A particle starts from the extreme position at t = 0 in a SHM. If the time period of motion is 2s & maximum speed is 5ms find the equation of motion.(a) x = 1.59cos(πt)(b) x = 1.59sin(πt)(c) x = 2.5sin(2t)(d) x = 2.5cos(2t)This question was addressed to me in final exam.I would like to ask this question from Simple Harmonic Motion in section Oscillations of Physics – Class 11

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51.	A particle starts from the extreme position, at t = 0, in a SHM. If the time period of motion is 2s & maximum speed is 5m/s, find the equation of motion.(a) x = 1.59cos(πt)(b) x = 1.59sin(πt)(c) x = 2.5sin(2t)(d) x = 2.5cos(2t)This question was addressed to me in final exam.I would like to ask this question from Simple Harmonic Motion in section Oscillations of Physics – Class 11
Answer» CORRECT ANSWER is (a) x = 1.59cos(πt) Easiest explanation: T = 2s. ∴ W = 2π/T =s^-1.Aw = 5. ∴ A = 5/π metre.x = 5/π sin(πt + a), where is PHASE constant.At t = 0, x = A. Thus, a = π/2.x = 5/π sin(πt + π/2)= 5/π cos(πt) = 1.59cos(πt).

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