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This section includes InterviewSolutions, each offering curated multiple-choice questions to sharpen your Class 11 knowledge and support exam preparation. Choose a topic below to get started.
| 49401. |
A solution containing 1MXSO_4(aq) and 1MYSO_4(aq) is electrolysed. If conc. Of X^(2+) is 10^(-z)M when deposition Y^(2+) and X^(2+) starts simultaneously, calculate the value of Z. Given: (2.303RT)/F=0.06 E_(x^(2+)"|"X)^(@)=-0.12V,E_(Y^(2+)"|"Y)^(@)=-0.24V |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 49402. |
A solution consists of 0.2 MNH_4 OH and 0.2 MNH_4Cl .If K_b of NH_4 OH is 1. 8 xx 10 ^(-5), the [OH^(-) ] of the resulting solution is |
| Answer» <html><body><p>`0.9 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 10 ^(-5) M` <br/>` 1.8 xx 10 ^(-5) ` <br/>` 3.2 xx 10 ^(-5) M` <br/>` 3. <a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> xx 10 ^(-5) ` M </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/poh-1145204" style="font-weight:bold;" target="_blank" title="Click to know more about POH">POH</a> =P^(K_b)+ log ""( [S])/([<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>]) ` <br/>If ` [S] =[B] rArr pOH = P^(K_b) rArr [OH^(-) ] =K_b`</body></html> | |
| 49403. |
A soltuion contains mixture of H_(2)SO_(4) and H_(2)C_(2)O_(4), 25mL of N//10 NaOH for neutralization and 23.45 mL fo N//10 KMnO_(4) for oxisation. Calcualte: (i) Normality of H_(2)C_(2) O_(4) and H_(2)SO_(4) (ii) Strength of H_(2)C_(2)O_(4) and H_(2)SO_(4). Assume molecular weight of H_(2)C_(2)O_(4) = 126 |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :(i) `H_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)C_(2)O = 0.0938N, H_(2)SO_(4) = 0.0482N`, <br/> (<a href="https://interviewquestions.tuteehub.com/tag/ii-1036832" style="font-weight:bold;" target="_blank" title="Click to know more about II">II</a>) `H_(2)SO_(4) = 2.362g//"litre"`</body></html> | |
| 49404. |
Solubility of NaCl in heavy water is |
| Answer» <html><body><p>Both A and R are <a href="https://interviewquestions.tuteehub.com/tag/true-713260" style="font-weight:bold;" target="_blank" title="Click to know more about TRUE">TRUE</a> and R is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of A <br/>Both A and R are true but R is not the correct explanation of A <br/>A is true but is false <br/>A is false but R is true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 49405. |
A solid substance AB has a rock salt geometry. What is the coordination number of A and B ? Ho amy atoms oif A and B are presnet in the unit cell ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>, 6, : 4,4,</body></html> | |
| 49406. |
A solid substance AB has a rock salt geometry . What is the coordination number of A and B ? How many atoms of A and B are present in the unit cell ? |
| Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>, 6, , <a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> ,4</body></html> | |
| 49407. |
A solid mixture(5.000 g) consisting of lead nitrate and sodium nitrate was heated below 600°C until the weight of the residue was constant. If the loss in weight is 28%, find the amount of lead nitrate and sodium nitrate in the mixture. |
| Answer» <html><body><p><br/></p>Solution :Suppose, the given mixture <a href="https://interviewquestions.tuteehub.com/tag/contains-11473" style="font-weight:bold;" target="_blank" title="Click to know more about CONTAINS">CONTAINS</a> x g of lead nitrate.<br/> `therefore` The amount of sodium nitrate in the mixture = `5.<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a> - x` g The corresponding equations are: <br/> `2Pb(NO_(3))_(2) to <a href="https://interviewquestions.tuteehub.com/tag/underset-3243992" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERSET">UNDERSET</a>(2 xx 331.22 g)(2PbO) + 4NO_(2) uarr + underset(2 xx 223.2 g)(O_(2)) uarr`<br/> `2NaNO_(3) to underset(2.85 g)(2NaNO_(2)0 + underset(2 xx <a href="https://interviewquestions.tuteehub.com/tag/69-331759" style="font-weight:bold;" target="_blank" title="Click to know more about 69">69</a> g)(O_(2)) uarr` <br/> According to these equations, weight of <a href="https://interviewquestions.tuteehub.com/tag/pbo-597764" style="font-weight:bold;" target="_blank" title="Click to know more about PBO">PBO</a> formed by heating x g of `Pb(NO_(3))_(2)` <br/> `=(2 xx 223.2)/(2 xx 331.22) xx x = 0.6739 g` <br/> and weight of `NaNO_2` obtained by heating `(5.0 -x) g` of `NaNO_(3)` <br/> `=(2 xx 69)/(2 xx 85) xx (5.0-x) = 0.8118(5.0 -x)`g of `NaNO_(3)` <br/> `therefore` Total weight of the residue = = 0.6739 x + 0.8118 (5.0 - x) g <br/> Since, the mixture loses 28% on heating, the residue obtained on heating 5.0 g of mixture <br/> `=(100-28)/100 xx 5.000 = 3.600 g` <br/> The amount of `Pb (NO_3)_2` in the mixture = 3.328 g and the amount of `NaNO_3` in the mixture = 5.0 - 3.328 = 1.672 g</body></html> | |
| 49408. |
A solid is made up of two elements P and Q. Atoms Q are in ccp arrangement while atoms P occupy all the tetrahedral sites. What is the formula of the compound ? |
| Answer» <html><body><p><br/></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/suppose-656311" style="font-weight:bold;" target="_blank" title="Click to know more about SUPPOSE">SUPPOSE</a> number of <a href="https://interviewquestions.tuteehub.com/tag/atoms-887421" style="font-weight:bold;" target="_blank" title="Click to know more about ATOMS">ATOMS</a> Q=<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a> <br/> Then number of tetrahedral sites =2 n <br/> `<a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a>` Number of atoms P=2n <br/> `therefore` Ratio P:Q=2n:n =2 :1 , i.e., <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> is `P_2Q`</body></html> | |
| 49409. |
A solid element has specific heat 1 I gm^(-1)k^(-1).If the equivalent weight of the element is 9. Identify the valency and atomic weight of element. |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>, 6<br/>3, 27<br/>9, 28<br/>6, 27</p>Solution :At <a href="https://interviewquestions.tuteehub.com/tag/wt-1462289" style="font-weight:bold;" target="_blank" title="Click to know more about WT">WT</a> = `(6.4)/("<a href="https://interviewquestions.tuteehub.com/tag/sp-1219706" style="font-weight:bold;" target="_blank" title="Click to know more about SP">SP</a>. Heat")=26.75~=27` <br/> Valency = `("atomic <a href="https://interviewquestions.tuteehub.com/tag/weight-1451304" style="font-weight:bold;" target="_blank" title="Click to know more about WEIGHT">WEIGHT</a>")/("<a href="https://interviewquestions.tuteehub.com/tag/equivalent-446407" style="font-weight:bold;" target="_blank" title="Click to know more about EQUIVALENT">EQUIVALENT</a> weight")=(26.75)/(9)~=3`</body></html> | |
| 49410. |
A solid compound XY has NaCl structure. If the radius of the cation is 100 pm, the radius of the anion (Y^-) will be |
| Answer» <html><body><p>275.1<br/>322.5 <a href="https://interviewquestions.tuteehub.com/tag/pm-1156895" style="font-weight:bold;" target="_blank" title="Click to know more about PM">PM</a><br/>241.5 pm<br/>165.7 pm</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/nacl-572483" style="font-weight:bold;" target="_blank" title="Click to know more about NACL">NACL</a> has face-centred cubic arrangement of `Cl^-` <a href="https://interviewquestions.tuteehub.com/tag/ions-1051295" style="font-weight:bold;" target="_blank" title="Click to know more about IONS">IONS</a> and `<a href="https://interviewquestions.tuteehub.com/tag/na-572417" style="font-weight:bold;" target="_blank" title="Click to know more about NA">NA</a>^+` ions are present in the octahedral voids. Hence, for such a <a href="https://interviewquestions.tuteehub.com/tag/solid-1216587" style="font-weight:bold;" target="_blank" title="Click to know more about SOLID">SOLID</a> radius of cation =0.414 xradius of the anion ( or `r_+/r_(-)`=0.414) <br/> i.e., `r_+= 0.414xxr_(-)` <br/> or `r_(-)=r_+/0.414=100/0.414`=241.5 pm</body></html> | |
| 49411. |
A solid compound 'X' on heating gives CO_(2)gas and a residue. The residue when mixed with water forms 'Y'. On passing an excess of CO_(2)through 'Y' in water a clear solution 'Z' is obtained. On boiling 'Z' compound 'X' is reformed. The compound 'X' is..... |
| Answer» <html><body><p>`Ca(HCO_(3))_(2)` <br/>`CaCO_(3)` <br/>`Na_(2)CO_(3)` <br/>`K_(2)CO_(3)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :B</body></html> | |
| 49412. |
A solid compound XY has NaCl structure. If the radius of the cation is 100 pm, the radius of the anion (y^(-))will be |
| Answer» <html><body><p>275.1 <a href="https://interviewquestions.tuteehub.com/tag/pm-1156895" style="font-weight:bold;" target="_blank" title="Click to know more about PM">PM</a><br/>322.5 pm<br/>241.5 pm<br/>165.7 pm</p>Solution :In NaCl, Cl' ion from ccp and `Na^(+)` <a href="https://interviewquestions.tuteehub.com/tag/ions-1051295" style="font-weight:bold;" target="_blank" title="Click to know more about IONS">IONS</a> <a href="https://interviewquestions.tuteehub.com/tag/occupy-584657" style="font-weight:bold;" target="_blank" title="Click to know more about OCCUPY">OCCUPY</a> octahedral voids. <br/> `<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>^(+)//r=0.414 or <a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>/r=0.414 ,` <br/> `r^(-)=(100"pm")/0.414=241.5 " pm"`</body></html> | |
| 49413. |
A solid compound 'X' on heating gives CO_(2)gas and a residue. The residue mixed with water forms 'Y'. On passing an excess of CO_(2)through Y' in water, a clear solution 'Z' is obtained. On boiling 'Z', compound 'X' is reformed. The compound 'X' is.... |
| Answer» <html><body><p>`Na_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)CO_(3)` <br/>`K_(2)CO_(3)` <br/>`Ca(HCO_(3))_(2)` <br/>`CaCO_(3)` </p>Solution :The given compound X must be `CaCO_(3)`. It can be explained by <a href="https://interviewquestions.tuteehub.com/tag/followingreactions-2650638" style="font-weight:bold;" target="_blank" title="Click to know more about FOLLOWINGREACTIONS">FOLLOWINGREACTIONS</a>, <br/> `underset((X))(CaCO_(3)) overset(Delta)to underset(("Residue"))(CaO+CO_(2)<a href="https://interviewquestions.tuteehub.com/tag/uarr-3241817" style="font-weight:bold;" target="_blank" title="Click to know more about UARR">UARR</a>),CaO+H_(2)underset((Y))to Ca(<a href="https://interviewquestions.tuteehub.com/tag/oh-585115" style="font-weight:bold;" target="_blank" title="Click to know more about OH">OH</a>)_(2)` <br/> `Ca(OH)_(2)+CO_(2)+H_(2)O to underset((Z))(Ca(HCO_(3)))` <br/>`Ca(HCO_(3))_(2) overset(Delta)to underset((X))(CaCO_(3))+CO_(2)uarr+H_(2)O`</body></html> | |
| 49414. |
A solid compound contains X, Y and Z atoms in a cubinc lattice with X atoms occupying ht corners. Y atoms in the body centred positions and Z atoms at tjee centres of faces of the unit cell. What is the empricial formula of the comound? |
| Answer» <html><body><p>`XY_(2)Z_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`XYZ_(3)`<br/>`X_(2)Y_(2)Z_(3)`<br/>`X_(8)YZ_(6)`<br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :(b) `Z_(x)=(1)/(8)xx8=1` `Z_(y)=1` "["At <a href="https://interviewquestions.tuteehub.com/tag/body-900196" style="font-weight:bold;" target="_blank" title="Click to know more about BODY">BODY</a> centre']", `Z_(3)=3` "["At face centre"]"</body></html> | |
| 49415. |
A solid compound contains X,Y and Z atoms in a cubic lattice with X atoms occupying the corners, Y atoms in the body centred positions and Z atoms at the centres of faces of the unit cell. What is the empirical formula of the compound ? |
| Answer» <html><body><p>`XY_(2)Z_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)`<br/>`XYZ_(3)`<br/>`X_(2)T_(2)Z_(3)`<br/>`X_(8)YZ_(6)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Atoms of X per <a href="https://interviewquestions.tuteehub.com/tag/unit-1438166" style="font-weight:bold;" target="_blank" title="Click to know more about UNIT">UNIT</a> <a href="https://interviewquestions.tuteehub.com/tag/cell-25680" style="font-weight:bold;" target="_blank" title="Click to know more about CELL">CELL</a> `=(8times1)/8=1`<br/> Atoms of Y per unit cell =1 <br/> Atoms of Z per unit cell `=6times1/2=3`<br/> `therefore` the formula of the compound is `XYZ_(3)`</body></html> | |
| 49416. |
A solid acts as an adsorbent because it has |
| Answer» <html><body><p>A definite shape<br/>Small <a href="https://interviewquestions.tuteehub.com/tag/pores-1159601" style="font-weight:bold;" target="_blank" title="Click to know more about PORES">PORES</a> in it<br/>Unsaturated valencies<br/>A <a href="https://interviewquestions.tuteehub.com/tag/high-479925" style="font-weight:bold;" target="_blank" title="Click to know more about HIGH">HIGH</a> <a href="https://interviewquestions.tuteehub.com/tag/lattice-1069551" style="font-weight:bold;" target="_blank" title="Click to know more about LATTICE">LATTICE</a> energy</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49417. |
A solid AB has NaCl structure. If the radius of the cation A is 100 pm, what is the radius of the anion B |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :As <a href="https://interviewquestions.tuteehub.com/tag/nacl-572483" style="font-weight:bold;" target="_blank" title="Click to know more about NACL">NACL</a> has <a href="https://interviewquestions.tuteehub.com/tag/octahedral-1127994" style="font-weight:bold;" target="_blank" title="Click to know more about OCTAHEDRAL">OCTAHEDRAL</a> <a href="https://interviewquestions.tuteehub.com/tag/structure-1230280" style="font-weight:bold;" target="_blank" title="Click to know more about STRUCTURE">STRUCTURE</a>, `r_A^+=0.414xxr_B^-`</body></html> | |
| 49418. |
A solid AB has NaCl structure. If the radius of the cation A is 100 pm, what is the radius of the anion B ? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :As NaCl has octahedral <a href="https://interviewquestions.tuteehub.com/tag/structure-1230280" style="font-weight:bold;" target="_blank" title="Click to know more about STRUCTURE">STRUCTURE</a>` r_(A +) = 0.414 xx r_(<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>^(-))`</body></html> | |
| 49419. |
A solid AB has NaCl structure. If the radius of cation A^+ is 170 pm, calculate the maximum possible radius of the anion B^- |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The formula `r_+=0.414xxr_(-)` <a href="https://interviewquestions.tuteehub.com/tag/gives-1007647" style="font-weight:bold;" target="_blank" title="Click to know more about GIVES">GIVES</a> <a href="https://interviewquestions.tuteehub.com/tag/maximum-556915" style="font-weight:bold;" target="_blank" title="Click to know more about MAXIMUM">MAXIMUM</a> <a href="https://interviewquestions.tuteehub.com/tag/possible-592355" style="font-weight:bold;" target="_blank" title="Click to know more about POSSIBLE">POSSIBLE</a> radius of <a href="https://interviewquestions.tuteehub.com/tag/anion-876036" style="font-weight:bold;" target="_blank" title="Click to know more about ANION">ANION</a> for a given cation for close packing.</body></html> | |
| 49420. |
A solid AB has NaCl structure. If the radius of cation A^(+) is 170 pm, calculate the maximum possibleradius of the anionB^(-) |
| Answer» <html><body><p><br/></p>Solution :The <a href="https://interviewquestions.tuteehub.com/tag/formula-464310" style="font-weight:bold;" target="_blank" title="Click to know more about FORMULA">FORMULA</a> ` r_(+) = 0.414 xx r_(-)` <a href="https://interviewquestions.tuteehub.com/tag/gives-1007647" style="font-weight:bold;" target="_blank" title="Click to know more about GIVES">GIVES</a> maximum possible radius of <a href="https://interviewquestions.tuteehub.com/tag/anion-876036" style="font-weight:bold;" target="_blank" title="Click to know more about ANION">ANION</a> for a given <a href="https://interviewquestions.tuteehub.com/tag/cation-910854" style="font-weight:bold;" target="_blank" title="Click to know more about CATION">CATION</a>, for close packing</body></html> | |
| 49421. |
A solid AB has CsCl type structure. The edge length of the unit cell is 404 pm. Calculate the distance of closest approach between A^+ and B^- ions? |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Distance of closest <a href="https://interviewquestions.tuteehub.com/tag/approach-882321" style="font-weight:bold;" target="_blank" title="Click to know more about APPROACH">APPROACH</a> is <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to the distance between the nearest neighbours (d). As <a href="https://interviewquestions.tuteehub.com/tag/cscl-410997" style="font-weight:bold;" target="_blank" title="Click to know more about CSCL">CSCL</a> has BCC lattice, <br/> `d=sqrt3/2a=1.732/2xx404` pm =349.9 pm</body></html> | |
| 49422. |
A solid AB has CsCl typestructure. The edge length of the unit cell is404 pm.Calculate the distance of closest approach between A^(+)and B^(-)ions ? |
| Answer» <html><body><p><br/></p>Solution :Distance of closest approach is <a href="https://interviewquestions.tuteehub.com/tag/equal-446400" style="font-weight:bold;" target="_blank" title="Click to know more about EQUAL">EQUAL</a> to the distance between the nearest <a href="https://interviewquestions.tuteehub.com/tag/neighbours-1113488" style="font-weight:bold;" target="_blank" title="Click to know more about NEIGHBOURS">NEIGHBOURS</a> (d)As CsCl has BCC latttic .,<br/>`d = sqrt3/ <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> a = 1.732/2 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> <a href="https://interviewquestions.tuteehub.com/tag/404-1874913" style="font-weight:bold;" target="_blank" title="Click to know more about 404">404</a>"pm"= 349.9 ` pm</body></html> | |
| 49423. |
A solid A^+ B^- has NaCl type close packed structure. If the anion has a radius of 250 pm, what should be the ideal radius of the cation ? Can a cation C^+ having a radius of 180 pm be slipped into the tetrahedral site of the crystal A^+ B^- ? Give reason for your answer. |
| Answer» <html><body><p><br/></p>Solution :`(r_(+)(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>^+))/(r_(-)(B^-))="180pm"/"250pm"=0.72` <br/> It does not lie in the <a href="https://interviewquestions.tuteehub.com/tag/range-1177030" style="font-weight:bold;" target="_blank" title="Click to know more about RANGE">RANGE</a> 0.225-0.414 . <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a>, `C^+` cannot be slipped into the tetrahedralsite.</body></html> | |
| 49424. |
A solid A^(+)B^(-) has NaCl type close packed structure. If the anion has a radius of 250 pm,what should be the ideal radius of cation ? Can a cationC^(+)having a radius of 180 pm be slipped into the tetrahedral site of the crtstalA^(+) B^(-)?Given reason for your answer . |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`(r_(+)(<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>^(+)))/(r_(-)(B^(-))) = (180"pm")/(250"pm") = 0.72`<br/>It does not ,lie in the <a href="https://interviewquestions.tuteehub.com/tag/range-1177030" style="font-weight:bold;" target="_blank" title="Click to know more about RANGE">RANGE</a> ( 0.225 - 0.414 . Hence`C^(+)`cannot be slipped into the tetrahedral site.</body></html> | |
| 49425. |
A solid A^+B^- has NaCl type close packed structure .If the anion has a radius of 241.5 pm , what should be the ideal radius of the cation ? Can a cation C^+ having radius of 50 pm be fitted into the tetrahedral hole of the crystal A^+ B^- ? |
| Answer» <html><body><p></p>Solution :As `A^+ B^-` has <a href="https://interviewquestions.tuteehub.com/tag/nacl-572483" style="font-weight:bold;" target="_blank" title="Click to know more about NACL">NACL</a> structure, `A^+` ions will be present in the octahedral voids. Ideal radius of the cation will be equal to the radius of the octahedral void because in that case. It will touch the anions and the arrangement will be <a href="https://interviewquestions.tuteehub.com/tag/close-408965" style="font-weight:bold;" target="_blank" title="Click to know more about CLOSE">CLOSE</a> packed. Hence, Radius of the octahedral void =`r_(A^+)=0.414 xxr_(B^-)=0.414xx241.5` pm =100.0 pm <br/> Radius of the tetrahedral void =`0.225 xxr_(B^-)` =0.225 x 241.5 pm =54.3 pm<br/> As the radius of the cation `<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>^+` (50 pm) is smaller than the size of the tetrahedral void, it can be placed into the tetrahedral void (but not exactly <a href="https://interviewquestions.tuteehub.com/tag/fitted-2079092" style="font-weight:bold;" target="_blank" title="Click to know more about FITTED">FITTED</a> into it)</body></html> | |
| 49426. |
A solid A^(+)B^(-) has NaCl close packed structure. The radius of thecation when the radius of the anion is 250 pm is |
| Answer» <html><body><p>103.5 pm<br/>207 pm<br/>69 pm <br/>276 pm</p>Solution :Since the solid `A^(+) <a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>^(-)`has NaCl type close packed structure, it belongs to a system with coordination number <a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>. In thesecases the ratio of the cation to the anion radii is <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> by<br/> `<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>^(+)/r^(-)ge0.414`<br/> `"Now" r^(-)=<a href="https://interviewquestions.tuteehub.com/tag/250-297421" style="font-weight:bold;" target="_blank" title="Click to know more about 250">250</a>"pm"` <br/> `thereforer^(+)=250times0.414=103.5"pm"`</body></html> | |
| 49427. |
A soldium salt of unknown anion when treated with MgCl_(2) gives white precipitate only on boiling. The anion is: |
| Answer» <html><body><p>`SO_(4)^(2-)`<br/>`HCO_(3)^(-)`<br/>`CO_(3)^(2-)`<br/>`NO_(3)^(-)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :The salt is `NaHCO_(3)` <br/> `2NaHCO_(3) + MgCl_(2) rarr underset(("White ppt"))underset(MgCO_(3))underset(darr "heat")(Mg(HCO_(3))_(2))+ 2NaCl`</body></html> | |
| 49428. |
(A) :Soil becomes infertile due to acid rain (R) :Due to acid rain pH of the soil increases |
| Answer» <html><body><p> Both A and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> are true , and R is correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of A<br/> Both A and R are true , and R is not the correct explanation of A<br/> A is true but R is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a> <br/>A is false but R is true</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a></body></html> | |
| 49429. |
A sodium street light gives off yellow light that has a wavelength of 600 nm. Then (For energy of a photon take E=(12400eV-"Å")/(lambda("Å")): |
| Answer» <html><body><p>frequency of this <a href="https://interviewquestions.tuteehub.com/tag/light-1073401" style="font-weight:bold;" target="_blank" title="Click to know more about LIGHT">LIGHT</a> is `7xx10^(14)s^(-1)`<br/>frequency of this light is `5xx10^(14)s^(-1)`<br/>wave number of the light is `<a href="https://interviewquestions.tuteehub.com/tag/3xx10-1865443" style="font-weight:bold;" target="_blank" title="Click to know more about 3XX10">3XX10</a>^(6) m^(-1)`<br/>energy of the photon is <a href="https://interviewquestions.tuteehub.com/tag/approximately-380771" style="font-weight:bold;" target="_blank" title="Click to know more about APPROXIMATELY">APPROXIMATELY</a> 2.07 eV</p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a>::D</body></html> | |
| 49430. |
A sodium salt on treatment with MgCl_(2) gives white precipitate on heating. The anion of the sodium salt is: |
| Answer» <html><body><p>`CO_(3)^(2-)`<br/>`HCO_(3)^(Θ)`<br/>`SO_(4)^(2+)`<br/>`NO_(3)^(Θ)`</p>Solution :Given, `NaX+MgCl_(2)overset(Delta)(rarr)`White ppt. <br/> `NaHCO_(3)+MgCl_(2)rarrunderset("Soluble")(<a href="https://interviewquestions.tuteehub.com/tag/mg-1095425" style="font-weight:bold;" target="_blank" title="Click to know more about MG">MG</a>(HCO_(3))_(2))+NaCl` <br/> `Mg(HCO_(3))_(2)overset(Delta)(rarr)underset("White ppt".)(MgCO_(3))+H_(2)O+Co_(2)` <br/> Hence, anion of the <a href="https://interviewquestions.tuteehub.com/tag/sodium-1215510" style="font-weight:bold;" target="_blank" title="Click to know more about SODIUM">SODIUM</a> salt is `HCO_(3)^(Θ)`.</body></html> | |
| 49431. |
A sodium salt of unknown anion when treated with MgCl_(2) gives white precipitateonly on boiling . The anion is |
| Answer» <html><body><p>`SO_(4)^(2-)`<br/>`HCO_(3)^(-)`<br/>`CO_(3)^(2-)`<br/>`NO_(3)^(-)`</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/bicarbonates-896608" style="font-weight:bold;" target="_blank" title="Click to know more about BICARBONATES">BICARBONATES</a> on heating <a href="https://interviewquestions.tuteehub.com/tag/form-996208" style="font-weight:bold;" target="_blank" title="Click to know more about FORM">FORM</a> insoluble <a href="https://interviewquestions.tuteehub.com/tag/carbonates-413333" style="font-weight:bold;" target="_blank" title="Click to know more about CARBONATES">CARBONATES</a> <br/> `MgCl_(2) + 2 NaHCO_(3) to NaCl + Mg(HCO_(3))_(2)` <br/> `Mg(HCO_(3))_(2) <a href="https://interviewquestions.tuteehub.com/tag/overset-2905731" style="font-weight:bold;" target="_blank" title="Click to know more about OVERSET">OVERSET</a>(Delta)(to) MgCO_(3) darr + CO_(2) + H_(2)O`</body></html> | |
| 49432. |
A sodium salt on treatment with MgCI_(2) gives white precipitate only on heating. The anion of sodium salt is |
| Answer» <html><body><p>`HCO_(3)^(-)`<br/>`CO_(3)^(2-)`<br/>`NO_(3)^(-)`<br/>`SO_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)^(2-)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`2NaHCO_(3) + MgCI_(2)overset(Delta) <a href="https://interviewquestions.tuteehub.com/tag/rarr-1175461" style="font-weight:bold;" target="_blank" title="Click to know more about RARR">RARR</a> Mg(HCO_(3))_(2) + 2NaCI`</body></html> | |
| 49433. |
A sodium salt of unknown anion when treated with MgCl_(2)gives white precipitate only on boiling. The anion is .......... |
| Answer» <html><body><p>`SO_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)^(2-)` <br/>`HCO_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)^(-)` <br/>`CO_(3)^(2-)` <br/>`NO_(3)^(-)` </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49434. |
(A) : Sodium metals is stored in kerosene (R): The density of sodium is less than water |
| Answer» <html><body><p>Both A and R are correct and 'R' is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of A<br/>Both A and R are correct and 'R' is not the correct explanation of A<br/>A is correct but R is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a><br/>A is false but R is correct </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49435. |
(A) Sodium fusion extract of a compound gives black precipitate with lead acetate. (R) Sulphur containing compounds form Na_(2)S in sodium fusion extract. |
| Answer» <html><body><p>If both <a href="https://interviewquestions.tuteehub.com/tag/assertion-384238" style="font-weight:bold;" target="_blank" title="Click to know more about ASSERTION">ASSERTION</a> and reason are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> and reason is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of the assertion <br/>If both assertion and reason are correct but reason is not the correct explanation of the assertion <br/>If assertion is correct but reason is <a href="https://interviewquestions.tuteehub.com/tag/incorrect-499101" style="font-weight:bold;" target="_blank" title="Click to know more about INCORRECT">INCORRECT</a> <br/>If assertion is incorrect but reason is correct </p>Answer :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49436. |
A sodium fire in the laboratory is extinguished by |
| Answer» <html><body><p>Water<br/>Petrol<br/>Alcohol<br/>CC14</p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> <a href="https://interviewquestions.tuteehub.com/tag/na-572417" style="font-weight:bold;" target="_blank" title="Click to know more about NA">NA</a> does not <a href="https://interviewquestions.tuteehub.com/tag/react-613674" style="font-weight:bold;" target="_blank" title="Click to know more about REACT">REACT</a> with `CCI_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)`</body></html> | |
| 49437. |
A: SO_(2) molecule has unsymmetrical shape R: The dipole moment of SO_(2) molcule is equal to zero. |
| Answer» <html><body><p>Both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are true and (R) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> of (A)<br/>Both (A) and (R) are true and (R) is not the correct explanation of (A) <br/>(A) is true but (R) is <a href="https://interviewquestions.tuteehub.com/tag/false-459184" style="font-weight:bold;" target="_blank" title="Click to know more about FALSE">FALSE</a><br/>(A) is false but (R) is true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :A</body></html> | |
| 49438. |
(A) Soap and detergent are macro-molecular colloids . (R) soap and detergent are molecular of large size. |
| Answer» <html><body><p>IF both (A) and (<a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a>) are <a href="https://interviewquestions.tuteehub.com/tag/correct-409949" style="font-weight:bold;" target="_blank" title="Click to know more about CORRECT">CORRECT</a> and (r) is the correct <a href="https://interviewquestions.tuteehub.com/tag/explanation-455162" style="font-weight:bold;" target="_blank" title="Click to know more about EXPLANATION">EXPLANATION</a> for (a). <br/>If both (a) and (r) are correct but (r) is not the correct explanation for (a). <br/>IF (a) is correct but (r) is <a href="https://interviewquestions.tuteehub.com/tag/incorrect-499101" style="font-weight:bold;" target="_blank" title="Click to know more about INCORRECT">INCORRECT</a>. <br/>If (a) is incorrect but (r) is correct. </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html> | |
| 49439. |
A smuggler could not carry gold by depositing iron chemically on the gold surface since |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/gold-1008823" style="font-weight:bold;" target="_blank" title="Click to know more about GOLD">GOLD</a> is denser<br/>iron rusts<br/>gold has <a href="https://interviewquestions.tuteehub.com/tag/higher-1022060" style="font-weight:bold;" target="_blank" title="Click to know more about HIGHER">HIGHER</a> <a href="https://interviewquestions.tuteehub.com/tag/reduction-621019" style="font-weight:bold;" target="_blank" title="Click to know more about REDUCTION">REDUCTION</a> potential than iron<br/>gold has lower reduction potential than iron</p>Solution :Gold having higher `E_("red")^(@)` oxidises Fe to `Fe^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>+)`</body></html> | |
| 49440. |
A smaple of pyrolusite weighing 0.5 g is distilled with conc. HCl. The evolved Cl_(2) when passed through a solution of KI liberates sufficient I_(2) to react with 125 mL of N//12.5 hypo (Na_(2)S_(2)O_(3). 5H_(2)O). Calculate the percentage of MnO_(2) in pyrolusite. |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :N//A</body></html> | |
| 49441. |
A small quantity of gaseous NH_(3) and HBr are introduced simultaneously into the opposite ends of an open tube which is one metre long. Calculatethe distance of the white solid NH_(4)Br formed from the end which was used to introduce NH_(3). |
| Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<a href="https://interviewquestions.tuteehub.com/tag/similar-1207900" style="font-weight:bold;" target="_blank" title="Click to know more about SIMILAR">SIMILAR</a> to <a href="https://interviewquestions.tuteehub.com/tag/solved-631889" style="font-weight:bold;" target="_blank" title="Click to know more about SOLVED">SOLVED</a> <a href="https://interviewquestions.tuteehub.com/tag/problem-25530" style="font-weight:bold;" target="_blank" title="Click to know more about PROBLEM">PROBLEM</a> <a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>.</body></html> | |
| 49442. |
A small particle of massm moves in such a way that the potential energy U = ar^(2) where a is a constant and r is the distance of the particle from the origin. Assuming Bohr's model of quantization of angular momentum and circular orbits, find the radius of n^(th) allowed orbit. |
| Answer» <html><body><p>`n^2`<br/>`n`<br/>`sqrtn`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>/(sqrtn)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`-1/2 xx P.E.= <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a>.E` <br/>`=-1/2 (- 1/2 mkr^2) = 1/2 mv^2 , mvr = (<a href="https://interviewquestions.tuteehub.com/tag/nh-570695" style="font-weight:bold;" target="_blank" title="Click to know more about NH">NH</a>)/(<a href="https://interviewquestions.tuteehub.com/tag/2pi-1838601" style="font-weight:bold;" target="_blank" title="Click to know more about 2PI">2PI</a>),` <br/>`v^2 = (n^2 h^2)/(4pi^2 m^2 r^2) ,r^4 = (n^2 h^2)/(2pi^2 m^2 k) ` or `r^00 sqrtn`</body></html> | |
| 49443. |
A small amount of NH_(4)HS is placed in a flask already containing ammonia gas at a certain temperature and 0*50 atm pressure. Ammonium hydrogensulphide decomposes to yield NH_(3) andH_(2)S gass in the flask . When the decomposition reaction reaches equilibrium , the total pressure in the flask rises to 0.84 atm. The equilibrium constant for NH_(4)HS decomposition at this temperature is |
| Answer» <html><body><p>`0.30`<br/>`0*18`<br/>`0*<a href="https://interviewquestions.tuteehub.com/tag/17-278001" style="font-weight:bold;" target="_blank" title="Click to know more about 17">17</a>` <br/>`0*<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a>`</p>Solution :`{:(,NH_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>)HS (s),<a href="https://interviewquestions.tuteehub.com/tag/harr-2692945" style="font-weight:bold;" target="_blank" title="Click to know more about HARR">HARR</a>,NH_(3) (g),+,H_(2)S (g)), ("Intial",a " moles",,0.5" atm",,), (" At .eqm.",(a-<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>),,(0.5+p),,p " atm".):}` <br/> i.e., if x moles of `NH_(4)HS` decompose , increase in pressure due to `NH_(3)` = increase in pressure due to `H_(2)S` = p atm .<br/> Total pressure at equilibrium <br/> ` 0.5 + p+ p = 0.5 + 2 p ` atm <br/> ` 0.5 + 2 p = 0.84 " atm" or p=0.17` atm <br/> ` :. p_(NH_(3)) = 0.5 + 0.17 = 0.67` atm<br/> ` p_(H_(2)S) = 0.17 ` atm <br/> ` K_(p) =p_(NH_(3)) xx p_(H_(2)S)` <br/> ` =0.67 xx 0.17 = 0.1139`</body></html> | |
| 49444. |
A small amount of CaCO_(3) completely neutralises 525 ml of (N)/(10) HCl and no acid is left at the end after converting all calcium chloride to CaSO_(4). How much plaster paris (CaSO_(4)(1)/(2)H_(2)O) can be obtained |
| Answer» <html><body><p>`1.916g`<br/>`5.827g`<br/>`7.53g`<br/>`3.81g`</p>Solution :No. of Meq of HCl = `525xx(1)/(<a href="https://interviewquestions.tuteehub.com/tag/10-261113" style="font-weight:bold;" target="_blank" title="Click to know more about 10">10</a>)=52.5` <br/> No. of Meq of HCl = No. of mecq of `CaCl_(2)` = <br/> No. of Meq of <a href="https://interviewquestions.tuteehub.com/tag/plaster-601297" style="font-weight:bold;" target="_blank" title="Click to know more about PLASTER">PLASTER</a> of <a href="https://interviewquestions.tuteehub.com/tag/paris-11027" style="font-weight:bold;" target="_blank" title="Click to know more about PARIS">PARIS</a> <br/> So No. of Meq of plaster of paris = 52.5 <br/> `52.5=("wt of plaster of paris")/("GEW of plaste of paris")xx1000` <br/> `52.5=(<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>)/(72.5)xx1000impliesx=3.81g`</body></html> | |
| 49445. |
A single electron system has ionization energy 11180 kJ mol^(-1). Find the number of protons in the nucleus of the system. |
| Answer» <html><body><p><br/></p>Solution :`IE=(Z^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))/(<a href="https://interviewquestions.tuteehub.com/tag/n-568463" style="font-weight:bold;" target="_blank" title="Click to know more about N">N</a>^(2))xx21.69xx10^(-19)<a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a>` <br/> `(11180xx10^(3))/(6.023xx10^(23))=(Z^(2))/(1^(2))xx21.69xx10^(-19)` <br/> `Z~~3`.</body></html> | |
| 49446. |
A single compound of the structure is obtained from ozonolysis of twhich of the followiing cyclic compounds ? |
| Answer» <html><body><p><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/A2Z_CHM_XI_C15_E01_288_O01.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/A2Z_CHM_XI_C15_E01_288_O02.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/A2Z_CHM_XI_C15_E01_288_O03.png" width="30%"/><br/><img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/A2Z_CHM_XI_C15_E01_288_O04.png" width="30%"/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :<img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/A2Z_CHM_XI_C15_E01_288_S01.png" width="80%"/></body></html> | |
| 49447. |
A simplified application of MO theory to the hypothetical "molecule" OF would give its bond order as |
| Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a><br/>`1.5`<br/>`1.0`<br/>`0.5`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |
| 49448. |
A Simple aromatic hydrocarbon A reacts with Cl_2 to give B of molecular formula C_6H_5Cl. B on reaction with ethyl chloride along with sodium metal gives C of formula C_8H_10.C alone reacts with Na metal in the presence of ether to give D C_12 H_10. Identify A,B,C & D. |
| Answer» <html><body><p></p>Solution : (i) The simple aromatic <a href="https://interviewquestions.tuteehub.com/tag/hydrocarbon-1034072" style="font-weight:bold;" target="_blank" title="Click to know more about HYDROCARBON">HYDROCARBON</a> is `C_6H_6` Benzene (A) <br/> (ii) Benzene reacts with `Cl_2` to give chlorobenzene. <br/> `C_6H_6 + Cl_2 overset(FeCl_2) to underset("benzene")underset("Chloro")(C_6H_5Cl) + HCl_B` <br/> (<a href="https://interviewquestions.tuteehub.com/tag/iii-497983" style="font-weight:bold;" target="_blank" title="Click to know more about III">III</a>) Chlorobenzene reacts with ethyl <a href="https://interviewquestions.tuteehub.com/tag/chloride-915854" style="font-weight:bold;" target="_blank" title="Click to know more about CHLORIDE">CHLORIDE</a> to <a href="https://interviewquestions.tuteehub.com/tag/form-996208" style="font-weight:bold;" target="_blank" title="Click to know more about FORM">FORM</a> ethyl benzene, C as the product. <br/> `C_6H_5Cl + <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> Na+ C_2H_5Cl overset("ether")to underset("Ethyl benzene C")(C_6H_5- C_2H_5) + 2NaCl` <br/> (iv) Chlorobenzene on reaction Na metal gives Biphenyl compound D as the product. <br/> `C_6H_5Cl + 2Na + C_6H_5Clto underset("Biphenyl D")(C_6H_5-C_2H_5) + 2NaCl` <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/FM_CHE_XI_V02_C14_E03_235_S01.png" width="80%"/></body></html> | |
| 49449. |
A similarity between optical and geometrical isomerism is that |
| Answer» <html><body><p>each forms equal number of isomers for a <a href="https://interviewquestions.tuteehub.com/tag/given-473447" style="font-weight:bold;" target="_blank" title="Click to know more about GIVEN">GIVEN</a> compound<br/>if in a compound, <a href="https://interviewquestions.tuteehub.com/tag/one-585732" style="font-weight:bold;" target="_blank" title="Click to know more about ONE">ONE</a> is <a href="https://interviewquestions.tuteehub.com/tag/present-1163722" style="font-weight:bold;" target="_blank" title="Click to know more about PRESENT">PRESENT</a> then so is the other <br/> both are <a href="https://interviewquestions.tuteehub.com/tag/included-499087" style="font-weight:bold;" target="_blank" title="Click to know more about INCLUDED">INCLUDED</a> in stereoisomerism<br/> they have no similarity </p>Answer :C</body></html> | |
| 49450. |
(A): Silicones are synthetic organosilicon compounds (R) : Silicones contain Si-O-Si linkages |
| Answer» <html><body><p>A and <a href="https://interviewquestions.tuteehub.com/tag/r-611811" style="font-weight:bold;" target="_blank" title="Click to know more about R">R</a> are true, R explains A <br/>A and R are true, R does not explain A <br/>A is true, but R is false <br/>A is false, but R is true </p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :<a href="https://interviewquestions.tuteehub.com/tag/b-387190" style="font-weight:bold;" target="_blank" title="Click to know more about B">B</a></body></html> | |