311 + Interview Questions in QUANTITATIVE APTITUDE in TIME AND WORK Page 6 InterviewSolution

251.	1). 62). 25/43). 124). 25/2
Answer» A complete work in = 25 days A’s 1 - DAY work = 1/25 B complete work in = 15 days B’s 1 - day work = 1/15 Both working together for 1 hour = (1/25) + (1/15) Both working together for 1 hour = (3 + 5)/75 TIME to complete the work together = 75/8 = 9(3/8) days ∴ Time to complete (2/3) of total work together = (75/8) × (2/3) = (25/4) days

251.

1). 62). 25/43). 124). 25/2

Answer»

A complete work in = 25 days

A’s 1 - DAY work = 1/25

B complete work in = 15 days

B’s 1 - day work = 1/15

Both working together for 1 hour = (1/25) + (1/15)

Both working together for 1 hour = (3 + 5)/75

TIME to complete the work together = 75/8 = 9(3/8) days

∴ Time to complete (2/3) of total work together = (75/8) × (2/3) = (25/4) days

Discussion

252.	Two men undertook to do a Job for Rs. 1400. One of them can do it alone in 7 days, and the other in 8 days. With the assistance of a boy they together completed the work in 3 days. How much money will the boy get ?1). Rs. 3002). Rs. 3253). Rs. 2754). Rs. 250
Answer» ANSWER for this QUESTION is RS. 275

Discussion

253.	A can do a work in 12 days and B in 24 days. If they work on it together for 4 days, then what fraction of work is left?1). 1/32). 1/23). 1/44). 1/5
Answer»

Discussion

254.	x does $\frac{1}{4}$ of a job in 6 days. y completes rest of the job in 12 days. Then x and y could ccomplete the job together in1). 9 days2). $9\frac{3}{5}$ days3). $8\frac{1}{8}$ days4). $7\frac{1}{3}$ days
Answer» Its very simple QUESTION $9\frac{3}{5}$ days is the CORRECT answer.

Discussion

255.	Two persons can complete a piece of work in 9 days. How many more persons are needed to complete double the work in 12 days ?1). 32). 23). 44). 1
Answer» ANSWER for this QUESTION is OPTION 1

Discussion

256.	A and B can do a piece of work in 8 days, B and C can do it in 24 days, while C and A can do it in $8\frac{4}{7}$ days. In how many days can C do it alone ?1). 60 days2). 40 days3). 30 days4). 10 days
Answer» RIGHT ANSWER for this QUESTION is OPTION 1

Discussion

257.	A work can be completed by 28 women in 36 days. If 4 women leave after working for 18 days, then how many days will be needed to complete the remaining work?1). 242). 213). 274). 25
Answer» Number of person DAYS required = 28 × 36 = 1008 Number of person days spent = 28 × 18 = 504 Number of people left = (28 - 4) = 24 Using the formula for person days 1008 = 504 + 24x ⇒ 24x = 1008 - 504 = 504 ⇒ X = 504/24 = 21 days ∴ Number of days needed to complete remaining work = 21

257.

A work can be completed by 28 women in 36 days. If 4 women leave after working for 18 days, then how many days will be needed to complete the remaining work?1). 242). 213). 274). 25

Answer»

Number of person DAYS required = 28 × 36 = 1008

Number of person days spent = 28 × 18 = 504

Number of people left = (28 - 4) = 24

Using the formula for person days 1008 = 504 + 24x

⇒ 24x = 1008 - 504 = 504

⇒ X = 504/24 = 21 days

∴ Number of days needed to complete remaining work = 21

Discussion

258.	Suman can do a work in 3 days. Sumati can do the same work in 2 days. Both of them finish the work together and get Rs. 150. What is the share of Suman ?1). Rs. 302). Rs. 603). Rs. 704). Rs. 75
Answer» RS. 60 is the CORRECT answer as per the SSC answer key

Discussion

259.	Aman and Ajay can build a wall in 9 days and 12 days respectively. In how many days can they finish the work if they work together?1). \(5\frac{1}{7}\)2). \(11\frac{1}{2}\)3). 24). 7
Answer» ⇒ Aman’s EFFICIENCY = 1/9 ⇒ AJAY’s efficiency = 1/12 ⇒ Efficiency of Ajay and Aman TOGETHER = (1/9) + (1/12) = 7/36 ⇒ TIME taken = 36/7 = $(5\frac{1}{7})$

259.

Aman and Ajay can build a wall in 9 days and 12 days respectively. In how many days can they finish the work if they work together?1). $5\frac{1}{7}$2). $11\frac{1}{2}$3). 24). 7

Answer»

⇒ Aman’s EFFICIENCY = 1/9

⇒ AJAY’s efficiency = 1/12

⇒ Efficiency of Ajay and Aman TOGETHER = (1/9) + (1/12) = 7/36

⇒ TIME taken = 36/7 = $(5\frac{1}{7})$

Discussion

260.	Grassin a field can completely feed 20 cows or 30 goats for a day. The same field is sufficient to feed 8 cows and 12 goats for1). \(1\frac{1}{2}\) days2). \(1\frac{1}{3}\) days3). \(1\frac{1}{9}\)days4).
Answer» ⇒ 20 cows or 30 goats can eat GRASS for 1 day from field ⇒ 30 goats will eat grass for 1 day ⇒ 1 goat will eat grass for 30 DAYS ⇒ 20 cow = 30 goats ⇒ 1 cow = (30/20) ⇒ 1 cow = 3/2 ⇒ Let x day for 8 cow and 12 goats same field will be sufficient ⇒ 8 cow + 12 goats = 8 (3/2) + 12 ⇒ 8 cow + 12 goats = 24 goats ⇒ 1 goat will eat grass for 30 days ⇒ 24 goats will eat grass for (30/24) ⇒ 24 goats will eat grass for (1¹/₄ days) ∴ 8 cows and 12 goats eat grass for (1¹/₄ days)

260.

Grassin a field can completely feed 20 cows or 30 goats for a day. The same field is sufficient to feed 8 cows and 12 goats for1). $1\frac{1}{2}$ days2). $1\frac{1}{3}$ days3). $1\frac{1}{9}$days4).

Answer»

⇒ 20 cows or 30 goats can eat GRASS for 1 day from field

⇒ 30 goats will eat grass for 1 day

⇒ 1 goat will eat grass for 30 DAYS

⇒ 20 cow = 30 goats

⇒ 1 cow = (30/20)

⇒ 1 cow = 3/2

⇒ Let x day for 8 cow and 12 goats same field will be sufficient

⇒ 8 cow + 12 goats = 8 (3/2) + 12

⇒ 8 cow + 12 goats = 24 goats

⇒ 1 goat will eat grass for 30 days

⇒ 24 goats will eat grass for (30/24)

⇒ 24 goats will eat grass for (1¹/₄ days)

∴ 8 cows and 12 goats eat grass for (1¹/₄ days)

Discussion

261.	A can do a piece of work in 70 days and B is 40% more efficient than A. The number of days taken by B to do the same work is1). 40 days2). 60 days3). 50 days4). 45 days
Answer» it from previous YEAR SSC papers, option 3 is the right answer

Discussion

262.	A & B together finishes a work in 10 days. B & C together finishes same work in 18 days. A works 5 days on this work firstly then B worked for 10 days and the remaining work is done by C in 15 days. If C alone do this work then in how many days he will take to complete the work.1). 42 days2). 45 days3). 38 days4). 28 days
Answer» WORK DONE by A & B = 10 days Work done by A & B in one DAY = 1/10 work Work done by B & C = 18 days Work done by B & C in one day = 1/18 work Let C finishes the work in x days. ∴ Work done by C in one day = 1/x ? B + C = 1/18 C = 1/x ∴ B = 1/18 – 1/x ? A + B = 1/10 ∴ A = 1/10 – (1/18 – 1/x) Total work done = 1 ∴ A × (5 days) + B × (5 days) + C × (10 days) = 1 5 × (1/10) + 5 × (1/18) + 10 × (1/x) = 1 10/x = 1 – (5/10 + 5/18) ∴ x = 45 days. C will complete the work 45 days.

262.

A & B together finishes a work in 10 days. B & C together finishes same work in 18 days. A works 5 days on this work firstly then B worked for 10 days and the remaining work is done by C in 15 days. If C alone do this work then in how many days he will take to complete the work.1). 42 days2). 45 days3). 38 days4). 28 days

Answer»

WORK DONE by A & B = 10 days

Work done by A & B in one DAY = 1/10 work

Work done by B & C = 18 days

Work done by B & C in one day = 1/18 work

Let C finishes the work in x days.

∴ Work done by C in one day = 1/x

? B + C = 1/18

C = 1/x

∴ B = 1/18 – 1/x

? A + B = 1/10

∴ A = 1/10 – (1/18 – 1/x)

Total work done = 1

∴ A × (5 days) + B × (5 days) + C × (10 days) = 1

5 × (1/10) + 5 × (1/18) + 10 × (1/x) = 1

10/x = 1 – (5/10 + 5/18)

∴ x = 45 days.

C will complete the work 45 days.

Discussion

263.	P and Q can together do a work in 6 days. If P can do the work alone in 18 days, then P is:1). As efficient as Q2). Half as efficient as Q3). Twice as efficient as Q4). Thrice as efficient as Q
Answer» <P>P’s 1 DAY work = 1/18 (P + Q)’s 1 day work = 1/6 Q’s 1 day work = 1/6 – 1/18 = 1/9 Hence, Q can alone do the work in 9 days ∴ P is half as efficient as Q

263.

P and Q can together do a work in 6 days. If P can do the work alone in 18 days, then P is:1). As efficient as Q2). Half as efficient as Q3). Twice as efficient as Q4). Thrice as efficient as Q

Answer»

<P>P’s 1 DAY work = 1/18

(P + Q)’s 1 day work = 1/6

Q’s 1 day work = 1/6 – 1/18 = 1/9

Hence, Q can alone do the work in 9 days

∴ P is half as efficient as Q

Discussion

264.	A and B together can do a piece of work in 5 days and A alone can do it ih 8 days, B alone can do the same piece of work in1). $11\frac{1}{3}$ days2). $12\frac{3}{5}$ days3). $13\frac{1}{3}$ days4). $16\frac{4}{5}$ days
Answer» $13\frac{1}{3}$ DAYS is the BEST SUITED

Discussion

265.	Three taps A, B and C can fill a tank in 20, 45 and 36 hours respectively. If all the taps are opened together, then in how many hours will the tank be filled? 1). 62). 103). 124). 15
Answer» A can fill a tank in = 20 HOURS ∴ In 1 hour A can fill = 1/20 B can fill a tank in = 45 hours ∴ In 1 hour B can fill = 1/45 C can fill a tank in = 36 hours ∴ In 1 hour C can fill = 1/36 Let, they together can fill the tank in = x hours According to PROBLEM, $( \Rightarrow \frac{x}{{20}} + \frac{x}{{45}} + \frac{x}{{36}} = 1)$ $( \Rightarrow \frac{{9x + 4x + 5x}}{{180}} = 1)$ ⇒ 18x = 180 ⇒ x = 10 ∴ If all the taps are OPENED together the tank will be FILLED in = 10 hours

265.

Three taps A, B and C can fill a tank in 20, 45 and 36 hours respectively. If all the taps are opened together, then in how many hours will the tank be filled? 1). 62). 103). 124). 15

Answer»

A can fill a tank in = 20 HOURS

∴ In 1 hour A can fill = 1/20

B can fill a tank in = 45 hours

∴ In 1 hour B can fill = 1/45

C can fill a tank in = 36 hours

∴ In 1 hour C can fill = 1/36

Let, they together can fill the tank in = x hours

According to PROBLEM,

$( \Rightarrow \frac{x}{{20}} + \frac{x}{{45}} + \frac{x}{{36}} = 1)$

$( \Rightarrow \frac{{9x + 4x + 5x}}{{180}} = 1)$

⇒ 18x = 180

⇒ x = 10

∴ If all the taps are OPENED together the tank will be FILLED in = 10 hours

Discussion

266.	1). 24 hours2). \(17\frac{1}{7}{\rm{ \;hours}}\)3). 40 hours4). Can’t be determined
Answer» LET a and B be the NUMBER of hours required by Pascal and RASCAL to complete the job individually. ∴ According to the given conditions, 1/a + 1/b = 1/10- - - - - - (1) And, 2.5/a + 8.5/b = 1/2- - - - - - (2) On solving equations (1) and (2) SIMULTANEOUSLY, we get, ⇒ a = 120/7 and b = 24 ∴ Pascal can complete the whole work in 120/7 hours.

266.

1). 24 hours2). $17\frac{1}{7}{\rm{ \;hours}}$3). 40 hours4). Can’t be determined

Answer»

LET a and B be the NUMBER of hours required by Pascal and RASCAL to complete the job individually.

∴ According to the given conditions,

1/a + 1/b = 1/10- - - - - - (1)

And, 2.5/a + 8.5/b = 1/2- - - - - - (2)

On solving equations (1) and (2) SIMULTANEOUSLY, we get,

⇒ a = 120/7 and b = 24

∴ Pascal can complete the whole work in 120/7 hours.

Discussion

267.	1). Rs. 45002). Rs. 30003). Rs. 20004). Rs. 1500
Answer» ⇒ Work done by RAHUL in 8 DAYS = 8 × (1/16) = 1/2 ⇒ Work done by Ravi in 8 days = 8 × (1/24) = 1/3 It means, Rahul and Ravi done 1/2 and 1/3rd of work, respectively, in 8 days ⇒ Work done by kamlesh = {1 – (1/2 + 1/3)} = 1 – 5/6 = 1/6 ⇒ Rahul’s SHARE: Ravi’s share : Kamlesh's share = 1/2 : 1/3 = 3 : 2 ⇒ Kamlesh’s share = (1/6) × 9,000 = 1500 ∴ Kamlesh’s share is Rs. 1500

267.

1). Rs. 45002). Rs. 30003). Rs. 20004). Rs. 1500

Answer»

⇒ Work done by RAHUL in 8 DAYS = 8 × (1/16) = 1/2

⇒ Work done by Ravi in 8 days = 8 × (1/24) = 1/3

It means, Rahul and Ravi done 1/2 and 1/3rd of work, respectively, in 8 days

⇒ Work done by kamlesh = {1 – (1/2 + 1/3)} = 1 – 5/6 = 1/6

⇒ Rahul’s SHARE: Ravi’s share : Kamlesh's share = 1/2 : 1/3 = 3 : 2

⇒ Kamlesh’s share = (1/6) × 9,000 = 1500

∴ Kamlesh’s share is Rs. 1500

Discussion

268.	A man, a woman and a boy together finish a piece of work in 6 days . If a man and a women cando the work in 10 and 24 days respectively. The days taken by a boy to finish the work is1). 302). 353). 404). 45
Answer» ANSWER for this QUESTION is OPTION 3

Discussion

269.	A can do in one day three time the work done by B in one day. They together finish $\frac{2}{5}$ of the work in 9 days. The number of days by which B can do the work alone is :1). 90 days2). 120 days3). 100 days4). 30 days
Answer» OPTION 1 is the ANSWER

Discussion

270.	If A and B together can finish a piece of work in 20 days B and C in 10 days and C and A in 12 days, then A, B, C jointly can finish the same work in1). $4\frac{2}{7}$ days2). 30 days3). $8\frac{4}{7}$ days4). $\frac{7}{60}$ days
Answer» I THINK $8\frac{4}{7}$ DAYS is RIGHT

Discussion

271.	A, B and C can do a piece of work in 30, 20 and 10 days respectively. A is assisted by B on one day and by C on the next day. alternately. How long would the work take to finish ?1). $9\frac{3}{8}$ days2). $4\frac{8}{8}$ days3). $8\frac{4}{13}$ days4). $3\frac{9}{13}$ days
Answer» OPTION 1 is the RIGHT ANSWER

Discussion

272.	1). 122). 103). 94). 11
Answer» Time taken by P = 15 days Time taken by Q = 24 days Let Total work = LCM of 15 and 24 = 120 units Efficiency of P = 120/15 = 8 units/day Efficiency of Q = 120/24 = 5 units/day Total Efficiency of P and Q = 8 + 5 = 13 units/day Total work DONE by Q in 2 days = 5 × 2 = 10 units Now New Total work = 120 + 10 = 130 units ∴ Total time taken to complete the work = 130/13 = 10 days

272.

1). 122). 103). 94). 11

Answer»

Time taken by P = 15 days

Time taken by Q = 24 days

Let Total work = LCM of 15 and 24 = 120 units

Efficiency of P = 120/15 = 8 units/day

Efficiency of Q = 120/24 = 5 units/day

Total Efficiency of P and Q = 8 + 5 = 13 units/day

Total work DONE by Q in 2 days = 5 × 2 = 10 units

Now New Total work = 120 + 10 = 130 units

∴ Total time taken to complete the work = 130/13 = 10 days

Discussion

273.	1). 1202). 37.53). 454). 90
Answer» TAPS R, S and T can fill a tank in 90 min, 100 min and 180 min R’s one-min work = 1/90 S’s one-min work = 1/100 T’s one-min work = 1/180 R, S and T‘s one-min work = 1/90 + 1/100 + 1/180 = 2/75 Total TIME taken by R, S and T to fill the tank = 1/(2/75) = 37.5 min

273.

1). 1202). 37.53). 454). 90

Answer»

TAPS R, S and T can fill a tank in 90 min, 100 min and 180 min

R’s one-min work = 1/90

S’s one-min work = 1/100

T’s one-min work = 1/180

R, S and T‘s one-min work = 1/90 + 1/100 + 1/180 = 2/75

Total TIME taken by R, S and T to fill the tank = 1/(2/75) = 37.5 min

Discussion

274.	1). 20 hours2). 18 hours3). 16 hours4). 25 hours
Answer» Time taken by pipe A to FILL a tank = 36 HOURS ⇒ Part of the tank filled by pipe A in 1 hour = 1/36----(1) Time taken by pipe B to fill a tank = 45 hours ⇒ Part of the tank filled by pipe B in 1 hour = 1/45----(2) Adding equations 1 and 2, Part of the tank filled by pipe A and B both in 1 hour $(= \frac{1}{{36}} + \frac{1}{{45}} = \frac{{5 + 4}}{{180}} = \frac{9}{{180}} = \frac{1}{{20}})$ ∴ Time taken by pipe A and B both to fill the tank completely = 20 hours

274.

1). 20 hours2). 18 hours3). 16 hours4). 25 hours

Answer»

Time taken by pipe A to FILL a tank = 36 HOURS

⇒ Part of the tank filled by pipe A in 1 hour = 1/36----(1)

Time taken by pipe B to fill a tank = 45 hours

⇒ Part of the tank filled by pipe B in 1 hour = 1/45----(2)

Adding equations 1 and 2,

Part of the tank filled by pipe A and B both in 1 hour $(= \frac{1}{{36}} + \frac{1}{{45}} = \frac{{5 + 4}}{{180}} = \frac{9}{{180}} = \frac{1}{{20}})$

∴ Time taken by pipe A and B both to fill the tank completely = 20 hours

Discussion

275.	A and B can complete a piece of work in 30 days, B and C in 20 days, while C and A in 15 days If all of them work together, the time taken in completing the work will be1). 10 days2). 12 days3). $12\frac{2}{3}$ days4). $13\frac{1}{3}$ days
Answer» $13\frac{1}{3}$ DAYS

Discussion

276.	1). \(3\frac{2}{7}\) hours2). \(3\frac{3}{7}\) hours3). \(3\frac{1}{7}\) hours4). None of these
Answer» ? Time TAKEN by first pipe to fill the tank = 6 hours ∴ In one HOUR the First pipe can fill tank (by volume) = (1/6) ? Time taken by Second pipe to fill the tank = 8 hours ∴ In one hour the Second pipe can fill tank (by volume) = (1/8) ⇒ If operated together the two pipes can fill tank (by volume) in one hour = (1/6) + (1/8) = 14/48 = 7/24 ⇒ The Tank will be FILLED in time = 24/7 HRS $(3\frac{3}{7})$ hours

276.

1). $3\frac{2}{7}$ hours2). $3\frac{3}{7}$ hours3). $3\frac{1}{7}$ hours4). None of these

Answer»

? Time TAKEN by first pipe to fill the tank = 6 hours

∴ In one HOUR the First pipe can fill tank (by volume) = (1/6)

? Time taken by Second pipe to fill the tank = 8 hours

∴ In one hour the Second pipe can fill tank (by volume) = (1/8)

⇒ If operated together the two pipes can fill tank (by volume) in one hour = (1/6) + (1/8)

= 14/48

= 7/24

⇒ The Tank will be FILLED in time = 24/7 HRS $(3\frac{3}{7})$ hours

Discussion

277.	A work can be completed by P and Q in 12 days, Q and R in 15 days, R and P in 20 days. In how many days P alone can finish the work?1). 10 days2). 20 days3). 30 days4). 60 days
Answer» ANSWER for this QUESTION is OPTION 3

Discussion

278.	Varun alone can do a piece of work in 16 hours while Akash alone can do it in 18 hour. They together took Rs. 432 to do the same work. If with the help of Arun, they finish the piece of work in 4 hour, then how much money is paid to Arun?1). Rs. 1782). Rs. 1983). Rs. 2284). Rs. 200
Answer» VARUN alone can do a piece of work in 16 hours while Akash alone can do it in 18 hour If Varun and Akash work together then, In 1 hr they will complete $(= \left( {\frac{1}{{16}} + \frac{1}{{18}}} \right) = \;\frac{{9 + 8}}{{144}} = \frac{{17}}{{144}})$ of the work To complete the whole work they will take $(\frac{1}{{\frac{{17}}{{144}}}} = \;\frac{{144}}{{17}}\;hrs)$ They together took Rs. 432 to do the same work. If with the help of Arun, they FINISH the piece of work in 4 hour. For 144/17 hrs of work Varun and Akash are CHARGING Rs 432 For 4 hrs of work, tha amount Varun and Akash should charge $(= \;\;Rs.\;432\; \times \frac{{17}}{{144}} \times 4 = 204)$ So they should give the rest of the money to Arun. Arun will get (432 – 204) = Rs. 228

278.

Varun alone can do a piece of work in 16 hours while Akash alone can do it in 18 hour. They together took Rs. 432 to do the same work. If with the help of Arun, they finish the piece of work in 4 hour, then how much money is paid to Arun?1). Rs. 1782). Rs. 1983). Rs. 2284). Rs. 200

Answer»

VARUN alone can do a piece of work in 16 hours while Akash alone can do it in 18 hour

If Varun and Akash work together then,

In 1 hr they will complete $(= \left( {\frac{1}{{16}} + \frac{1}{{18}}} \right) = \;\frac{{9 + 8}}{{144}} = \frac{{17}}{{144}})$ of the work

To complete the whole work they will take $(\frac{1}{{\frac{{17}}{{144}}}} = \;\frac{{144}}{{17}}\;hrs)$

They together took Rs. 432 to do the same work. If with the help of Arun, they FINISH the piece of work in 4 hour.

For 144/17 hrs of work Varun and Akash are CHARGING Rs 432

For 4 hrs of work, tha amount Varun and Akash should charge $(= \;\;Rs.\;432\; \times \frac{{17}}{{144}} \times 4 = 204)$

So they should give the rest of the money to Arun.

Arun will get (432 – 204) = Rs. 228

Discussion

279.	24 men can repair a road in 50 days. If they are joined by 16 more men, then in how much time (in days) the road can be repaired?1). 282). 253). 324). 30
Answer» We KNOW that, (M1 × D1)/W1 = (M2 × D2)/W2 According to the question Since work is same in both the cases hence it is taken as 1 ⇒ (24 × 50)/1 = [(24 + 16) × D2]/1 ⇒ D2 = (24 × 50)/40 = 30 days ∴ the road can be repaired in 30 days

279.

24 men can repair a road in 50 days. If they are joined by 16 more men, then in how much time (in days) the road can be repaired?1). 282). 253). 324). 30

Answer»

We KNOW that,

(M1 × D1)/W1 = (M2 × D2)/W2

According to the question

Since work is same in both the cases hence it is taken as 1

⇒ (24 × 50)/1 = [(24 + 16) × D2]/1

⇒ D2 = (24 × 50)/40 = 30 days

∴ the road can be repaired in 30 days

Discussion

280.	Jack and Finn can finish a work together in 6 hours, while Finn alone can do it in 10 hours. What is the ratio of efficiencies of Jack and Finn?1). 1 : 22). 2 : 33). 3 : 44). 3 : 5
Answer» Let the efficiencies of Jack and Finn be M and N, respectively. We know, TIME to finish WORK is inversely PROPORTIONAL to efficiency. ⇒ 6 × (M + N) = 10 × N ⇒ 6M = 4N ⇒ M/N = 2/3 ∴ Ratio of efficiencies is 2 : 3.

280.

Jack and Finn can finish a work together in 6 hours, while Finn alone can do it in 10 hours. What is the ratio of efficiencies of Jack and Finn?1). 1 : 22). 2 : 33). 3 : 44). 3 : 5

Answer»

Let the efficiencies of Jack and Finn be M and N, respectively.

We know, TIME to finish WORK is inversely PROPORTIONAL to efficiency.

⇒ 6 × (M + N) = 10 × N

⇒ 6M = 4N

⇒ M/N = 2/3

∴ Ratio of efficiencies is 2 : 3.

Discussion

281.	1). 4 days2). 5 days3). 6 days4). 7 days
Answer» ⇒ (A + B)’s 8 days’ work = 1 ⇒ (A + B)’s 1 DAY’s work = 1/8…….. (1) ⇒ (B + C) 12 day? work = 12 ⇒ (B + C)’s 1 day’s work = 1/12……. (2) ⇒ (C + A) 8 day?s work = 1 ⇒ (C + A)’s 1 day’s work = 1/8........ (3) ⇒ Now we add the equation (1), (2) and (3) we have ⇒ 2(A + B + C)’s 1 day’s work = 1/8 + 1/12 + 1/8 = 1/3 ⇒ (A + B + C)’s 1 day’s work = 1/6 ∴ the work will be completed in 6 days

281.

1). 4 days2). 5 days3). 6 days4). 7 days

Answer»

⇒ (A + B)’s 8 days’ work = 1

⇒ (A + B)’s 1 DAY’s work = 1/8…….. (1)

⇒ (B + C) 12 day? work = 12

⇒ (B + C)’s 1 day’s work = 1/12……. (2)

⇒ (C + A) 8 day?s work = 1

⇒ (C + A)’s 1 day’s work = 1/8........ (3)

⇒ Now we add the equation (1), (2) and (3) we have

⇒ 2(A + B + C)’s 1 day’s work = 1/8 + 1/12 + 1/8 = 1/3

⇒ (A + B + C)’s 1 day’s work = 1/6

∴ the work will be completed in 6 days

Discussion

282.	P can complete a work in 12 days working 8 hours a day. Q can complete the same work in 8 days working 10 hours a day. If both P and Q work together, working 8 hours a day, in how many days can they complete the work?1). 60/112). 61/113). 71/114). 72/11
Answer» P can complete the work in (12 × 8)hrs. = 96 hrs. Q can complete the work in (8 × 10)hrs. = 80 hrs. P's 1 hour's work = 1/96 Q's 1 hour's work = 1/80 (P + Q)'s 1 hour's work ⇒ 1/96 + 1/80 = 11/480 So, both P and Q will finish the work in (480/11) hrs. Number of days of 8 hours each = (480/11 × 1/8) = 60/11 days

282.

P can complete a work in 12 days working 8 hours a day. Q can complete the same work in 8 days working 10 hours a day. If both P and Q work together, working 8 hours a day, in how many days can they complete the work?1). 60/112). 61/113). 71/114). 72/11

Answer»

P can complete the work in (12 × 8)hrs. = 96 hrs.

Q can complete the work in (8 × 10)hrs. = 80 hrs.

P's 1 hour's work = 1/96

Q's 1 hour's work = 1/80

(P + Q)'s 1 hour's work

⇒ 1/96 + 1/80 = 11/480

So, both P and Q will finish the work in (480/11) hrs.

Number of days of 8 hours each = (480/11 × 1/8) = 60/11 days

Discussion

283.	1). 402). 453). 604). 72
Answer» Let the EFFICIENCIES of P, Q, R and S be x, y, z and w. P and Q can FINISH a work together in 30 hours. Q, R and S can finish the same work in 20 hours. And when all FOUR of them work together, they finish the work in 15 hours. ⇒ x + y = 1/30 And, y + z + w = 1/20 And, x + y + z + w = 1/15 ⇒ x = 1/15 – 1/20 = 1/60 ⇒ y = 1/30 – x = 1/30 – 1/60 = 1/60 ∴ Q can finish work alone in 60 hours.

283.

1). 402). 453). 604). 72

Answer»

Let the EFFICIENCIES of P, Q, R and S be x, y, z and w.

P and Q can FINISH a work together in 30 hours. Q, R and S can finish the same work in 20 hours. And when all FOUR of them work together, they finish the work in 15 hours.

⇒ x + y = 1/30

And, y + z + w = 1/20

And, x + y + z + w = 1/15

⇒ x = 1/15 – 1/20 = 1/60

⇒ y = 1/30 – x = 1/30 – 1/60 = 1/60

∴ Q can finish work alone in 60 hours.

Discussion

284.	1). 10002). 5003). 6004). 1200
Answer» A pipe can fill the tank in = 120 hours ∴ In 1 hour pipe can fill = 1/120 Tank is actually FILLED in = 150 hours ∴ In 1 hour tank actually fills = 1/150 ∴ In 1 hour the leak empties, $( \RIGHTARROW \frac{1}{{120}} - \frac{1}{{150}})$ $( \Rightarrow \frac{{5 - 4}}{{600}})$ ⇒ 1/600 ∴ The leak can EMPTY the WHOLE tank in = 600 hours

284.

1). 10002). 5003). 6004). 1200

Answer»

A pipe can fill the tank in = 120 hours

∴ In 1 hour pipe can fill = 1/120

Tank is actually FILLED in = 150 hours

∴ In 1 hour tank actually fills = 1/150

∴ In 1 hour the leak empties,

$( \RIGHTARROW \frac{1}{{120}} - \frac{1}{{150}})$

$( \Rightarrow \frac{{5 - 4}}{{600}})$

⇒ 1/600

∴ The leak can EMPTY the WHOLE tank in = 600 hours

Discussion

285.	If A and B together can complete a piece of work in 15 days and B alone in 20 days, in how many days can A alone complete the work ?1). 60 days2). 45 days3). 40 days4). 30 days
Answer» OPTION 1 : SEEMS CORRECT

Discussion

286.	1). 3002). 4003). 5004). 250
Answer» Let, the tank holds = x litres In 24 hours the leak empties = x litres ∴ In 1 HOUR the leak empties = x/24 lit According to PROBLEM, ⇒ x = 50 × 12 - 12x/24 ⇒ x + x/2 = 600 ⇒ 1.5x = 600 ⇒ x = 400 ∴ The tank holds = 400 litres

286.

1). 3002). 4003). 5004). 250

Answer»

Let, the tank holds = x litres

In 24 hours the leak empties = x litres

∴ In 1 HOUR the leak empties = x/24 lit

According to PROBLEM,

⇒ x = 50 × 12 - 12x/24

⇒ x + x/2 = 600

⇒ 1.5x = 600

⇒ x = 400

∴ The tank holds = 400 litres

Discussion

287.	12 men finished 1/4 part of whole work in 6 days. Find the number of additional men required to complete the job in next 6 days.1). 362). 123). 184). 24
Answer» 12 men finished 1/4 part of whole work in 6 days, ⇒ 12 men finished whole work in 24 days, ⇒ Total work = 12 × 24 = 288 units, LET x ADDITIONAL men are required, REMAINING work = 288 × 3/4 = 216 units ⇒ To finish 216 units work in next 6 days, men required = 216/6 = 36 men ∴ Additional men required are 24.

287.

12 men finished 1/4 part of whole work in 6 days. Find the number of additional men required to complete the job in next 6 days.1). 362). 123). 184). 24

Answer»

12 men finished 1/4 part of whole work in 6 days,

⇒ 12 men finished whole work in 24 days,

⇒ Total work = 12 × 24 = 288 units,

LET x ADDITIONAL men are required,

REMAINING work = 288 × 3/4 = 216 units

⇒ To finish 216 units work in next 6 days, men required = 216/6 = 36 men

∴ Additional men required are 24.

Discussion

288.	A and B can do a piece of workin 36 days, B and C can do it in 60 days, A and C can do it in 45 days, C alone can do it in1). 90 days2). 180 days3). 120 days4). 150 days
Answer» I THINK OPTION 2 is the RIGHT ANSWER

Discussion

289.	1). 1/42). 1/53). 4/104). 5/14
Answer» A can COMPLETE 6/7^th of the task in 12 DAYS A can complete the entire task in 14 days A’s rate of work is 1/14 B is 1.5 times as efficient as A B’s rate = 1.5 × A’s rate B’s rate = 3/2 × 1/14 B’s rate = 3/28 Work done by B in 1 day = 3/28 Work done by B in 7 days = 21/28 Work left = 1 – 21/28 = 7/28 = 1/4 ∴ 1/4^th PART is left INCOMPLETE

289.

1). 1/42). 1/53). 4/104). 5/14

Answer»

A can COMPLETE 6/7^th of the task in 12 DAYS

A can complete the entire task in 14 days

A’s rate of work is 1/14

B is 1.5 times as efficient as A

B’s rate = 1.5 × A’s rate

B’s rate = 3/2 × 1/14

B’s rate = 3/28

Work done by B in 1 day = 3/28

Work done by B in 7 days = 21/28

Work left = 1 – 21/28 = 7/28 = 1/4

∴ 1/4^th PART is left INCOMPLETE

Discussion

290.	If 10 men can do a piece of work in 12 days, the time taken by 12 men to do the same piece of work will be1). 12 days2). 10 days3). 9 days4). 8 days
Answer» OPTION 2 is the RIGHT ANSWER

Discussion

291.	A group of 10 people can finish a certain work in 15 days. If a group of 5 people who are 30% more efficient are added to the group, how many days approximately will be saved?1). 12 days2). 3 days3). 9 days4). 6 days
Answer» Let the total amount of work be X Work done by one person in 15 days = X/10 Work done by one person in one day = X/150 A person who is 30% more efficient will be able to do 30% more work in one day. Work done by more efficient person in one day = (1 + 0.3) × (X/150) = 1.3X/150 Now in total there are 15 people in the group and HENCE we have 10 PERSONS who can finish X/150 work in one day and 5 who can finish 1.3X/150 in one day. Total work that can be FINISHED in one day = 10 × (X/150) + 5 × (1.3X/150) = 16.5X/150 ∴ Time taken to finish the work = 150/16.5 = 9.09 days = 9 days ∴ Days saved = 15 - 9 = 6 days

291.

A group of 10 people can finish a certain work in 15 days. If a group of 5 people who are 30% more efficient are added to the group, how many days approximately will be saved?1). 12 days2). 3 days3). 9 days4). 6 days

Answer»

Let the total amount of work be X

Work done by one person in 15 days = X/10

Work done by one person in one day = X/150

A person who is 30% more efficient will be able to do 30% more work in one day.

Work done by more efficient person in one day = (1 + 0.3) × (X/150) = 1.3X/150

Now in total there are 15 people in the group and HENCE we have 10 PERSONS who can finish X/150 work in one day and 5 who can finish 1.3X/150 in one day.

Total work that can be FINISHED in one day = 10 × (X/150) + 5 × (1.3X/150) = 16.5X/150

∴ Time taken to finish the work = 150/16.5 = 9.09 days = 9 days

∴ Days saved = 15 - 9 = 6 days

Discussion

292.	A and B can complete a piece of work in 12 and 18 days reapectlvely. A begins to do the work and they work alternatively one at a time for one day each. The whole work will be completed in1). $14\frac{1}{3}$ days2). $15\frac{2}{3}$ days3). $16\frac{1}{3}$ days4). $18\frac{2}{3}$ days
Answer» $14\frac{1}{3}$ days : OPTION 1 is the CORRECT answer

Discussion

293.	1). 182). 193). \(19\frac{1}{2}\)4). Data insufficient
Answer» (A + B)’s 2 day’s work $( = \frac{1}{{12}} + \frac{1}{{48}} = \frac{5}{{48}})$ Work done in 9 pairs of days $( = \LEFT\{ {\frac{5}{{48}} \times 9} \right\} = \frac{{15}}{{16}})$ Remaining work $( = \left\{ {1 - \frac{{15}}{{16}}} \right\} = \frac{1}{{16}})$ Work done by B on 19^th day $(= \frac{1}{{48}})$ Remaining work $( = \left\{ {\frac{1}{{16}} - \frac{1}{{48}}} \right\} = \frac{1}{{24}})$ Now, $(\frac{1}{{12}})$ work is done by A in 1 day. $(\frac{1}{{24}})$ work is done by A in $( = \left\{ {12 \times \frac{1}{{24}}} \right\} = \frac{1}{2})$ Total time TAKEN $( = 19\frac{1}{2})$

293.

1). 182). 193). $19\frac{1}{2}$4). Data insufficient

Answer»

(A + B)’s 2 day’s work $( = \frac{1}{{12}} + \frac{1}{{48}} = \frac{5}{{48}})$

Work done in 9 pairs of days $( = \LEFT\{ {\frac{5}{{48}} \times 9} \right\} = \frac{{15}}{{16}})$

Remaining work $( = \left\{ {1 - \frac{{15}}{{16}}} \right\} = \frac{1}{{16}})$

Work done by B on 19^th day $(= \frac{1}{{48}})$

Remaining work $( = \left\{ {\frac{1}{{16}} - \frac{1}{{48}}} \right\} = \frac{1}{{24}})$

Now, $(\frac{1}{{12}})$ work is done by A in 1 day.

$(\frac{1}{{24}})$ work is done by A in $( = \left\{ {12 \times \frac{1}{{24}}} \right\} = \frac{1}{2})$

Total time TAKEN $( = 19\frac{1}{2})$

Discussion

294.	A and B can do a piece of work in 12 days and 15 days respectively. They began to work together but A left after 4 days. In how many more days would B alone complete the remaining work ?1). $\frac{20}{3}$ days2). $\frac{25}{3}$ days3). 6 days4). 5 days
Answer» 6 DAYS : - OPTION 3

Discussion

295.	A can finish a work in 18 days and B can do the same work in 5 days. B worked for 10 days and left the Job. In how many days, A alone can finish the remaining work?1). 6 days2). $5\frac{1}{2}$ days3). 5 days4). 8 days
Answer» 6 days : - is CORRECT HENCE option 1

Discussion

296.	The average wage of 500 workers was found to be Rs. 200. Later on, it was discovered that the wages of two workers were misread as 180 and 20 instead of 80 and 220. The correct average wage is :1). Rs. 200.102). Rs. 200.203). Rs. 200.504). Rs. 201.00
Answer» OPTION option 2 is the CORRECT ANSWER

Discussion

297.	A man and a boy received Rs.800 as wages for 5 days for the work they did together. The man's efficiency in the work was three times that of the boy. What are the daily wages of the boy ?1). Rs. 762). Rs. 563). Rs. 444). Rs. 40
Answer» RIGHT ANSWER for this QUESTION is OPTION 4

Discussion

298.	P is thrice as good a workman as Q and therefore able to finish a job in 48 days less than Q. Working together, they can do it in :1). 18 days2). 24 days3). 30 days4). 12 days
Answer» 18 DAYS : - OPTION 1

Discussion

299.	The ratio of efficiencies of P, Q, R and S is 4 : 3 : 6 : 2. They all worked together for some time, except for Q who worked for only half the time as others. In total, they received an amount of Rs. 81000 for their work. What will be the share of S (in rupees)?1). 100002). 120003). 124004). 13600
Answer» <P>The ratio of efficiencies of P, Q, R and S is 4 : 3 : 6 : 2. They all WORKED together for some time, except for Q who worked for only half the time as others. So, the ratio of work done by them will be 4 : (3/2) : 6 : 2, which is 8 : 3 : 12 : 4. ∴ Share of S inRs. 81000 = [4/(8 + 3 + 12 + 4)] × Rs. 81000 = Rs. 12000

299.

The ratio of efficiencies of P, Q, R and S is 4 : 3 : 6 : 2. They all worked together for some time, except for Q who worked for only half the time as others. In total, they received an amount of Rs. 81000 for their work. What will be the share of S (in rupees)?1). 100002). 120003). 124004). 13600

Answer»

<P>The ratio of efficiencies of P, Q, R and S is 4 : 3 : 6 : 2. They all WORKED together for some time, except for Q who worked for only half the time as others.

So, the ratio of work done by them will be 4 : (3/2) : 6 : 2, which is 8 : 3 : 12 : 4.

∴ Share of S inRs. 81000 = [4/(8 + 3 + 12 + 4)] × Rs. 81000 = Rs. 12000

Discussion

300.	1). 62). 123). 94). 15
Answer» Let A can FINISH the task in ‘x’ days and B can finish the task in ‘y’ days ? C can finish the task in 36 days When they work together, part of work finished by all three in one day = 1/x + 1/y + 1/36 It is given that, A, B and C together can finish a task in 9 days 9(1/x + 1/y + 1/36) = 1 1/x + 1/y = 1/12 We can SAY that A and B can do 100% of the job working together in 12 days A and B can do 50% of the job working together in 6 days

300.

1). 62). 123). 94). 15

Answer»

Let A can FINISH the task in ‘x’ days and B can finish the task in ‘y’ days

? C can finish the task in 36 days

When they work together, part of work finished by all three in one day = 1/x + 1/y + 1/36

It is given that, A, B and C together can finish a task in 9 days

9(1/x + 1/y + 1/36) = 1

1/x + 1/y = 1/12

We can SAY that A and B can do 100% of the job working together in 12 days

A and B can do 50% of the job working together in 6 days

Discussion

Explore topic-wise InterviewSolutions in .

1). 62). 25/43). 124). 25/2

Two men undertook to do a Job for Rs. 1400. One of them can do it alone in 7 days, and the other in 8 days. With the assistance of a boy they together completed the work in 3 days. How much money will the boy get ?1). Rs. 3002). Rs. 3253). Rs. 2754). Rs. 250

A can do a work in 12 days and B in 24 days. If they work on it together for 4 days, then what fraction of work is left?1). 1/32). 1/23). 1/44). 1/5

x does $\frac{1}{4}$ of a job in 6 days. y completes rest of the job in 12 days. Then x and y could ccomplete the job together in1). 9 days2). $9\frac{3}{5}$ days3). $8\frac{1}{8}$ days4). $7\frac{1}{3}$ days

Two persons can complete a piece of work in 9 days. How many more persons are needed to complete double the work in 12 days ?1). 32). 23). 44). 1

A and B can do a piece of work in 8 days, B and C can do it in 24 days, while C and A can do it in $8\frac{4}{7}$ days. In how many days can C do it alone ?1). 60 days2). 40 days3). 30 days4). 10 days

A work can be completed by 28 women in 36 days. If 4 women leave after working for 18 days, then how many days will be needed to complete the remaining work?1). 242). 213). 274). 25

Suman can do a work in 3 days. Sumati can do the same work in 2 days. Both of them finish the work together and get Rs. 150. What is the share of Suman ?1). Rs. 302). Rs. 603). Rs. 704). Rs. 75

Aman and Ajay can build a wall in 9 days and 12 days respectively. In how many days can they finish the work if they work together?1). \(5\frac{1}{7}\)2). \(11\frac{1}{2}\)3). 24). 7

Grassin a field can completely feed 20 cows or 30 goats for a day. The same field is sufficient to feed 8 cows and 12 goats for1). \(1\frac{1}{2}\) days2). \(1\frac{1}{3}\) days3). \(1\frac{1}{9}\)days4).

A can do a piece of work in 70 days and B is 40% more efficient than A. The number of days taken by B to do the same work is1). 40 days2). 60 days3). 50 days4). 45 days

P and Q can together do a work in 6 days. If P can do the work alone in 18 days, then P is:1). As efficient as Q2). Half as efficient as Q3). Twice as efficient as Q4). Thrice as efficient as Q

A and B together can do a piece of work in 5 days and A alone can do it ih 8 days, B alone can do the same piece of work in1). $11\frac{1}{3}$ days2). $12\frac{3}{5}$ days3). $13\frac{1}{3}$ days4). $16\frac{4}{5}$ days

Three taps A, B and C can fill a tank in 20, 45 and 36 hours respectively. If all the taps are opened together, then in how many hours will the tank be filled? 1). 62). 103). 124). 15

1). 24 hours2). \(17\frac{1}{7}{\rm{ \;hours}}\)3). 40 hours4). Can’t be determined

1). Rs. 45002). Rs. 30003). Rs. 20004). Rs. 1500

A man, a woman and a boy together finish a piece of work in 6 days . If a man and a women cando the work in 10 and 24 days respectively. The days taken by a boy to finish the work is1). 302). 353). 404). 45

A can do in one day three time the work done by B in one day. They together finish $\frac{2}{5}$ of the work in 9 days. The number of days by which B can do the work alone is :1). 90 days2). 120 days3). 100 days4). 30 days

If A and B together can finish a piece of work in 20 days B and C in 10 days and C and A in 12 days, then A, B, C jointly can finish the same work in1). $4\frac{2}{7}$ days2). 30 days3). $8\frac{4}{7}$ days4). $\frac{7}{60}$ days

A, B and C can do a piece of work in 30, 20 and 10 days respectively. A is assisted by B on one day and by C on the next day. alternately. How long would the work take to finish ?1). $9\frac{3}{8}$ days2). $4\frac{8}{8}$ days3). $8\frac{4}{13}$ days4). $3\frac{9}{13}$ days

1). 122). 103). 94). 11

1). 1202). 37.53). 454). 90

1). 20 hours2). 18 hours3). 16 hours4). 25 hours

A and B can complete a piece of work in 30 days, B and C in 20 days, while C and A in 15 days If all of them work together, the time taken in completing the work will be1). 10 days2). 12 days3). $12\frac{2}{3}$ days4). $13\frac{1}{3}$ days

1). \(3\frac{2}{7}\) hours2). \(3\frac{3}{7}\) hours3). \(3\frac{1}{7}\) hours4). None of these

A work can be completed by P and Q in 12 days, Q and R in 15 days, R and P in 20 days. In how many days P alone can finish the work?1). 10 days2). 20 days3). 30 days4). 60 days

Varun alone can do a piece of work in 16 hours while Akash alone can do it in 18 hour. They together took Rs. 432 to do the same work. If with the help of Arun, they finish the piece of work in 4 hour, then how much money is paid to Arun?1). Rs. 1782). Rs. 1983). Rs. 2284). Rs. 200

24 men can repair a road in 50 days. If they are joined by 16 more men, then in how much time (in days) the road can be repaired?1). 282). 253). 324). 30

Jack and Finn can finish a work together in 6 hours, while Finn alone can do it in 10 hours. What is the ratio of efficiencies of Jack and Finn?1). 1 : 22). 2 : 33). 3 : 44). 3 : 5

1). 4 days2). 5 days3). 6 days4). 7 days

P can complete a work in 12 days working 8 hours a day. Q can complete the same work in 8 days working 10 hours a day. If both P and Q work together, working 8 hours a day, in how many days can they complete the work?1). 60/112). 61/113). 71/114). 72/11

1). 402). 453). 604). 72

1). 10002). 5003). 6004). 1200

If A and B together can complete a piece of work in 15 days and B alone in 20 days, in how many days can A alone complete the work ?1). 60 days2). 45 days3). 40 days4). 30 days

1). 3002). 4003). 5004). 250

12 men finished 1/4 part of whole work in 6 days. Find the number of additional men required to complete the job in next 6 days.1). 362). 123). 184). 24

A and B can do a piece of workin 36 days, B and C can do it in 60 days, A and C can do it in 45 days, C alone can do it in1). 90 days2). 180 days3). 120 days4). 150 days

1). 1/42). 1/53). 4/104). 5/14

If 10 men can do a piece of work in 12 days, the time taken by 12 men to do the same piece of work will be1). 12 days2). 10 days3). 9 days4). 8 days

A group of 10 people can finish a certain work in 15 days. If a group of 5 people who are 30% more efficient are added to the group, how many days approximately will be saved?1). 12 days2). 3 days3). 9 days4). 6 days

A and B can complete a piece of work in 12 and 18 days reapectlvely. A begins to do the work and they work alternatively one at a time for one day each. The whole work will be completed in1). $14\frac{1}{3}$ days2). $15\frac{2}{3}$ days3). $16\frac{1}{3}$ days4). $18\frac{2}{3}$ days

1). 182). 193). \(19\frac{1}{2}\)4). Data insufficient

A and B can do a piece of work in 12 days and 15 days respectively. They began to work together but A left after 4 days. In how many more days would B alone complete the remaining work ?1). $\frac{20}{3}$ days2). $\frac{25}{3}$ days3). 6 days4). 5 days

A can finish a work in 18 days and B can do the same work in 5 days. B worked for 10 days and left the Job. In how many days, A alone can finish the remaining work?1). 6 days2). $5\frac{1}{2}$ days3). 5 days4). 8 days

The average wage of 500 workers was found to be Rs. 200. Later on, it was discovered that the wages of two workers were misread as 180 and 20 instead of 80 and 220. The correct average wage is :1). Rs. 200.102). Rs. 200.203). Rs. 200.504). Rs. 201.00

A man and a boy received Rs.800 as wages for 5 days for the work they did together. The man's efficiency in the work was three times that of the boy. What are the daily wages of the boy ?1). Rs. 762). Rs. 563). Rs. 444). Rs. 40

P is thrice as good a workman as Q and therefore able to finish a job in 48 days less than Q. Working together, they can do it in :1). 18 days2). 24 days3). 30 days4). 12 days

The ratio of efficiencies of P, Q, R and S is 4 : 3 : 6 : 2. They all worked together for some time, except for Q who worked for only half the time as others. In total, they received an amount of Rs. 81000 for their work. What will be the share of S (in rupees)?1). 100002). 120003). 124004). 13600

1). 62). 123). 94). 15