Explore topic-wise InterviewSolutions in Current Affairs.

This section includes 7 InterviewSolutions, each offering curated multiple-choice questions to sharpen your Current Affairs knowledge and support exam preparation. Choose a topic below to get started.

1.

In the given figure, which of the diodes are forward biased? A. `1,2,3`B. `2,4,5`C. `1,3,4`D. `2,3,4`

Answer» Correct Answer - B
(2) in figure 2,4 and 5. P-crystals are more positive as compared to N-crystals
2.

When a point charge of `(1)/(3)mu C` is placed on the axis of a thin disc of total charge `(2)/(3)mu C` (uniform distribution) aned radius `3.95 cm` such that distance. Between point charge and centre of disc is 1 m, then force experienced by disc is approximately :A. `4mN`B. `6mN`C. `3mN`D. `2mN`

Answer» Correct Answer - D
Behaviour of disc is like a point charge because distance between the disc and the point charge is very large in comparison to radius of disc.
`F = (9 xx 10^(9)xx (2)/(3)mu C xx (1)/(3) muC)/(1^(2))=2mN`
3.

The potential energy of a particle of mass `m` free to move along the x-axis is given by `U=(1//2)kx^2` for `xlt0` and `U=0` for `xge0` (x denotes the x-coordinate of the particle and k is a positive constant). If the total mechanical energy of the particle is E, then its speed at `x=-sqrt(2E//k)` isA. zeroB. `sqrt((2E)/(m))`C. `sqrt((E)/(m))`D. `sqrt((E )/(2m))`

Answer» Correct Answer - A
From conservation of energy
`K.E + P.E = E`
or `K.E = E - (1)/(2) kx_(2)`
K.E at `x =- sqrt((2E)/(k))` is
`E -(1)/(2)k((2E)/(k))=0`
`:.` The speed of particle at `x = - sqrt((2E)/(k))` is zero.
4.

Magnetic monopole exist at?A.neutron starB.does not exist

Answer»

Magnetic poles doesn't exist. If they exist, could be pair-produced nonperturbatively in the extreme magnetic fields of neutron stars.

Hence option (A) can be the right answer

Correct option is (B) does not exits

Magnetic monopole does not exists because magnetic north pole and the south pole can never be separated even on breaking a magnet to its atomic size. A magnetic field is produced by an electric field and not by a monopole.

5.

How does the poet describe the Jazz?

Answer»

player’s appearance and his music? He stood at the crest of the tallest hill. He was old and had wrinkled face. He had no interest in life. His head was turned downward, he closed his eyes. He wore an old faded blue shirt. That shirt was dark with sweat, the tie was tom. The jacket was old and it could not hold his sagging (hanging) stomach.

He wore the old shoes which had papers inside. His face was not shaved. One could see the pain in each wrinkle of his face. He alone stood with his head down and eyes closed. He wore an old alto saxophone and chanting some religious music in low voice. That old saxophone was hanging from his neck by a wire coat hanger.

He wanted to tell that he was a Black Man. He had been sent here to preach the Black Gospel of Jazz. He was preaching it with words by loud musical sound. When he started to preach, he was transformed into a Bird. That Bird gathers its wings and flies high, high and higher until it flies away. Otherwise he come back to find himself as a Black man again.

6.

Write an essay on Ksheer Bhagya Yojana at School:

Answer»

This yojana includes providing milk to the children of Govt schools. As like mid day meal, this is an essential thing as majority of the children of GOV school are coming from so poor families “that they cannot afford milk. Considering the nutritional value of milk, this is again a good gesture that keeps the physical, mental and emotional aspect of a child in check.

Whichever be the plan, executing is equally important and it should be ensured that a perishable item like milk will be served without any chance of contamination. In Govt. Schools in Kerala, it is successfully applied. The teachers provide milk and egg on certain days to the children in the morning itself apart from mid day meal. If successfully implemented, the Govt can check the drop outs in Govt school and a healthy student generation also will be a reality.

7.

How does the poet discriminate Jazz player’s appearance with his artistic character?

Answer»

He stood at the crest of the tallest hill. He was old and had wrinkled face. He had no interest in life. His head was turned downward, he closed his eyes. He wore an old faded blue shirt. That shirt was dark with sweat, the tie was tom. The jacket was old and it could not hold his sagging (hanging) stomach. He wore the old shoes which had papers inside. His face was not shaved. One could see the pain in each wrinkle of his face. He alone stood with his head down and eyes closed. He wore an old alto saxophone and chanting some religious music in low voice. That old saxophone was hanging from his neck by a wire coat hanger.

8.

Write in brief your vision of the future of India.

Answer»

According to poet, the future of our country can open up on mothers forehead. It is like earth’s destiny. All the sorrows and sufferings came to an end and the new things and views will come and make the people happy. The Sun God will protect the earth and saves all. I envision of very bright future for India. A India where there all it people work hard for the development of the country. All Indians should be happy and live harmoniously with each other. There should be no discrimination aftd all the people should be treated as equal.

9.

Read the following passage and answer the questions that follow : A king had two clever sons, but they were very mischevious. They spent their time and money wastefully. They had a younger cousin whom they called ‘simpleton’ because he was quite and simple. They would make fun of him for his simplicity. 1. How many sons the king had? 2. How did they spend their time and money? 3. Who was Quiet and simple?4. Why did they called their cousin as simpleton?

Answer»

1. The king had two clever sons.

2. They spend their time and money wastefully.

3. Their younger cousin was quiet and simple.

4. They called their younger cousin as simpletton because he was quiet and simple.

10.

The poem has figures of speech. One is given, “a chain link necklace chokes me” is personification. Pick out one or two or more such figures of speech from the poem.

Answer»
  • I am the land. I wait.
  • You shout. I lie patient.
  • With muddy holes and car lot eyes I stare.
11.

Equal currents `i=1` A are flowing through the wires parallel to y-axis located at `x=+1m, x=+2m, x=+4m` and so on...., etc. but in opposite directions as shown in Fig The magnetic field (in tesla) at origin would be A. `-1.33xx10^(-7)hat(k)`B. `1.33xx10^(-7)hat(k)`C. `2.67xx10^(-7)hat(k)`D. `-2.67xx10^(-7)hat(k)`

Answer» Correct Answer - B
`B_(1)=(mu_(0)i)/(2pi) o. " " B_(2)=(mu_(0)i)/(4pi) ox " " B_(3)=(mu_(0)i)/(8pi) o.`
`B_("net")=(mu_(0)i)/(2pi)+(mu_(0)i)/(8pi)-(mu_(0)i)/(4pi) ......`
`=(mu_(0)i)/(2pi)[1-(1)/(2)+(1)/(4)......oo]`
`=(mu_(0)i)/(2pi)[(1)/(1+(1)/(2))]=(mu_(0)i)/(3pi)=(4)/(3)xx10^(-7)=1.33xx10^(-7o.)`
12.

A coil having an inductance of `1//pi` henry is connected in series with a resistance of `300 Omega`. If 20 volt from a 200 cycle source are impressed across the combination, the value of the phase angle between the voltage and the current is :A. `tan^(-1)((5)/(4))`B. `tan^(-1)((4)/(5))`C. `tan^(-1)((3)/(4))`D. `tan^(-1)((4)/(3))`

Answer» Correct Answer - D
`tanphi=(X_(L))/(R)=(2pifL)/(R)=(2pixx200xx(1)/(pi))/(300)=(4)/(3)`
or `phi="tan"^(-1)(4)/(3)`
13.

The diagram given below shows a solenoid carrying time varying current `l= l_(0)t`. On the axis of the solenoid, a ring has been placed. The mutual inductance of the ring and the solenoid is M and the self inductance of the ring is L. If the resistance of the ring is R then maximum current which can flow through the ring is A. `((2M+L)I_(0))/(R)`B. `(MI_(0))/(R)`C. `((2M-L)I_(0))/(R)`D. `((M+L)I_(0))/(R)`

Answer» Correct Answer - B
`phi=MI=MI_(0)t`
Hence, induced emf `e=(d phi)/(dt)=MI_(0)`
Current through ring `=e/R=(MI_(0))/(R)`.
14.

The diagram given below shows a solenoid carrying time varying current `l= l_(0)t`. On the axis of the solenoid, a ring has been placed. The mutual inductance of the ring and the solenoid is M and the self inductance of the ring is L. If the resistance of the ring is R then maximum current which can flow through the ring is A. `((2M+L)l_(0))/(R )`B. `(Ml_(0))/(R )`C. `((2M-L)l_(0))/(R )`D. `((M+L)I_(0))/(R )`

Answer» Correct Answer - C
`Hgunderset((A))((NO_(3))_(2))+underset((B))(NH_(4)I)rarrunderset("Colourless soln")underset((E))underset(K_(2)[Hg|_(4)])underset(darrunderset(Kl)(Excess))underset(("Red"))underset((C )) (HgI_(2)darr)+underset((F))underset(NH_(3)(g))underset(darrunderset("NaOH Soln")("warm with"))underset((D))(NH_(4)NO_(3))`
`K_(2)[Hgl_(4)]+KOH+NH_(3)rarrHgO.underset(("brown"))(Hg(NH_(2)))darr`
`Hg(NO_(3))_(2)+H_(2)SO_(4)+C_(6)H_(10)O_(5)overset("warm")rarrCO_(2)uarr+underset(("Brown"))(NO_(2))uarr+HgSO_(4)darr`
15.

An X-ray tube has three main controls. (i). The target material (its atomic number Z) (ii). The filament current `(l_(f))` and (iii). The accelerating voltage (V) Figure shown a typical intensity distribution against wavelength which of the following si incorrect?A. The limit `lamda_(min)` is proportional to `V^(-1)`B. The sharp peak shifts to the right as Z is increasedC. The penetrating power of X ray increases if V is increasedD. The intensity everywhere increases if filament current `l_(f)` is increased

Answer» Correct Answer - B
As accelerating voltage is increased, energy increases, the `lamda_(min)` decreases and X-rays are getting harder (less wavelength) and penetrating power increases if filament current increases, more electrons are emitted.
16.

During negative B decay, an anti- neutrino is also emmited along with the ejected electron. ThenA. only linear momentum will be conservedB. total linear momentum and total angular momentum but not total energy will be conservedC. total linear momentum and total energy but not total energy but not total angular momentum will be conservedD. total linear momentum, total angular momentum and total energy will be conserved

Answer» Correct Answer - D
17.

To estimate `g` (from `g = 4 pi^(2)(L)/(T^(2))`), error in measurement of `L` is `+- 2%` and error in measurement of `Tis +- 3%` The error in estimated `g` will beA. `+-8%`B. `+-6%`C. `+-3%`D. `+-5%`

Answer» `g = 4pi^(2) (l)/(T^(2))`
`(Deltal)/(l) =2% = +- 2 xx 10^(-2)`
`(DeltaT)/(T) = +- 3% = +- 3 xx 10^(-2) rArr (Deltag)/(g) = (Deltal)/(l) + (2DeltaT)/(T) = 2 xx 10^(-2) + 2 xx 3 xx 10^(-2) = 8 xx 10^(-2) = +- 8%` .
18.

Which of the following has highest tendency to ionise in aqueous solution ?A. `HCOOH`B. `CH_(3)COOH`C. `FCH_(2)COOH`D. `BrCH_(2)COOH`

Answer» Correct Answer - 3
`-I` group increases acidity.
19.

The external and internal diameters of a hollow cylinder are measured to be `(4.23+-0.01)` cm and `(3.89+-0.01)`cm. The thickness of the wall of the cylinder isA. `0.34+- 0.02 cm`B. `0.17 +- 0.02 cm`C. `0.17 + - 0.01cm`D. `0.34 +- 0.01 cm`

Answer» `D = (4.23 +- 0.01)cm`
`d = (3.89 +- 0.01)cm`
`Deltat = (D -d)//(2)`
`= ((4.23 +-0.01)-(3.9=89+-0.01))/(2)`
`=((4.23-3.89)+-(0.01+0.01))/(2)`
`=(0.34 +- 0.02)//2cm`
`=(0.17 +- 0.01)cm` .
20.

Identify PA. B. C. D. None of these

Answer» Correct Answer - 1
Electrophile attack on that ring which have more `+M` effect.
21.

What will be the volume strength of 100 ml of `H_(2)O_(2)` required to react completely with 61 ml of `KMnO_(4)` in acidic medium ? ( Given that `61 l` of `KMnO_(4)` reacts completely with 5 ml of 1M of `K_(4)[Fe(CN)_(6)]` where it converts into `K^(+),Fe^(3+),CO_(3)^(2-)` and `NO_(3)^(-)` )A. `17.08`B. `34.2`C. `18.8`D. `19.8`

Answer» Correct Answer - 1
Valency factor of `K_(4)[(Fe(CN)_(6)]=61`
so of molarity of `H_(2)O_(2)=x M` than
`implies2x xx100=5xx61xx1`
`[` for `KMnO_(4). 61xxyxx5=5xx61xx1impliesy=1M]`

So, `x=(305)/(200)=1.525.` So , volume strength `=17.08`
22.

A quantity of gas is collected in a graduated tube over the mercury. The volume of gas at `18^(@)C` is 50 mL and the level of mercuty in the tube is 100mm above the outside mercuty level. The barometer reads 750 torr. Hence, volume of gas 1 atm and `0^(@)C` is approximately:A. `22 ml`B. `40 ml`C. `20ml`D. `44ml`

Answer» Correct Answer - 2
Net pressure of gas `=P_("gas")`
`P_("gas")=650mm`
`(P_(1)V_(1))/(T_(1))=((P_(2)V_(2))/(T_(2)))_(STP)" , "(650xx50)/(291)=(760xxV_(2))/(273)`
`V_(2)=40.11ml`
`P_(1)=9 atm" "P_(2)=6 atm`
`V_(1)=6l" "V_(2)=10l`
23.

Consider a conducting circular loop placed in a magentic filed as shown. When magnetic field changes with time, magentic flux also changes and emf is induced. `e=-(dphi)/(dt)` If resistance of loop is R then induced current. `i=e/R` For Current, charge must have come into motion. Magnetic force cannot make the statinoary charges to move. Actually there is an induced electric field in the conductor caused by changing magnetic flux, which make the change to move `intvec(E).dvec(l)=e=-(dphi)/(dt)` This induced electric field is non-electrostatic by nature. line integral of `vec(E)` around a closed path is non-zero A square non- conducting loop 20 cm on a side is placed in a magnetic field The centre of side AB coincides with the centre of magnetic field The magnetic field is increasing at the rate of 2T/s. Find the magnitude of line integral of induced electric field along path BC. A. 10 mVB. 20 mVC. 30 mVD. zero

Answer» Explanation:
Perpendicular distance between BC and centre O is 10 cm. component of induced electric field along
the rod =`d/2 (dB)/(dt)`
where d =Perpendicular distance from centre to the rod.
Hence, potential difference between the ends of rod
`v=EI=I. d/2 (dB)/(dt)`
`=10/2xx10^(-2)xx20xx10^(-2)xx2=20 mV`
Hence, choice (b) is correct and choices (a),(c) and (d) are wrong.
24.

Consider a conducting circular loop placed in a magentic filed as shown. When magnetic field changes with time, magentic flux also changes and emf is induced. `e=-(dphi)/(dt)` If resistance of loop is R then induced current. `i=e/R` For Current, charge must have come into motion. Magnetic force cannot make the statinoary charges to move. Actually there is an induced electric field in the conductor caused by changing magnetic flux, which make the change to move `intvec(E).dvec(l)=e=-(dphi)/(dt)` This induced electric field is non-electrostatic by nature. line integral of `vec(E)` around a closed path is non-zero Refer to above questions, Find the magnitude of line integral of induced electric field along path CD.A. 40 mVB. 60 mVC. 80 mVD. zero

Answer» Explanation :
Perpendicular distance between CD and O is 20 cm .
There fore, induced emf in CD
`=d/2I(dB)/(dt)=20/2xx10^(-2)xx20xx10^(-2)xx2`
`=40 mV`
25.

100 ml 0.2 M `Na_(2)A` is titrated with 100ml 0.03 M HCl. Calculate pH of final solution. `pKa_(1)(H_(2)A)=5" "pKa_(2)(H_(2)A)=9`A. 2B. 7.5C. 5D. 9

Answer» Correct Answer - A
`SO_(2)Cl_(2)(g)rarrSO_(2)(g)+Cl_(2)(g)`
0.5
`0.5-x " "x" "x`
`K_(A)=(1)/(100)ln.(0.5)/(0.25)=(ln2)/(100)`
Rate `=KP_(A) = (ln2)/(100)xx0.3=2.1xx10^(-3)"atm"//"sec"`
26.

The order of reactivity of phenyl magnesium bromide with the following compound is (I) Acetone (II) Acetaldehyde (III) Acetophenone (IV) BenzonphenoneA. `I gt II gt III gt IV`B. `II gt I gt III gt IV`C. `IV gt III gt II gt I`D. `III gt IV gt I gt II`

Answer» Correct Answer - B
`underset("of chalcopyrite ")underset("Aqueous solution obtained on leaching")ubrace(CuSO_(4)(aq)+FeSO_(4)(aq))+ZnrarrZnSO_(4)+underset("as impurity ")underset("Iron is also obtained")ubrace(Fedarr+Cudarr)`
27.

The appropriate reagent for the following transformation A. `Zn(Hg),HCl`B. `H_(2),Ni`C. `NH_(2)-NH_(2),overset(ӫ)(O)H`D. `NaBH_(4)`

Answer» Correct Answer - C
`[Pt(H_(2)O)_(4)(OX)][CuCl_(4)]:` Exhibits coordination isomerism
28.

Ferric alum does not form precipitate with.A. NaOHB. `BaCl_(2)`C. `Na_(2)CO_(3)`D. `H_(2)S" gas"`

Answer» Correct Answer - C
For maximum volume of 3M HCl solution 2M, 1L HCl solution should be used completely.
`M_(1)V_(1)+M_(2)V_(2)=M_(f)V_(f)" "2xx1+5xxV=3xx(1+V),V=(1)/(2)l,V_(f)=(3)/(2)l`
29.

The specific conductivity of `N//10` KCl solution at `20^(@)C` is 0.212 `ohm^(-1) cm^(-1)` and the resistance of the cell containing this solution at `20^(@)C` is 55 ohm. The cell constant is :A. `4.616cm^(-1)`B. `1.166cm^(-1)`C. `2.173cm^(-1)`D. `11.66cm^(-1)`

Answer» Correct Answer - B
Rate of `SN_(2)` reaction `propunderset("Steric over crowding in transition state")overset(1)_`
30.

The correct sequence which shown decreasiong order of the ionic radii of the elements is :A. `AI^(3+)gt Mg^(2+)+Na^(+)gt F^(-)O^(2-)`B. `Na^(+)gtMg^(2+)gtAI^(3+)gtO^(2-)gtF^(-)`C. `Na^(+)gtF^(-)Mg^(2+)gtO_(2-)gtAI^(3+)`D. `O^(2-)gtF^(-)Na^(+)gtMg^(2+)gtAI^(3+)`

Answer» Correct Answer - D
The correct sequence which shows …………
For isoelectronic species, ionic radii
`prop (1)/("nuclear charge")`
So, correct order of ionic radii is
`8^(O^(2-))gt g^(F^(-))gt 11^(Na^(+))gt 12^(Mg^(2+))gt 13^(A//3+)`
31.

The salt which does not form coloured metaborate in borax bead test.A. `Fe_(2)(SO_(4))_(3)`B. `Al_(2)(SO_(4))_(3)`C. `Cr_(2)(SO_(4))_(3)`D. `CoSO_(4)`

Answer» Correct Answer - A
`(r_(x_(3)))/(r_(CH_(4)))=sqrt((M_(CH_(4)))/(M_(x_(3))))`
`(4//3)/(1)=sqrt((16)/(M_(x_(3))))" "M_(x_(3))=9`
Atomic mass x = 3
`V.D.=(9)/(2)=4.5" "d=(MP)/(RT)`
32.

Give the conect order of initials T(true) or F(false) for following statements [3] I : Lyophobic sols are irreversible sols. II : Micelles fonnation takes place only above krafc temperature III : `PO_4^(3-)` ions have more coagulation value than `SO_4^(2-)` 2ions for coagulation ofpositive sols. IV : The volues of the colligative properties observed exXperimcntall are ve small of colloied solsA. F T T FB. T F T FC. T T T TD. T T F T

Answer» Correct Answer - D
33.

Oxidation state of the metal in the mineral heamatic and magnerite respectively areA. `+2,+3` in hematite and `+3` in magnetiteB. `+2,+3` in hematite and `+2` in magnetiteC. `+2,` in hematite and `+2, +3` in magnetiteD. `+3` in hematite and `+2, +3` in magnetite

Answer» Correct Answer - d
`Haematite rArr Fe_(2)O_(3) rArr Fe(+3)`
`Magnetic rArr Fe_(2) O_(4) rArr FeO rArr FeO Fe_(2)O_(3) rArr Fe(+2) ,Fe(+3)`
34.

In correct statement about given carbohydrate is A. Above compound is a reducing sugarB. Above compound undergo mutarotationC. Above compound is a non-reducing sugarD. Above compound has a glycosidic linkag

Answer» Correct Answer - C
35.

What is the correct order of `2^(nd)` ionisation energy ?A. `F lt N lt C lt O`B. `N lt C lt F lt O`C. `C lt N lt F lt O`D. `O lt C lt F lt N`

Answer» Correct Answer - B
What is the correct order …………..
After removal of one electron :
`{:(C^(+):1s^(2)2s^(2)2p^(1), , , N^(+)1s^(2)2s^(2)2p^(2)),(O^(+):1s^(2)2s^(2)2p^(3), , , F^(+): 1s^(2)2s^(2)2p^(4)):}`
Remioval of second electron will requie maximum energy in case of O because of its half filed electronic configuration after removal of one electron.
`:.` increaseing order of 2nd ionisation enthalpy : `C lt N lt F lt O`
36.

Which of the following oxy anion is metaborate ion ?A. `BO_(3)^(3-)`B. `BO_(2)^(-)`C. `B_(2)O_(7)^(4-)`D. `B_(2)O_(5)^(4-)`

Answer» Correct Answer - D
Which of the following oxy anion …………
`BO_(2)^(-)` is meta - borate ion.
37.

Correct statement about I and II A. I is reducing sugarB. II is reducing sugarC. I & II both are reducing sugarD. None of the two is reducing sugar

Answer» Correct Answer - C
38.

Which method of parification is represented by the following equation ? `Ti(s) + 2I_*(2)(g) rarr TiI_(4)(g) rarr Ti(s) + 2I_(2)(g)`A. van arkelB. polingC. CupellationD. zone reflation

Answer» Correct Answer - a
Van arkel method is very useful for removing all the oxegen nitrogen present in the form imparity in cartain matals like `Zr and Ti`
The process of capellation involves the septration of `Ag` At and after noble metals is placed in a capel, it flat dish made of porous refracting meterail, and a blast of but air is directed upon it in a special furnace , the impurities are oxidried by the air and are partly swept awAy by the blass and partly abserhed by the cupel.
39.

`HgI_2` (yellow) will be turned into Hgl2 (med) variety onA. HeatingB. CoolingC. Application of mechanical stressD. Subliming

Answer» Correct Answer - C
40.

Copper pyrites ore is concentrated byA. electromagnetic methodB. gravity methodC. froth floatation processD. All of the above

Answer» Correct Answer - A
Sulphide ores are concentrated by froth floatation method. Thus , copper pyrites `(CuFeS_2)` is concentrated by froth floatation process.
41.

Which of the following metal can not be extracted by smelting processA. ZnB. AlC. PbD. Fe

Answer» Correct Answer - B
Smelting is the proces of reduction of a metal oxide to metal with C. Aluminium being highly electropositive cannot be obtained by the reduction with C.
42.

Which of the following sulphides when heated strongly in air gives the corresponding metal?A. `Cu_(2)S`B. `CuS `C. `Fe_2S_3`D. `HgS `

Answer» Correct Answer - D
HgS when heated strongly in air gives mercury and sulphur dioxide .
`HgS +O_(2) overset("Roasting ")to Hg +SO_(2)`
43.

which of the following is present in tea as well as in bark of a treea) Tannic acidb) Oxallic acidc) Cellulosed) Caffeine

Answer» Answer: (a) Tannic acid
44.

Cellulose is polymer of (a) Ribose (b) Fructose (c) Glucose (d) Sucrose

Answer»

(c) Glucose.

45.

Polymer formation from monomers starts by (a) condensation reaction between monomers (b) coordination reaction between monomers (c) conversion of monomers to monomer ion by protons(d) hydrolysis of monomers

Answer»

(a) condensation reaction between monomers

46.

If ten volumes of dihydrogen gas reats with five volumes of dioxygen gas, how many volumes of water vapour would be produced?

Answer» `H_(2)` and `O_(2)` react according to the equation
`2H_(2)(g)+O_(2)rarr 2H_(2)O(g)`
Thus, 2 volumes of `H_(2)` react with `1` volume of `O_(2)` to produce `2` volume of water vapour. Hence, `10` volumes of `H_(2)` will react completely with `5` volumes of `O_(2)` to produce `10` volumes of water vapour
47.

Name 5 double salts.

Answer»

Potash alum - K2SO4 Al2 (SO4)3 .24H2O
Dolomite - CaCO3.MgCO3

Alstonite, calcium barium carbonate - CaBa(CO3)2

Carnallite, KMgCl3·6H2O
Potassium sodium tartrate hydrate  - KNaC4H4O6·4H2O 

48.

What is Double salts? Give an examples.

Answer»

The addition compounds formed by the combination of two simple salts are termed as double salts.

Ex: FeSO4 (NH4)2 SO4 . 6H2O (Ferrous ammonium sulphate), K2SO4 Al2 (SO4)3 .24H2O (Alum) and other alums.

(ii) Above salts are stable in solid state only. 

(iii) When dissolved in water, it furnishes all the ions present in the simple salt from which it has been constituted. 

(iv) The solution of double salt shows the properties of the simple salts from which it has been constituted.

49.

What is Simple salts ? Give its types.

Answer»

The salts formed by the neutralisation process between acid and base. 

These are of three types:

(i) Normal salt : 

(i) The salt formed by the loss of all possible protons (replaceable H+ ions) 

Ex: NaCl, NaNO3, K2SO, Ca3 (PO4)2, Na3 BO3, Na2 HPO3, NaH2 PO2 etc. 

(ii) Acid salts : 

(i) Salts formed by incomplete neutralisation of polybasic acids. Such salts contain one or more replaceable H atom. 

Ex: NaHCO3 , NaHSO4 , NaHPO4, Na2 HPO4 etc. 

(ii) Above salts when neutralized by base form normal salts. 

(iii) Basic salts : 

(i) Salts formed by in complete neutralisation of poly acidic bases are called basic salts. These salt contain one or more hydroxyl groups. 

Ex: Zn(OH)Cl, Mg(OH)Cl, Fe(OH)2 Cl, Bi(OH)2 Cl etc. 

(ii) Above salts when neutralised by acids form normal salts.

50.

State the Salts.

Answer»

(i) Salts are the ionic compounds formed when its positive part (Cation) come from a base and its negative part (Anion) come from an acid. 

(ii) Salts may taste salty, bitter, astringent or sweet or tasteless. 

(iii) Solution of salts may be acidic, basic or neutral. 

(iv) Fused salts and their aqueous solutions conduct electricity and undergo electrolysis. 

(v) The salts are generally crystalline solids.