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InterviewSolution
This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your knowledge and support exam preparation. Choose a topic below to get started.
| 201. |
A's 2 day's work is equal to B's 3 day's work. If A can complete the work in 8 days then to complete the work B will take1). 14 days2). 12 days3). 15 days4). 16 days |
| Answer» RIGHT ANSWER for this QUESTION is OPTION 2 | |
| 202. |
A and B working separately can so a 15 days respectively. If they work on alternate days begining with A , in how many days will the work be completed ?1). 18 days2). 13 days3). 12 days4). 6 days |
| Answer» | |
| 203. |
A can do a piece of work in 6 days and B can do it in 4 days separately. How many days would it take for both A and B to finish the same work together?1). 12/72). 12/153). 24/104). 11/5 |
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Answer» Given that, A can do a task in 6 days. ∴ 1 DAY’s work by A = 1/6 Also, B can do it in 4 days ∴ 1 day’s work by B = 1/4 1 day’s work by both A and B together = $(\frac{1}{6}\; + \;\frac{1}{4}\; = \;\frac{{2\; + \;3}}{{12}}\; = \;\frac{5}{{12}})$ To do the whole work, time taken by A and B together = $(\frac{1}{{\frac{5}{{12}}}}\; = \;\frac{{12}}{5}\; = \;\frac{{24}}{{10}})$ |
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| 204. |
A woman works continuously for 7 days in the kitchen and refuses to work on the 8th day when her husband takes over. If she starts her work on a Sunday, the 11th time she rests will be on which day of the week?1). Wednesday2). Tuesday3). Monday4). Friday |
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Answer» Total days = WORKING days + REST days Given: rest days = 11 ? Working days = (rest days) × 7 ∴ Total days = 11 × 7 + 11 = 88 ? 1st day = Sunday so we have to find the day on 88th day: So, 88/7 remainder = 4 Now we just have to find the day on 4th day i.e. Sun + MON + Tue + Wed So When She will take rest 11th time, the day is Wednesday. |
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| 205. |
A certain number of men can do a piece of work in 40 days. If there were 45 men more the work could have been finished in 25 days. Find the original number of men employed in the work.1). 702). 853). 654). 75 |
| Answer» | |
| 206. |
A and B can separately do a piece of work in 8 and 12 days respectively. How much time will it take to finish the whole work if they work alternatively starting by A?1). \(4\frac{4}{5}\) days2). \(9\frac{2}{5}\) days3). \(4\frac{3}{5}\) days4). 9.5 days |
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Answer» Time taken by A = 8 days Time taken by B = 12 days Let Total work = LCM of 8 and 12 = 24 units ⇒ Efficiency of A = 24/8 = 3 units/day ⇒ Efficiency of B = 24/12 = 2 units/day ⇒ Efficiency of A and B together = 3 + 2 = 5 units/2 days By working alternatively,they would COMPLETE 20 units of work in 8 days. Remaining work = 24-20 = 4 units of these 4 units of work,first 3 units would be completed by A(as he STARTED the work) and 1 unit by B. time taken = 1+1/2 = 1.5 days ∴ Total time taken to complete the work = 9.5 days |
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| 207. |
A alone can complete a work in 18 days and B alone in 15 days. B alone worked at it for 10 days and then left the work. In how many more days, will A alone complete the remaining work ?1). 5 days2). $5\frac{1}{2}$ days3). 6 days4). 8 days |
| Answer» RIGHT ANSWER for this QUESTION is 6 DAYS | |
| 208. |
1). 1 hour 15 minutes2). 1 hour 20 minutes3). 1 hour 12 minutes4). 2 hour 24 minutes |
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Answer» <P>⇒ Part filled by P ALONE in 1 HOURS = 1/6 ⇒ Part filled by Q alone in 1 hours = 1/4 ⇒ Part filled by (P + Q) in 1 hours = (1/6 + 1/4) = 5/12 ∴ Both the taps together will FILL the tank in = 12/5 hours = 144 minute = 2 hours 24 minute |
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| 209. |
Two pipes can fill a tank in 12 hours and 24 hours respectively. The pipes are opened simultaneously and it is found that due to leakage in the tank, it took 2 hours more to fill the tank. When the tank is completely full, in what time will the leak empty it?1). 34 hours2). 36 hours3). 38 hours4). 40 hours |
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Answer» Let the leak empty the TANK in h hours. ∴ In 1 hr, it EMPTIES 1/h part. Given, TWO pipes can fill a tank in 12 hours and 24 hours respectively 1 hr, they can fill 1/12 and 1/24 part respectively. Thus, working together, in 1 hr part of tank they can fill = 1/12 + 1/24 = 1/8 ∴ They can fill the tank in 8 hours. Now due to the leak it TOOK 2 hours more. Thus, the tank was filled in 10 hours. In 1hr, part of tank filled = 1/10 ⇒ 1/8 – 1/h = 1/10 ⇒ 1/8 – 1/10 = 1/h ⇒ h = 40 hours |
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| 210. |
Three men can complete a piece of work in 6 days. Two days after they started the work. 3 more men Joined them. How many days will they take to complete the remaining work ?1). 1 days2). 2 days3). 3 days4). 4 days |
| Answer» HELLO, 2 DAYS is CORRECT | |
| 211. |
Robin can do a work alone in 9 days. Amit can do the same work alone in 6 days. Both of them finish the work together and they get a total Rs. 2500. What is the share (in Rs.) of Robin?1). 17002). 12003). 15004). 1000 |
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Answer» Amit’s 1 day work = 1/6 When they work together, they received Rs. 2500 ? RATIO of wages = Ratio of work efficiencies ⇒ Robin’s share? Amit’s share = (1/9) ? (1/6) = 6 ? 9 = 2 ? 3 Sum of ratios = 2 + 3 = 5 ∴ Robin’s share = 2/5 × 2500 = Rs. 1000 |
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| 212. |
Pipes A and B can fill a tank in 5 hours and 20 hours respectively. If both pipes are opened then, how much time (in hours) it will take to fill the tank?1). 4.52). 33). 3.54). 4 |
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Answer» Pipe A can FILL the tank in 5 hours. ⇒ Pipe A’s 1 - hour WORK = 1/5 Pipe B can fill the tank in 20 hours. ⇒ Pipe B’s 1 - hour work = 1/20 When they work TOGETHER, the work will complete in, (A + B) = (1/5 + 1/20) = (4 + 1)/20 = 5/20 = 1/4 (A + B) can complete the whole work in 4 days |
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| 213. |
If 80 tigers kill 80 goats in 80 days, then 8 tigers would kill 8 goats in how many days?1). 8 days2). 3 days3). 80 days4). 100 days |
| Answer» | |
| 214. |
1). 302). 243). 184). 15 |
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Answer» A can do 1 work in $(\left\{ {\frac{5}{4} \times 24} \right\} = 30)$ LET, B can do the work in x days. Work remaining $(= \left\{ {1 - \frac{4}{5}} \right\} = \frac{1}{5})$ 1/5 of the work was DONE by A and B in 2 days. $(\frac{2}{{30}} + \frac{2}{x} = \frac{1}{5})$ $(\frac{2}{x} = \frac{1}{5} - \frac{2}{{30}} = \frac{1}{5} - \frac{1}{{15}} = \frac{2}{{15}})$ x = 15 |
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| 215. |
1). 12 hours2). 14 hours3). 16 hours4). 20 hours |
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Answer» Time TAKEN by pipe 1 to FILL = 4 HOURS Time taken by pipe 2 to empty = 5 hours Let capacity of cistern = LCM (4 and 5) = 20 units Efficiency of pipe 1 = 20/4 = 5 units/hour Efficiency of pipe 2 = 20/5 = –4 units/hour Total Efficiency of pipe 1 and pipe 2 together = 5 – 4 = 1 unit/hour ⇒Total time taken to fill the cistern = 20/1= 20 hours |
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| 216. |
A and B alone can complete work in 9 days and18 days respectively. They worked together; however 3 days before the completion of the work A left. In how many days was the work completed ?1). 13 days2). 8 days3). 6 days4). 5 days |
| Answer» 8 DAYS : option 2 is the correct ANSWER | |
| 217. |
A daily-wage labourer was engaged for a certain number of days for Rs. 5,750; but being absent on some of those days he was paid only Rs. 5,000. What was his maximum possible daily wage ?1). Rs. 1252). Rs. 2503). Rs. 3754). Rs. 500 |
| Answer» OPTION 2 is the RIGHT ANSWER | |
| 218. |
Work done by ( x + 4) men in (x + 5) days is equal to the work done by (x - 5) men in ( x + 20) days. Then the value of x is1). 202). 253). 304). 15 |
| Answer» RIGHT ANSWER for this QUESTION is OPTION 1 | |
| 219. |
3 girls can do a piece of work in 8 days, 3 boys can do the same piece of work in 9 days, 7 men do the same piece of work in 3 days and 6 women can do the same piece of work in 4 days. Who is the most efficient?1). Boys2). Girls3). Women4). Men |
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Answer» Based on given data, Work DONE by 3 girls in 1 day = 1/8 Work done by 3 boys in 1 day = 1/9 Work done by 7 men in 1 day = 1/3 Work done by 6 women in 1 day = 1/4 ASSUMING all girls are equally efficient, Work done by 1 girl in 1 day = 1/3 × 1/8 = 1/24---(1) Assuming all boys are equally efficient, Work done by 1 BOY in 1 day = 1/3 × 1/9 = 1/27---(2) Assuming all men are equally efficient, Work done by 1 man in 1 day = 1/7 × 1/3 = 1/21---(3) Assuming all women are equally efficient, Work done by 1 woman in 1 day = 1/6 × 1/4 = 1/24---(4) From 1,2,3,4, 1/27 < 1/24 < 1/21 Thus the least efficiency is 1/27 and the GREATEST efficiency is 1/21. Thus, men are the most efficient. |
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| 220. |
A, B and C can do a job working alone in 50, 75 and 20 days respectively. They all work together for 4 days, then C quits. How many days will A and B take to finish the rest of the job?1). 202). 303). 184). 24 |
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Answer» Suppose unit work = 300 units (LCM of 50, 75 & 20) ∴ Work done by A in one day = 300/50 = 6 Work done by B in one day = 300/75 = 4 Work done by C in one day = 300/20 = 15 ∴ Work done by (A + B + C) in 4 days = 4 × (6 + 4 + 15) = 100 C quits after 4 days. ∴ Time taken by A and B together to complete 200 units = 200/(6 + 4) = 20 days |
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| 221. |
Smita can finish a work in 12 days and Sam can finish the same work in 9 days.After working together for 4 days they both leave the job. What is the fraction of unfinished work?1). 1/22). 7/93). 2/94). 1/4 |
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Answer» WORK DONE by Smita in one day = 1/12 Work done by Sam in one day = 1/9 Work done by Smita and Sam TOGETHER in one day = (1/12) + (1/9) = 7/36 Work done by Smita and Sam together in 4 days = 4 × 7/36 = 7/9 The fraction of unfinished work = 1 – 7/9 = 2/9 ∴ The fraction of unfinished work = 2/9 |
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| 222. |
A takes 10 days less than the time taken by B to finish a piece of work. If both A and B can do it in 12 days, then the time taken by B alone to finish the work is1). 30 days2). 27 days3). 20 days4). 25 days |
| Answer» OPTION 1 : SEEMS CORRECT | |
| 223. |
1). 182). 213). 194). 25 |
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Answer» Let, Initial number of MEN EMPLOYED = y Working HOURS needed by y men to complete the work = 100 × 6 = 600 [? They can complete the work in 100 days working 6 hours a day] Before strike they WORKED for = 60 × 6 =360 working hours According to the question, No. of men employed after strike = y + 3 No. of days worked after strike=100 - (10 + 60) = 30 [? 60 days worked before the strike and 10 days strike] No. of hours worked per day after strike = 6 + 1 = 7 ⇒ y × (600 - 360) = (y + 3) × 30 × 7 ⇒ 240y = 210y + 630 ⇒ 30y = 630 ⇒ y = 21 ∴ The initial number of men Ram employed = 21 |
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| 224. |
A cistern can be filled by two pipes in 10 and 12 min respectively. Both the pipes are opened together for a certain time but, due to defects, only 1/6th of full quantity of water flows through the former and 2/5th of the latter. The defects are detected and rectified. The cistern is filled in 3 min from that moment. How long was it before the detects were rectified?1). 8 min2). 8.5 min3). 9 min4). 10 min |
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Answer» Pipe A can fill the tank in 10 MIN. Pipe B can fill the tank in 12 min. Total units to be filled in the cistern = LCM of (10, 12) = 60 ⇒ Pipe A can fill 6 units of WATER in 1 min. ⇒ Defected Pipe A can fill (6 × 1/6) = 1 UNIT of water in 1 min. ⇒ Pipe B can fill 5 units of water in 1 min. ⇒ Defected Pipe B can fill (5 × 2/5) = 2 units of water in 1 min. Given that, last 3 min, both the pipes used were rectified ⇒ in last 3 min (6 + 5) × 3 = 33 units of water were filled in the tank. ⇒ (60 - 33) = 27 units of water were filled with defected pipes. Both Defected pipes can fill 3 units of water in 1 min. ⇒ Defected pipes can fill 27 units of water in (27/3) = 9 min. ∴ After 9 minutes the defects were rectified. |
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| 225. |
A pipe can fill a tank in 14 hours. Due to the leak in its bottom, the tank is filled in 16 hours. If the tank is full, then that leak can empty the tank in how many hours?1). 1122). 1203). 1084). 110 |
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Answer» PART of tank filled by the pipe in ONE hour = 1/14 Part of tank filled by the pipe with a leak in its bottom in one hour = 1/16 Part of tank the leak can empty the tank in one hour = (1/14) – (1/16) = 1/112 ∴ Time taken by the leak to empty the tank = 1/(1/112) = 112 days |
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| 226. |
Two pipes, A and B can fill a tank in 16 and 20 hours respectively. If both are opened together and at the end of 4 hours pipe A is closed, How long will the pipe B take to fill the remaining part of the tank?1). 11 hours2). 13 hours3). 16 hours4). 9 hours |
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Answer» Given, A and B can FILL a tank in 16 and 20 HOURS respectively In 1 hr, A can fill 1/16 of the tank. B can fill 1/20 of the tank. Together, PART of the tank filled by them in 1 hr, = 1/16 + 1/20 = 9/80 Given, they are opened for 4 hours together and then A is closed. Thus part of tank filled in 4 hr $(= 4 \TIMES \frac{9}{{80}} = \frac{9}{{20}})$ Part of tank remaining = 1 – 9/20 = 11/20 ∴ Pipe B will fill the rest of the tank in time $(= \frac{{\frac{{11}}{{20}}}}{{\frac{1}{{20}}}} = 11\;hours)$ |
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| 227. |
A can do a work in 21 days. B is 40% more efficient than A. The number of days required for B to finish the same work alone is1). 10 days2). 12 days3). 15 days4). 18 days |
| Answer» | |
| 228. |
1). 72). 3.53). 54). 7.5 |
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Answer» Time TAKEN by 15 persons to do a job = 30 DAYS ⇒ Time taken by 1 person to do a job = 30 × 15 = 450 days ⇒ Time taken by 1 person with twice the efficiency = 450/2 = 225 days ⇒ Time taken by 30 persons with twice the efficiency = 225/30 = 7.5 days ∴ Time taken by 30 persons with twice the efficiency = 7.5 days |
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| 229. |
A, B and C can complete a piece of work in 12, 24 and 36 days respectively. In how many days will they together complete the same work ?1). $5\frac{6}{11}$ days2). 4 days3). $6\frac{6}{11}$ days4). 6 days |
| Answer» | |
| 230. |
8 men can do a work in 12 days. After 6 days of work, 4 more men were engaged to finish the work. in how many days would the remaining work be completed ?1). 22). 33). 44). 5 |
| Answer» 4 is the correct ANSWER as per the SSC answer key | |
| 231. |
Work done by 1 man is equal to the work done by 4 children and work done by 1 woman is equal to the work done by 2 children. 2 men, 2 women and 1 child can complete work together in 8 days. In how many days 4 men, 4 women and 2 children can complete the work?1). 2 days2). 6 days3). 4 days4). 7 days |
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Answer» Let work done by 1 man, 1 woman and 1 CHILD in one DAY be m, w, c respectively and D be the days required to complete the work m = 4c, w = 2c ⇒ (2M + 2w + c) × 8 = (4M + 4w + 2c) × D ⇒ (8c + 4c + c) × 8 = (16c + 8c + 2c) ×D ⇒ 13 × 8 = 26 × D ∴ D = 4 days |
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| 232. |
A can do $\frac{1}{6}$ of a work in 5 days and B can do $\frac{2}{5}$ of the work in 8 days, in how many days, can both A and B together do the work ?1). 12 days2). 13 days3). 15 days4). 20 days |
| Answer» CORRECT ANSWER is: 12 DAYS | |
| 233. |
A and B can do a work in 18 and 24 days respectively . They worked together for 8 days and then A left. The remaining work was finished by B in :1). 5 days2). $5\frac{1}{3}$ days3). 8 days4). 10 days |
| Answer» OPTION 2 : SEEMS CORRECT | |
| 234. |
Ram and Shyam together can finish a job in 8 days. Ram can finish the same job on his own in 12 days. How long will Shyam alone take to finish that work?1). 16 days2). 20 days3). 24 days4). 30 days |
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Answer» RAM can COMPLETE the work in 12 days Ram’s one-day work = 1/12 Let Shyam’s one-day work = 1/x Total time taken by Ram and Shyam to complete the work = 8 Ram and Shyam ‘s one-day work = 1/8 1/12 + 1/x = 1/8 ⇒ x = 24 Shyam can complete the work in 24 days |
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| 235. |
1). 2.5 days2). 4 days3). 5 days4). 1.5 days |
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Answer» The part of work done by A in 1 DAY = 1/10 The part of work done by B in 1 day = 1/15 Let B work for X days after A left the work. According to the QUESTION, 5(1/10 + 1/15) + x/15 = 1 ⇒ 5(3 + 2)/30 + x/15 = 1 ⇒ 5/6 + x/15 = 1 ⇒ x/15 = 1 - 5/6 ⇒ x/15 = 1/6 ⇒ x = 15/6 = 5/2 ⇒ x = 2.5 days |
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| 236. |
A does 50% of a work in 12 days. He then calls in B and they together finish the remaining work in 8 days. How long B alone would take to complete the whole work?1). 12 days2). 24 days3). 36 days4). 48 days |
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Answer» A does 50% of a WORK in 12 days. So, the part of work DONE A in 1 day = (1/2)/12 = 1/24 Remaining part of work = 1 – ½ = ½ The part of work done by A in 8 days = 8 × (1/24) = 1/3 So, B does (1/2) – (1/3) = 1/6 part of the work in 8 days. So, the part of work done by B in 1 day = (1/6)/8 = 1/48 ∴ B would ALONE COMPLETE the work in 48 days. |
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| 237. |
A company employed 200 workers to complete a certain work in 150 days. If only one- fourth of the work has been done in 50 days, then in order to complete the whole work in time, the number of additional workers to be employed was1). 1002). 3003). 6004). 200 |
| Answer» | |
| 238. |
C is 5 times as productive as B. A takes 60 days to complete a task. If A, B and C work together they can complete the task in 12 days. In how many days can B complete the task if he worked alone?1). 182). 273). 904). 72 |
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Answer» Let the total work = 60 (LCM of 60 & 12) ⇒ Efficiency of A = 60/60 = 1 ⇒ Efficiency of (A + B + C) = 60/12 = 5 Since C is 5 times as productive as B, efficiency of C will be 5 times of the efficiency of B. Let efficiency of B be n then efficiency of C will be 5N, ⇒ 1 + n + 5n = 5 ⇒ 6n = 4 ⇒ n = 2/3 ⇒ Efficiency of B = 2/3 Time taken by B alone to COMPLETE the task = 60/(2/3) = 90 days |
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| 239. |
If 10 men or 20 boys can make 260 mats in 20 days, then how many mats will be made by 8 men and 4 boys in 20 days?1). 2602). 2403). 2804). 520 |
| Answer» RIGHT ANSWER for this QUESTION is 260 | |
| 240. |
A and B together can diga trench in 12 days, which A alone can dig in 28 days; B alone can dig it in1). 20 days2). 21 days3). 22 days4). 23 days |
| Answer» OPTION 2 : 21 DAYS is CORRECT | |
| 241. |
A garrison has provisions for few days. After 15 days,1/4 of people left and it was found that the provisions would last for as long as before. How long was that?1). 262). 453). 604). 80 |
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Answer» Let the food EATEN by 1 man in 1 day = x, TOTAL men = y Let the GARRISON had provisions for z days Then total quantity of food = xyz Amount of food eaten by y men in 15 days = 15xy Remaining food = xyz - 15xy = xy(z - 15) After 15 days, total men = 3y/4 Food consumed by 3y/4 men in 1 day = 3xy/4 Time TAKEN for 3y/4 men to complete xy(z - 15) food = xy(z−15)/(3xy/4) = 4(z−15)/3 Given that number of days remain the same ⇒ 4(z−15)/3 = z ⇒ z = 60 |
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| 242. |
A certain number of men complete a piece of work in 60 days.If there were 8 men more, the work could be finished in 10 days less. The number of men originally was1). 302). 403). 324). 36 |
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Answer» This question was asked some where in previous YEAR PAPERS of ssc, and CORRECT answer was 40 |
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| 243. |
Sarita, Mamta and Rashmi can knit a sweater in 15, 12 and 20 days respectively. Doing that work together they get an amount of Rs. 8400. What is the share of Mamta in that amount?1). Rs. 25202). Rs. 33503). Rs. 34004). Rs. 3500 |
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Answer» PER DAY WORK of Sarita, MAMTA and Rashmi is 1/15, 1/12 and 1/20. ? their shares will PROPORTIONAL to their per day work. Share of Mamta = [1/12/ (1/15 + 1/12 + 1/20)] × 8400 = (5/12) × 8400 = 3500 |
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| 244. |
If 12 men or 24 boys can do a work in 66 days, the number of days in which 15 menand 6 boys can do it is1). 442). 333). 554). 66 |
| Answer» OPTION 1 : SEEMS CORRECT | |
| 245. |
A and B can do a piece of work in 10 days. B and C in 15 days and C and A in 20 days. C alone can do the work in:1). 60 days2). 120 days3). 80 days4). 30 days |
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Answer» Let’s assume that, while working alone, A, B and C can individually finish the WORK in a, b and c days respectively. ∴ Part of work FINISHED by A in one DAY = 1/a ∴ Part of work finished by B in one day = 1/b ∴ Part of work finished by C in one day = 1/c A and B can do a piece of work in 10 days. ∴ Part of work finished by A and B in one day $(= \frac{1}{{\rm{a}}} + \frac{1}{{\rm{b}}} = \frac{1}{{10}})$ -----(i) B and C can do a piece of work in 15 days. ∴ Part of work finished by B and C in one day $(= \frac{1}{{\rm{b}}} + \frac{1}{{\rm{c}}} = \frac{1}{{15}})$ -----(ii) C and A can do a piece of work in 20 days. ∴ Part of work finished by C and A in one day $(= \frac{1}{{\rm{c}}} + \frac{1}{{\rm{a}}} = \frac{1}{{20}})$ -----(iii) Adding equation (i), (ii) and (iii), we get: $(2{\rm{\;}}\left( {\frac{1}{{\rm{a}}} + \frac{1}{{\rm{b}}} + \frac{1}{{\rm{c}}}} \right) = \frac{1}{{10}} + \frac{1}{{15}} + \frac{1}{{20}} = \frac{{13}}{{60}})$ $(\Rightarrow {\rm{\;}}\left( {\frac{1}{{\rm{a}}} + \frac{1}{{\rm{b}}} + \frac{1}{{\rm{c}}}} \right) = \frac{{13}}{{120}})$ -----(iv) Subtracting equation (i) from equation (iv): $(\frac{1}{{\rm{c}}} = \frac{{13}}{{120}} - \frac{1}{{10}} = \frac{{13 - 12}}{{120}} = \frac{1}{{120}})$ ∴ To finish the entire work C takes 120 days. |
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| 246. |
A and B can complete a piece of work in 8 days, B and C can do it in 12 days, C and A can do it in 8 days. A, B and C together can complete it in1). 4 days2). 5 days3). 6 days4). 7 days |
| Answer» OPTION option 3 is the CORRECT ANSWER | |
| 247. |
A does half as much work as B is one sixth of the time. If together they take 10 days to complete a work, how much time shall A alone take to do it?1). 70 days2). 30 days3). 14 days4). 50 days |
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Answer» Given, ⇒ A × 1/6 = B × 1/2 ⇒ A = 3B ⇒ $(\frac{A}{B} = \frac{3}{1})$ ∴ A’s efficiency = 3 unit / day. & B’s efficiency = 1 unit / day. According to Qs. (A + B) Complete in 10 day ∴ TOTAL Work = (3 + 1) × 10 = 4 × 10 = 40 ∴ Time taken by $(A = \frac{{40}}{{13}})$ = 13.33 DAYS = 14 Days. |
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| 248. |
If 80 persons can finish a workwithin 16 days by working 6hours a day. the number of hours a day, should 64 persons work to finish that very job within 15 days is:1). 5 hrs.2). 7 hrs.3). 8 hrs.4). 6 hrs. |
| Answer» 8 HRS. SEEMS CORRECT. | |
| 249. |
A and B can do a piece of work in 15 days. B and C can do the same work in 10 days and A and C can do the same in 12 days. Time taken by A, B and C together to do the Job is1). 4 days2). 9 days3). 8 days4). 5 days |
| Answer» 8 DAYS is the BEST SUITED | |
| 250. |
A and B undertook to do a piece of work for Rs. 4500. A alone could do it 8 days and B alone in 12 days. With the assistance of C they finished the work in 4 days. Then C’s share of the money is1). Rs. 22502). Rs. 15003). Rs. 7504). Rs. 375 |
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Answer» Given, ⇒ A + B + C = 4 LCM of A, B and A + B + C = 24 EFFICIENCY of A, B, (A + B + C) = = 3, 2, 6 ⇒ A + B + C = 6 ⇒ C = 6 – 3 – 2 = 1 Ratio of efficiency of A, B, C = 3 : 2 : 1 Total amount = 4500 ∴ C's share = 4500 × 1/6 = Rs.750 |
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