant.
90832.

A chemical system is in equilibrium Addition of a catalyst would result in:

Answer»

Increase in the rate of FORWARD REACTION
increase in the rate of REVERSE reaction
A new reaction path way to reaction
Increase the amount of heat evolved in the reaction

Answer :C
90833.

A chemical substance which radiues the temperature of body in fever is

Answer»

anti-inflammatory
antacid
ntipyretic
ntiseptic

Answer :C
90834.

A chemical substance whichcures the disease , is safe to use, has negligible toxicity and does not cause addiction is called a _______ while a chemical substance which cures the disease but is habit forming , causes addiction and has serious side effects is called a _______

Answer»


ANSWER :MEDICINE , DRUG
90835.

A chemical substance that forms an easily fusible slag with gangue is called as…

Answer»

Flux
Pure metal
Ore
impure metal

Answer :A
90836.

A chemical substance acts as the currency of energy metabolism in a cell. It is :

Answer»

ADENOSINE triphosphate
Adenosine diphosphate
Adenosine monophosphate
Glucose

Answer :A
90837.

A chemical reaction will not be feasible, if

Answer»

`TRIANGLEH" is POSITIVE and " triangleS` is ALSO positive
`triangleH" is positive and " triangleS` is NEGATIVE
`triangleH" is negative and " triangleS` is also negative
`triangleH" is negative and " triangleS` is also positive

Answer :B
90838.

A chemical reaction will be spontaneous if it is accompanied by a decrease in

Answer»

ENTROPY of the system
enthalpy of the system
internal eneryg of the system
free ENERGY of the system

Solution :GIBBS free energy of a system will decides the spontaneity of a PROCESS. If `DeltaG` is NEGATIVE , then the process is spontaneous.
90839.

A chemical reaction will be non-spontaneous if

Answer»

`E_("CELL")^(@)` is positive
`DELTAG^(@)` is negative
reaction quotient, `Q LT K`
`E_("cell")` is negative

Answer :D
90840.

A chemical reaction was carried out at 300 K and 280 K. The rate constants were found to be k_(1) and k_(2) respectively . Then

Answer»

`k_(2)=4k_(1)`
`k_(2)=2k_(1)`
`k_(2)=0.25 k_(1)`
`k_(2) = 0.5 k_(1)`

Solution :(C ) For every `10^(@)` C RISE in temperature rate CONSTANT becomes double . Therefore for `20^(@)` C rise in temperature rate constant will become 4 times i.e `k_(1)=4 k_(2) "or" k_(2) =0.25k_(1)` .
90841.

A chemical reaction was carried out 300 K and 208 K the rate constants were found to be K_(1) and K_(2) respectively. The energy of activation is 1.157xx10^(4) cal "mole"^(-1)and R=1.987 cal. Then

Answer»

`K_(2)=0.25K_(1)`
`K_(2)=0.5K_(1)`
`K_(2)=4K_(1)`
`K_(2)=2K_(1)`

ANSWER :A
90842.

A chemical reaction was carried out at 300 K and 280 K. The rate constants were found to be K_(1) and K_(2) respectively. Then

Answer»

`K_(2)=4K_(1)`
`K_(2)=2K_(1)`
`K_(2)=0.25K`
`K_(2)=0.5K_(1)`

SOLUTION :( c ) : For every `10^(@)C` rise in temperature, RATE constant is doubled. Hence, for `20^(@)C` rise in temperature, rate constant will BECOME 4 times, i.e., `K_(1)=4K_(2)" or "K_(2)=0.25K_(1).`
90843.

A chemical reaction takes place in a vessel of cross-sectional area 150 cm^2. Due to the reaction , the piston of the vessel is moved upward by 15 cm against the external pressure of one atm. The work done by the system is

Answer»

`- 3.35 L-atm`
`+ 3.35 L-atm`
`- 2.25 L-atm`
`- 5.51 L-atm`

ANSWER :A
90844.

A chemical reaction proceeds following the formula k = Pze^(-E_(a) //RT) Which of the following processes will increase the rate of reaction

Answer»

<P>LOWERING of `E_(a)`
Lowering of P
Lowering of Z
Independent of all the above factors

SOLUTION :Lowering of `E_(a)` , raises the VALUE of k .
90845.

A chemical reaction occurs in three paths having rate constants k_(1),k_(2) and k_(3) respectively. If Ea_(1),Ea_(2) and E_(a_(3) are 4,5 and 8kJ respectivel and overall rate constant k=(k_(1)k_(3))/(k_(2)). Assuming A_(av)=(A_(1)A_(3))/(A_(2)) the overall energy of activation in kJ is __________

Answer»


SOLUTION :`Aunderset(epsilona=)OVERSET(K)(to)`
`K=A.e^(-Ea//RT),K_(1)=A_(1).e^(-E_(1)//RT),K_(2)=A_(2).e^(-E_(2)//RT),K_(3)=A_(3).e^(-E_(3)//RT)`
Here `K=(K_(1).K_(3))/(K_(2)),A//e^((-Ea//RT))=(A_(1).e^((-E_(1))/(RT))xxA_(3).e^((-E_(3))/(RT)))/(A_(2).e^((-E_(2))/(RT)))impliesA=(A_(1).A_(3))/(A_(2))impliese^((-Ea)/(RT))=e^((-epsilon_(1)-epsilon_(3)+epsilon_(2))/(RT))`
`IMPLIES(-Ea)/(RT)=((-epsilon_(1)+epsilon_(2)-epsilon_(3)))/(RT)impliesEa=(epsilon_(1)-epsilon_(2)+epsilon_(3)),epsilon_(a)=(4-5+8)=-1+8=7`
90846.

A chemical reaction is spontaneous at 298 K but non-spontaneous at 350 K. Which one of the following is true for the reaction ?

Answer»

`{:(Delta G,Delta H,Delta S),(-,-,+):}`
`{:(Delta G,Delta H,Delta S),(+,+,+):}`
`{:(Delta G,Delta H,Delta S),(-,+,-):}`
`{:(Delta G,Delta H,Delta S),(-,-,-):}`

SOLUTION :`Delta G (-) = Delta H (-) - T Delta S (+ve)`
At high temperature, second TERM will have high +ve value and REACTION will be non-spontaneous.
90847.

A chemical reaction is said to take place through the various stages with DeltaG^(@) values as indicated by the graph. stages I and II respectively:

Answer»


SOLUTION :B) is the CORRECT
90848.

A chemical reaction is known to be of zero-order with k = 5 xx 10^(-8)" mole lit"^(-1) s^(-1) .(a) How long does it take for reactant concentration to decrease from 4 xx 10^(-4)" molelit"^(-1)to 2 xx 10^(-4) "mole lit"^(-1)?(b) Will the time to decrease the reactant concentration from 2 xx 10^(-2) "mol lit"^(-1) to 1xx 10^(-2) "mole lit"^(-1)be the same as in (a)?

Answer»

SOLUTION :`4 XX 10^3 s, No`
90849.

A chemical reaction is spontaneous at 298 K but non-spontaneous at 350 K. Which one of the following is true for the reaction

Answer»

`{:(DeltaG,DeltaH,DeltaS),("_","_","+"):}`
`{:(DeltaG,DeltaH,DeltaS),("+","+","+"):}`
`{:(DeltaG,DeltaH,DeltaS),("-","+","-"):}`
`{:(DeltaG,DeltaH,DeltaS),("-","-","-"):}`

Solution :`DeltaG=DeltaH-TDELTAS`
For first condition, REACTION will be spontaneous at all temperatures.
For second option as `DeltaH=+ve` and `DeltaS` is +ve THUS`DeltaG=underset(+ve)underbrace(DeltaH)-underset((-ve))underbrace(TDeltaS)`
If TEMPERATURE is high, `TDeltaS` will have higher negative value and reaction will be spontaneous
Thus not true for given reaction.
In case (c), `DeltaG`=ve, `DeltaS=+ve`
impliesspontaneous at all temperatures
In case (e), `DeltaG=underset(-ve)underbrace(DeltaH)-underset(+ve)underbrace(TDeltaS)`
At high temperature, second TERM will have high positive value and reaction will be non-spontaneous, thus case (e) is true for given example.
90850.

A chemical reaction is catalyzed by a catalyst' X'. Hence the catalyst 'X'

Answer»

Changes the EQUILIBRIUM constant of the reaction
Changes the ENTHALPY of reaction (AH)
Alters the concentration of both reactants and PRODUCTS in a state of equilibrium
Increases the speed of both the forward and backwand eactions to same extent in a reversible

Answer :D