94420 + Interview Questions in Chemistry in Class 12 Page 518 InterviewSolution

25851.	The pH value at which the amino acid does not migrate under the influence of electric field is called …………...........
Answer» Isoelectric POINT Isoelectronic point EQUIVALENCE point NEUTRALIZATION point Solution :Isoelectric point

Discussion

25852.	The pH value of 0.1 M HCl is approximately 1. What will be the approximately pH value of 0.05 MH_(2)SO_(4)
Answer» 0.05 0.5 1 2 Solution :`H_(2)SO_(4) = 0.05 xx 2` `:. [H^(+)] 0.1` and pH = 1.

Discussion

25853.	The pH pure water or neutral solution at 50^(@)C is..........(pK_(w) = 13.26 = 13.26 at 50^(@))
Answer» `7.0` 7.13 `6.0` 6.63 Answer :D

Discussion

25854.	The pH of which salt solution is independent of its concentration ? 1 (CH_(3)COO)C_(5)H_(5)NH 2Na_(2)PO_(4) 3.Na_(2)HPO_(4) 4. NH_(4)CN
Answer» `1,2,3,4` `1,4` `2,3` `1,2,3` SOLUTION :`PH` of amphiprotic SALT solutions and WEAK acid-weak base salt solutions is INDEPENDENT of there concentration .

Discussion

25855.	The pHof water is 7 at 25^(@)C. If water is heated to 50^(@)C, which of the following should be true?
Answer» PH will remain SEVEN pH will increase pH will increase pH will decrease `[H^(+)]` will increases but `[OH^(-)]` will decrease Answer :C

Discussion

25856.	The pH of the solution when 0.2 mole of HCl is added to one litre of a solution containing 0.1 M CH_(3)COOH and 0.1 M CH_(3)COO^(-) is
Answer» 0.7 4.57 3.8 `1.0` ANSWER :D

Discussion

25857.	The pH of water at 25^(@)C is nearly
Answer» 2 7 10 12 Solution :`[H^(+)] = [OH^(-)]` `K_(w) = [H^(+)][OH^(-)] = 10^(-14)` `:. [H^(+)] = 10^(-7), PH = -log[H^(+)] = 7`.

Discussion

25858.	The pH of the solution produced when an aqueous solution of strong acid pH 5 is mixed with equal volume of an aqueous solution of strong acid of pH 3 is:
Answer» 3.3 3.5 4.5 4 Answer :A

Discussion

25859.	The pH of the solution produced by mixing equal volume of 2.0 xx 10^(-3) M HClO_(4) and 1.0 xx 10^(-2) M KClO_(4) is
Answer» 2.7 2.3 3 1 Solution :`H^(+)` contribution is by ACID only as `KClO_(4)` is a SALT of a STRONG acid and strong base which does not hydrolyse. So, `pH = -LOG[2.0 xx 10^(-3)]` `= 3- log 2.0 = 3 - 0.3010 = 27`.

Discussion

25860.	The pH of the solution obtained by mixing 20mL of 0.01 (M) Ca(OH)_2 and 30mL of 0.1 (M) HCl solution is-
Answer» 0.32 9.85 11.3 4.74 Answer :C

Discussion

25861.	The pH of the solution obtained by dissolving pure sodium chloride water is
Answer» Both the statements are individually true and STATEMENT II is the CORRECT explanation of statement I Both the statements are individually true but statemnts II is not corrrect exp[anation of statemnt I statement I is true but statement II is false statement I is flse but statement IIU is true Solution :The common salt (NACI) is netural in nature so it doesn't change the PH

Discussion

25862.	The pH of the solution obtained by mixing 100 mL of a solution of pH = 3 with 400 mL of a solution of pH = 4 is
Answer» 3 - log 2.8 7- log 2.8 4- log 2.8 5- log 2.8 Solution :pH = 3 means `10^(-3)` M and pH = 4 means `10^(-4)` M . 100 mL of `10^(-3)` M solution contain = `(10^(-3) xx 100)/(1000) = 10 xx 10^(-5)` MOL 400 mL of `10^(-4)` M solution contain= `(10^(-4) xx 400)/(1000)= 4 xx 10^(-5)` mol Total number of moles present = `(10 xx 10^(-5))+ (4 xx 10^(-5)) = 14 xx 10^(-5)` mol Total volume after MIXING `= (100 + 400) = 500` mL Molarity of the mixture = `(14 xx 10^(-5))/(500) xx 1000` `= ((14)/(5) xx 10^(-4)) M`

Discussion

25863.	The pH of the solution obtained by mixing 100 mL of a solution of pH = 3 with 400 mL of a solution of pH = 4 is :
Answer» `3-LOG 2.8` `7-log 2.8` `4-log 2.8` `5-log 2.8` Solution :`{:(V_(1)=100mL,V_(2)=400mL),(pH=3,pH=4),(therefore M_(1)=10^(-3)M,M_(2)=10^(-4)M):}` Molarity, M of resultant solution may be calculated as : `M_(1)V_(1)+M_(2)V_(2)=MV` `10^(-3)xx100+10^(-4)xx400=M(100+400)` or`M=(10^(-1)+4xx10^(-2))/(500)=(10^(-1)(1+0.4))/(500)` `=(0.14)/(500)=0.028xx10^(-2)=2.8xx10^(-4)1` `pH=-log[H^(+)]=-log (2.8xx10^(-4))` `=4-log2.8`.

Discussion

25864.	The pH of the solution obtained by mixing 10 mL of 10^-1 N HCl and 10 mL of 10^-1 N NaOH is:
Answer» 8 2 7 None Answer :C

Discussion

25865.	The pH of the solution is 4. The hydrogen ion concentration of the solution in mol/litre is
Answer» 9.5 `10^(-4)` `10^(4)` `10^(-2)` SOLUTION :`PH = 4, (H^(+)) = 10^(-pH) = 10^(-4)M`.

Discussion

25866.	The pH of the solution containing following zwitter ion species is
Answer» 4 6 8 9 Solution :N//A

Discussion

25867.	ThepH of the solution is 3.0 if itspH is changed to 6.0 then the [H^+] of the original solution has to be :
Answer» DOUBLED HALVED INCREASED 1000 times DECREASED 1000 times Answer :D

Discussion

25868.	The pH of the solution containing 10 ml of 0.1 N NaOH and 10 ml of 0.05 NH_(2)SO_(4) would be
Answer» 0 1 `gt 7` 7 Solution :M.eq of 10 ml, `0.1 N NAOH = 10 xx 0.1 = 1` and M.eq. of 10 ml `0.05N H_(2)SO_(4) = 0.05 xx 10 = .5` REMAINING M.eq. of `NaOH = 1 - 0.5 = 0.5` `[OH^(-)] = (0.5)/(20 xx 10) = (1)/(40) = 0.25 xx 10^(-1) = 2.5 xx 10^(-2)` `POH = - LOG 2.5 xx 10^(-2)` `pOH = 0.2 - log 2.5` `pH = 14 - pOH` `pH = 14-2+log 2.5` `pH = 12 + log 2.5 gt 7`

Discussion

25869.	The pH of the solution: 5ml of (M)/(5), HCl + 10 ml of (M)/(10) NaOH is
Answer» 5 3 7 8 Solution :MILLIEQUIVALENTS of HCl `= 5 xx (1)/(5) = 1`. Millequivalents of `NAOH = 10 xx (1)/(10) = 1` `:. 5ML (M)/(5)HCl = 10 ml(M)/(10) NaOH` Hence the solution will be neutral i.e, PH = 7.

Discussion

25870.	The pH of the solution containing 10 mL of 0.1 N NaOH and 10 mLof 0.05 NH_(2)SO_(4)would be
Answer» 1 0 7 ` gt 7` SOLUTION :Numberof milliequivalents of NaOH = NORMALITY `xx` volume (mL)= `0.1 xx 10 =1 ` Numberof milliequivalents of ` H_(2)SO_(4) = 0.05 xx 10 = 0.5 ` 0.5 milliequivalentof ` H_(2)SO_(4)`gets neutralized with contains0.5milliequivalentof NaOH. Hencesolution will be basicwithPH > 7

Discussion

25871.	The pH of the bloodstream is maintained by a proper balance of H_2CO_3and NaHCO_3concentrations. What volume of 5 M NaHCO_3solution should be mixed with a 10 mL sample of blood which is 2 M in H_2CO_3 , in order to maintain a pH of 7.4? K_ą for H_2CO_3, in blood is 7.8xx 10^(-7)
Answer» Solution :mm of `NaHCO_3 = 5 XX X ` mm of `H_2CO_3 = 2 xx 10` APPLY henderson.s equation and CALCULATE x. 78.36mL

Discussion

25872.	The pH of the aqueous solution containing 0.49 gm of H_(2)SO_(4) in one litre is
Answer» 2 1 1.7 0.3 Solution :Moles of `H_(2)SO_(4) = (0.49)/(98) = 5 xx 10^(-3)` moles of `H_(2)SO_(4)` PERCENT per litre of solution (MOLARITY) = `(0.005)/(1) = 0.005 M`. `H_(2)SO_(4) + 2H_(2)O hArr 2H_(3)O^(+) + SO_(4)^(--)`. one mole of `H_(2)SO_(4)` give 2 moles of `H_(3)O^(+)` ions. `H_(3)O^(+) = 2 xx (H_(2)SO_(4)) = 2 xx 0.005 xx 0.01 M` `[H^(+)] = 10^(-2)M , pH = 2`.

Discussion

25873.	The pH of the a solution obtained by mixing 50 ml of 0.4 N HCl and 50 ml of 0.2 N NaOH is
Answer» `-log 2` `-log 0.2` `1.0` `2.0` Solution :M. eq. of 50 ML 0.4 N HCL `= 0.4 xx 50 = 20` M. eq. of 50 ml, 0.2 N NaOH `= 0.2 xx 50 = 10` REMAINING M.eq. of HCl = 20 - 10 = 10 `[H^(+)]` in `HCl = (10)/(50+50) = 0.1 n = 10^(-1)` `pH = - log 10^(-1) = 1`.

Discussion

25874.	The pH of the blood does not appreciably change by small addition of an acid or a base because blood :
Answer» CONTAINS SERUM PROTEIN which acts as a buffer Contains iron as a PART of the molecule Can be coagulated easily Is a body fluid Answer :A

Discussion

25875.	ThePhof stomach is:
Answer» 7 6 10 2 Answer :D

Discussion

25876.	The pH of solutions of both ammonium acetate and sodium chloride is 7 due to
Answer» HYDROLYSIS of the LATTER but not the FORMER Hydrolysis in both CASES No hydrolysis cases both The former hydrolysis and not the latter Answer :D

Discussion

25877.	The pH of solution obtained by mixing equal volumes of two aqueous solutions of pH 5 and pH 3 of the same substance is :
Answer» `3.5` `4.5` `3.3` 4 SOLUTION :LET 100 ml of both the solutions are mixed `[H^(+)]` in solution of pH = 5 is `10^(-5)` `[H^(+)]` in solution of pH = 3 is `10^(-3)` TOTAL `[H^(+)]=10^(-5)+10^(-3)` `=1.01xx10^(-3)` Total VOLUME = 2000 ml Conc. in mixture `=(1.01xx10^(-3)xx1000)/(2000)=5.05xx10^(-4)` `pH=-log(5.05xx10^(-4))=3.3`

Discussion

25878.	The pH of solution having [OH^(-)] = 10^(-7) is
Answer» 7 14 Zero `-7` Solution :`PH + POH = 14, pH = 14 - pOH because [OH^(-)] = 10^(-7)` `pOH = 7 :. pH = 14-7 = 7`.

Discussion

25879.	The pH of simple sodium acetate and acetic acid buffer is given by, pH=pK_a + log [Salt]/[Acid] K_a of acetic acid= 1.8 xx 10^-5. If [Salt] = [Acid] =0.1 M, the pH of the solution would be about:
Answer» 7 4.7 5.3 1.4 Answer :B

Discussion

25880.	The pH of the resultant solution of 20 mL of 0.1 M H_(3)PO_(4) and 20 mL of 0.1 M Na_(3)PO_(4) is :
Answer» `pK_(a_1)` `pK_(a_2)` `(pK_(a_1)+pK_(a_2))/2` 2 Answer :B

Discussion

25881.	The pH of pure water or neutral solution at 50^@C is………..
Answer» `7.0` `7.13` `6.0` `6.63` Solution :`[H^+][OH^-]=10^(-13.26)` `THEREFORE [H^+]=[OH^-]` `[H^+]^2=10^(-13.26)` `[H^+]=10^((-13.26)/2)` `therefore pH=6.63`

Discussion

25882.	The pH of pure water at 50^@C is ……………..(pK_w = 13.26 at 50^@C):
Answer» 6 6.63 7 7.13 Answer :B

Discussion

25883.	The pH of pure water at 50^@ C is (K_w -13.26 at 50^@ C)
Answer» `7.0` `7.13` `6.0` `6.63` SOLUTION :`PH = 1/2PK_w`( forpurewater) pH= `1/2xx13.26 = 6.63`

Discussion

25884.	The pH of pure water at 25^@C is
Answer» 0 1 7 14 Answer :C

Discussion

25885.	The pH of pure water at 25^@Cand 35^@C are 7 and 6 respectively. What is the heat of formation of water from H^+and OH^- ?
Answer» 84.55 kcal/mol 84.55 kcal/mol 74.55 kcal/mol None of these Answer :B

Discussion

25886.	The pH of neutral water at 25 ^0 C is 7.0. As the temperature increases, ionization of water increases, however the concentration of H+ions and OH−ions are equal. What will be the pH of pure water at 60^0C?
Answer» Equal to 7.0 Greater than 7.0 Less than 7.0 Equal to ZERO Solution :With INCREASE in temperature the IONISATION of water increases. Therefore the CONCENTRATION of `H^(+)` ions increases and pH will be less than 7.0.

Discussion

25887.	The pHof normal rainwater is
Answer» 6.5 7.5 5.6 3.5 Answer :C

Discussion

25888.	The pH of normal KOH is
Answer» 1 0 14 7 Solution :It is a STRONG BASE.

Discussion

25889.	The pH of (N)/(100) HCl would be approximately
Answer» 1 1.5 2 2.5 Solution :`0.01 M HCL = 10^(-2) M[H^(+)] , PH = 2`.

Discussion

25890.	The pH of mixture of , CH_3COONA + CH_3COOH after adding water shows _____ value:
Answer» Increased Decreased Constant All of the above Answer :C

Discussion

25891.	The pH of millimolar of HCl is………
Answer» 1 3 2 4 Solution :`pH=-LOG[H^+]:[H^+]=10^-3` `THEREFORE pH=log 1-log[H^+]` `=log 1- log10^-3=3`

Discussion

25892.	The pH of millimolar HCl is
Answer» 1 2 3 4 Solution :`PH = log.(1)/(H^(+)), pH = log.(1)/(10^(-3)), pH = 3`.

Discussion

25893.	The pH of fresh milk is 6 when it turns sour the pH
Answer» both the statements individually true and statement II is the correct explanation of statement I both the statements are idividually true but statement II is not correct EXPALNATION of statement I statement I is true but statement II is true statement I is false but statement II is true Solution :In presence of moisture chlorine acts as an oxidising and bleaching agent chlorine REACTS with water forming HCI NASCENT oxygen which changed coloured matter to coloruless matter `CI_(2)+H_(2)Orarr2HCI_O` Colorued matter + Nascent oxygen `rarr` colourless matter

Discussion

25894.	The pH of gastric juice is normally:
Answer» GREATER than 1.5 and LESS than 1.2 less than 1.5 greater than 1 and less than 3 Less than 1 and greater than zero Answer :C

Discussion

25895.	The pH of H_(2)SO_(4)is 2. Its molar concentration is :
Answer» `0.01` `0.005` `0.02` `0.05` ANSWER :B

Discussion

25896.	The ph of fluid in the stomach is :
Answer» `2.0` `7.0` 4.2 9.2 Answer :A

Discussion

25897.	The pH of D_(2)O and H_(2)O at 298 k is
Answer» 7.0,7.0 7.35,7.0 7.0,6.85 6.85.85,7.35 Answer :B

Discussion

25898.	The pH of blood stream is maintained by a proper balance of H_2 CO_3 and NaHCO_3 concentrations. What volume of 5 M NaHCO_3 solution should be mixed with a 10 mL sample of blood which is 2 Min H_2 CO_3, in order to maintain a pH of 7.4?K_a for H_2 CO_3 in blood is 7.8 xx10^(-7)
Answer» `50.20 mL` `62.42 mL` `78.37 mL` `52.41 mL` SOLUTION :Let ussupposethe volumeof `NaHCO_3` mixed beV mL ` THEREFORE ` No. of molesof Na`HCO_3`in V mLof 5 M`NaHCO_3` `=( 5 xx V )/(1000)= 0.005 V ` Noof molesof` H_2CO_3 ` in10mLof 2 M`H_2CO_3 = ( 2 xx 10 )/( 1000 ) = 0.02` NowfromHenderson.sequation, `pH = pK_a + log(["SALT "])/(["Acid"])` `7.4 =- log( 7.8 xx 10^(-7 ) ) + log ( 0.005V )/( 0.02)` `7.4 = 6.10 79 +log( 0.005V )/( 0.02)` ` 1.2921= log( 0.005 V )/( 0.02)or( 0.005V )/( 0.02 )= 19.5929` ` thereforeV= 78.37mL`

Discussion

25899.	The pH of blood stream is maintained by a proper balance of H_(2)CO_(3) and NaHCO_(3) concentrations. What volume of 5 M NaHCO_(3) solution, shnould be mixed with 10 mL sample of blood, which is 2 M in H_(2)CO_(3) in order to maintain a pH of 7.4 (K_(a)for H_(2)CO_(3)in blood =7.8xx10^(-7))
Answer» 40 mL 38 mL 50 mL 79 mL Answer :D

Discussion

25900.	The pH of blood is maintained by CO_2 and H_2CO_3 in the body and chemical constituents of blood.The phenomenon is called:
Answer» Collidal Buffer solution Acidity Salt balance Answer :B

Discussion

Explore topic-wise InterviewSolutions in .

The pH value at which the amino acid does not migrate under the influence of electric field is called …………...........

The pH value of 0.1 M HCl is approximately 1. What will be the approximately pH value of 0.05 MH_(2)SO_(4)

The pH pure water or neutral solution at 50^(@)C is..........(pK_(w) = 13.26 = 13.26 at 50^(@))

The pH of which salt solution is independent of its concentration ? 1 (CH_(3)COO)C_(5)H_(5)NH 2Na_(2)PO_(4) 3.Na_(2)HPO_(4) 4. NH_(4)CN

The pHof water is 7 at 25^(@)C. If water is heated to 50^(@)C, which of the following should be true?

The pH of the solution when 0.2 mole of HCl is added to one litre of a solution containing 0.1 M CH_(3)COOH and 0.1 M CH_(3)COO^(-) is

The pH of water at 25^(@)C is nearly

The pH of the solution produced when an aqueous solution of strong acid pH 5 is mixed with equal volume of an aqueous solution of strong acid of pH 3 is:

The pH of the solution produced by mixing equal volume of 2.0 xx 10^(-3) M HClO_(4) and 1.0 xx 10^(-2) M KClO_(4) is

The pH of the solution obtained by mixing 20mL of 0.01 (M) Ca(OH)_2 and 30mL of 0.1 (M) HCl solution is-

The pH of the solution obtained by dissolving pure sodium chloride water is

The pH of the solution obtained by mixing 100 mL of a solution of pH = 3 with 400 mL of a solution of pH = 4 is

The pH of the solution obtained by mixing 100 mL of a solution of pH = 3 with 400 mL of a solution of pH = 4 is :

The pH of the solution obtained by mixing 10 mL of 10^-1 N HCl and 10 mL of 10^-1 N NaOH is:

The pH of the solution is 4. The hydrogen ion concentration of the solution in mol/litre is

The pH of the solution containing following zwitter ion species is

ThepH of the solution is 3.0 if itspH is changed to 6.0 then the [H^+] of the original solution has to be :

The pH of the solution containing 10 ml of 0.1 N NaOH and 10 ml of 0.05 NH_(2)SO_(4) would be

The pH of the solution: 5ml of (M)/(5), HCl + 10 ml of (M)/(10) NaOH is

The pH of the solution containing 10 mL of 0.1 N NaOH and 10 mLof 0.05 NH_(2)SO_(4)would be

The pH of the bloodstream is maintained by a proper balance of H_2CO_3and NaHCO_3concentrations. What volume of 5 M NaHCO_3solution should be mixed with a 10 mL sample of blood which is 2 M in H_2CO_3 , in order to maintain a pH of 7.4? K_ą for H_2CO_3, in blood is 7.8xx 10^(-7)

The pH of the aqueous solution containing 0.49 gm of H_(2)SO_(4) in one litre is

The pH of the a solution obtained by mixing 50 ml of 0.4 N HCl and 50 ml of 0.2 N NaOH is

The pH of the blood does not appreciably change by small addition of an acid or a base because blood :

ThePhof stomach is:

The pH of solutions of both ammonium acetate and sodium chloride is 7 due to

The pH of solution obtained by mixing equal volumes of two aqueous solutions of pH 5 and pH 3 of the same substance is :

The pH of solution having [OH^(-)] = 10^(-7) is

The pH of simple sodium acetate and acetic acid buffer is given by, pH=pK_a + log [Salt]/[Acid] K_a of acetic acid= 1.8 xx 10^-5. If [Salt] = [Acid] =0.1 M, the pH of the solution would be about:

The pH of the resultant solution of 20 mL of 0.1 M H_(3)PO_(4) and 20 mL of 0.1 M Na_(3)PO_(4) is :

The pH of pure water or neutral solution at 50^@C is………..

The pH of pure water at 50^@C is ……………..(pK_w = 13.26 at 50^@C):

The pH of pure water at 50^@ C is (K_w -13.26 at 50^@ C)

The pH of pure water at 25^@C is

The pH of pure water at 25^@Cand 35^@C are 7 and 6 respectively. What is the heat of formation of water from H^+and OH^- ?

The pH of neutral water at 25 ^0 C is 7.0. As the temperature increases, ionization of water increases, however the concentration of H+ions and OH−ions are equal. What will be the pH of pure water at 60^0C?

The pHof normal rainwater is

The pH of normal KOH is

The pH of (N)/(100) HCl would be approximately

The pH of mixture of , CH_3COONA + CH_3COOH after adding water shows _____ value:

The pH of millimolar of HCl is………

The pH of millimolar HCl is

The pH of fresh milk is 6 when it turns sour the pH

The pH of gastric juice is normally:

The pH of H_(2)SO_(4)is 2. Its molar concentration is :

The ph of fluid in the stomach is :

The pH of D_(2)O and H_(2)O at 298 k is

The pH of blood stream is maintained by a proper balance of H_2 CO_3 and NaHCO_3 concentrations. What volume of 5 M NaHCO_3 solution should be mixed with a 10 mL sample of blood which is 2 Min H_2 CO_3, in order to maintain a pH of 7.4?K_a for H_2 CO_3 in blood is 7.8 xx10^(-7)

The pH of blood stream is maintained by a proper balance of H_(2)CO_(3) and NaHCO_(3) concentrations. What volume of 5 M NaHCO_(3) solution, shnould be mixed with 10 mL sample of blood, which is 2 M in H_(2)CO_(3) in order to maintain a pH of 7.4 (K_(a)for H_(2)CO_(3)in blood =7.8xx10^(-7))

The pH of blood is maintained by CO_2 and H_2CO_3 in the body and chemical constituents of blood.The phenomenon is called: