52671 + Interview Questions in Chemistry in Class 11

1.	How much PCl_(5) must be added to a one litre vessel at 250^(@)C in order to obtain a concentration of 0.1 mole of chlorine ? Equilibrium constant for the dissociation of PCl_(5) " at " 250^(@)C " is " 0.0414.
Answer» Solution :`{:(,PCl_(5),HARR,PCl_(3),+,Cl_(2)),("Intial","a mole",,,,),(" At EQM.",(a-01),,01,,01 "mol " L^(-1)):}` `K_(C) = ([PCl_(3)][CL_(2)])/([PCl_(5)]) , 1.e., 00414 = (01 xx 01)/(a-01)` This gives a = `03415` mole

Discussion

2.	How much PCl_(5) must be added to a one litre vessel at 250^(@)C in order to obtain a 35 concentration of 0.1 mol of Cl_(2)? K_(c) for PCl_(5) hArr PCl_(3)+Cl_(2) is 0.0414 mol L^(-1)
Answer» Solution :`{:(,PCl_(5),hArr,PCl_(3),+,Cl_(2)),("INITIAL moles",a,,0,,0),("moles at",(a-0.1),,0.1,,0.1),("EQUILIBRIUM",,,,,):}` `:. K_(c)=(0.1/1xx0.1/1)/((a-0.1)/1) ( :' "volume is" 1 L)` `0.0414=0.01/((a-0.1))` or `a=0.3415 "mol"`

Discussion

3.	How much oxygen is required for complete combustion of 560 g of ethene?
Answer» 6.4 kg 1.92 Kg 2.8 kg 9.6 kg Solution :`underset(28G)(C_2H_4)+underset(3xx32=96g)(3O_2) to 2CO_2 + 2H_2O` 28 G of `C_2H_4` REQUIRES 96g of `O_2` 560 g of `C_2H_4` requires `96/28xx560` =1920g or 1.92kg of `O_2`

Discussion

4.	How much of lime, CaO can be obtained by the calcination of 400 gm of lime stone?
Answer» ANSWER :224gm

Discussion

5.	How much of 0.3 M ammoniumhydroxide should be mixed with 30 mL of 0.2 M solution of ammonium chloride to give a buffer solution of pH 10. Given pK_(b) for NH_(4)OH is 4.75.
Answer» Solution :`pOH = 14 - PH = 14 - 0 = 4 ` `pOH = pK_(b) + log .(["Salt"])/(["Base"]), 4= 4.75 + log.(["Salt"])/(["Base"]) or log.(["Salt"])/(["Base"]) = - 0.75 = 1.25 or (["Salt"])/(["Base"]) = 0.1778` i.e.,`("Moles of salt")/("Moles of base")=0.1778 or ((0.2)/(1000)xx30)/((0.3)/(1000)xxV)=0.1778` or `V = 112.5 ML`

Discussion

6.	How much of 0.3 M ammonium hydroxide should be mixed with 30 mL of 0.2 M solution of ammonium chloride to give buffer solutions of pH 8.65 and 10 (pK_b = 4.75) ?
Answer» SOLUTION :For BASIC buffer solution, `PH=14-pK_b+"LOG""[Base]"/"[Salt]"` pH=14-4.75 +log `"[Base]"/"[Salt]"` or log `"[Base]"/"[Salt]"` = pH-9.25 (i)For suffer of pH=8.65 log `"[Base]"/"[Salt]"`=8.65-9.25 or `"[Base]"/"[Salt]"` =Antilog (-0.60)=0.25 or `([NH_4OH])/([NH_4Cl])=((0.3xxV)/1000)/((0.2xx30)/1000)`=0.25 `V=(0.25xx0.2xx30xx1000)/(0.3xx1000)` =5.02 ML Similarly for solution of pH =10 log `"[Base]"/"[Salt]"` =10-9.25 `"[Base]"/"[Salt]"` =antilog 0.75=5.62 `therefore ((0.3xxV)/1000)/((0.2xx30)/1000)=5.62` `therefore V=(5.62xx0.2xx30xx1000)/(0.3xx1000)` =12.94 mL

Discussion

7.	How much of 0.3 MNH_(4) should be mixed with 30 mL of NH_(4)Cl to give a buffer solution of pH10.pk_(b)" for " NH_(4)OH "is " 4.75.
Answer» ANSWER :`V = 112.6` ML

Discussion

8.	How much (NaN)_(3) must be weighed out to make 50 ml of an aqueous solution containing 70 mg of Na^(+) per mL?
Answer» `12.394` G `1.29` g `10.934` g `12.934` g Answer :D

Discussion

9.	How much nitrogen is evolved when one gm of NH_(4)Cl is heated with borax strongly ?
Answer» Solution :DOESNOT EVOLVE nitrogen `(N_(2))` gas.

Discussion

10.	How much mass of sodium acetate is required to make 250 mL of 0.575 molaraqueous solution?
Answer» 11.79 g 15.38 g 10.81 g 25.35 g Solution :MOLAR MASS of sodium ACETATE `(CH_3COONa)` =82.0245 g/mol Mass of `CH_3COONa` required to make 250 mL of 0.575M solution `=(0.575xx82.0245xx250)/(1000)=11.79g`

Discussion

11.	How much iron can be theoretically obtained by the reduction of 1 kg ofFe_2O_3 Atomic mass of Fe = 55.8.
Answer» SOLUTION :0.699 KG

Discussion

12.	How much hydrogen will be obtained from a mixture containing 8 grams of LiH and 21 grams of CaH_2
Answer» SOLUTION :`8 gm to 2gm` `CaH_2 + 2H_2O to Ca(OH)_2 + 2H_2` `42 gm to 4 gm` `21 g m to 2 gm`

Discussion

13.	How much heat is reuired to convert 5.0 g of ice at -10.0^(@) C to liquid water at 15.0^(@) C ? (Assume heart capacities are indendent o ftemperature.)
Answer» `4.2xx10^(2)J` `2.1xx10^(3)J` `9.3xx10^(3)J` `3.8xx10^(4)J` ANSWER :b

Discussion

14.	How much heat energy must be supplied to change36 g of ice at 0^(@)C to Water at room temperature 25^(@)C? Data for Water DeltaH_("fusion")^(@)=9Kj//mol, c_(p("liquid"))=4JK^(-1)g^(-1)
Answer» 18KJ 3.6Kj 22KJ 21.6Kj Answer :d

Discussion

15.	How much gm of bleaching powder required for chlorination of 1000 lit water ?
Answer» 5 GM 5 KG 50 gm 0.5 gm Solution :5 gm

Discussion

16.	How much gm water required to prepare 10% w/w solution of HCl by dissolving 36.5 gm HCl.
Answer» ANSWER :328.5 GM

Discussion

17.	How much energy is required to ionise a hydrogen atom if the electron occupies n=5 orbit ? Compare your answer with the ionisation energy of hydrogen atom (energy required to remove the electron from n=1 orbit).
Answer» Solution :`E_(n)=-(21.8xx10^(-19))/n^(2)" J ATOM"^(-1)` For ionization from 5TH ORBIT, `n_(1)=5, n_(2)=OO` `:. Delta E=E_(2)-E_(1)=-21.8xx10^(-19) (1/n_(2)^(2)-1/n_(1)^(2))=21.8xx10^(-19) (1/n_(1)^(2)-1/n_(2)^(2))=21.8xx10^(-19) (1/5^(2) -1/oo)` `=8.72xx10^(-20) J` For ionization from 1st orbit, `n_(1)=1, n_(2)=oo` `Delta E'=21.8xx10^(-19) (1/1^(2)-1/oo)=21.8xx10^(-19) J` `(Delta E')/(Delta E)=(21.8xx10^(-19))/(8.72xx10^(-20))=25` Thus, the energy required to remove electron from 1st orbit is 25 times than that required to remove electron from 5th orbit.

Discussion

18.	How much energy will be released when a sodium ion and a chloride ion, originally at infinite distance are brought together to a distance of2. 76 Å ( the shortest distance fo approach in a sodium chloride crystal ? Assume that the ions act as point charges , each with a mangitude of1. 60 xx 10^(-19) C ( the electronic charge ) Also if lattice enrgy of Nacl is185kcal , how the lower value obtained per mole by above calculation can be explained ?
Answer» SOLUTION :119.595 KCAL ,

Discussion

19.	How much energy is required for the removal of the only electron present in the hydrogen atom ?
Answer» SOLUTION :`Delta E = E_(oo) - E_(1) = 0 - (-21.8 xx 10^(-19)J) = 2.18 xx 10^(-19) J`

Discussion

20.	Calculate the ionisation energy of hydrogen atom as well as energy needed to promote its electron from first energy level to third energy level
Answer» SOLUTION :Ionizationenthalpy n=5 forionization n`=prop=n_(F )` in initialelectron is inn=5so `n_(i)=5 ` hydrogen z=1 `Delta E = 2.18 xx 10^(18)((1)/(n_(1)^(2) ) - (1)/(n_(f )^(2)))= IE_(5)` `=2.18 xx 10^(18)((1)/(5^(2)) - (1)/(prop^(2)))` `=(2.18 xx 10^(18))/( 25) J` tibalanceionisationenthalpy of `IE_(5) ` and `IE_(1)` : `(1E_(5))/( 1E_(1)) = (8.72 xx 10^(20)J )/( 2.18 xx 10^(18) J) = 4.-036 xx 10^(2)= 0.04` ionizationenthalpyof n=1compareto n=5is0.04 for`n_(5)`LESSAND `n_(1)` moreionizationenthalpy `IE(5): IE (1)` `=0.04 :1` `4:100` `1: 25` So IE (1) isapprox25 timemorethan1E(5 )`

Discussion

21.	How much energy is released when 6 mole of octane is burnt in air? GivenDelta H_(f)^(0) " for " CO_(2(g)), H_(2)O_((g)) and C_(8)H_(18(l)) respectively are -390, -240 and +160 KJ/mol
Answer» `-32.6 MJ` `-37.4 MJ` `-35.5 MJ` `-20.00 MJ` SOLUTION :`C_(8) H_(18) + (25)/(2) O_(2) rarr *CO_(2) + 9H_(2)O` `Delta H_("comb") = 8 Delta H_(f_(CO_(2))) + 9Delta H_(f_(H_(2)O)) - Delta H_(f_(C_(8)H_(18)))` `= 8 xx(-390) + 9 xx (-240) - (+160)` `= --5400` kJ/mol For 6 moles `= -32640kJ = - 32.6` MJ

Discussion

22.	How much copper sulphate will be required to saturate 100g of a dilute aqueous solution of CuSO_(4) at 25^(@)C if 10g of the dilute solution leave on evaporation and drying 1.2g of anhydrous CuSO_(4) ? The solubility of CuSO_(4) in water at 25^(@)C is 25.
Answer» Solution :100g of dilute solution of `CuSO_(4)` CONTAIN `=1.2 xx 10 = 12.0 g CuSO_(4)` MASS of water present in dilute solution `=(100-12)=88g` To saturate 100g of water, `CuSO_(4)` required = 25g So, to saturate 88g of water, `CuSO_(4)` required `= (25)/(100)xx88` `=22g` Thus, the mass of `CuSO_(4)` to be ADDED to 100g of dilute solution to saturate it `= (22-12)=10g`.

Discussion

23.	How much copper can be obtained from 100 g of CuSO_4
Answer» Solution :Molecular MASS of `CuSO_4=63.5+32+64=159.5` Mass of CU PRESENT in `1.59.5 G CuSO_4=63.5/159.5xx100=39.8 g` Mass of Cu present in`100gCuSO_4=63.5/159.5xx100=39.8g`

Discussion

24.	How much copper can be obtained from 100 g of copper sulphate (CuSO_(4))?
Answer» Solution :MOLAR mass of `CuSO_(4) = 63.5 + 32 + (4 xx 16) = 159.5 G mol^(-1)` 1 mole (159.5 g) of `CuSO_4` contains 1 g atom (63.5 g) of copper. Amount of copper that can be obtained from 100 g of copper sulphate. `=(63.5)/159.5 xx 100 = 39.81 g`

Discussion

25.	How much copper can be obtained from 100 g of copper sulphate (CuSO_(4)) ?
Answer» SOLUTION :MOLECULARMASS of `CuSO_(4) = 63.54+32.06+(4 xx 16)` `= 159.6g` mol In `159.6 g CuSO_(4) rarr 63.54g` CU obtained `:. 100 g CuSO_(4) = "" (?)` `= (63.54xx100)/(159.6)= 39.81 g Cu`

Discussion

26.	How much copper can be obtained from 100 g of anhydrous copper sulphate?
Answer» SOLUTION :Anhydrous COPPER sulphate = `CuSO_(4)` MOLECULAR mass of `CuSO_(4)` = 63.5+ 32+ (16 `xx` 4) = 63.5 + 32 + 64 = 159.5 g 159.5 g of `CuSO_(4)`contains 63.5 g of copper. `:. `100 g of `CuSO_(4)` contains `63.5/159.5 xx 100 = 0.39811xx100` = 39.81 g of copper

Discussion

27.	How much Ca(NO_(3))_(2) in mg must be present in 50 ml of a solution with 2.35 ppm of Ca?
Answer» `0.1175` `770.8` `4.7` `0.48` Solution :Water density 1g/ML `10^(6)g` (`10^(6)` ml) water CONTAINS 2.35g CA 50ml (50G) water contains `(50xx2.35)/(10^(6))GCA` `=(50xx2.35)/(10^(6))xx10^(3)mgCa=0.1175gCa` `40gCa-164gCa(NO_(3))_(2)` `0.1175Ca-0.48g Ca(NO_(3))_(2)`

Discussion

28.	How methane reacts with Cl_(2) in the presence of light ?
Answer» Solution :`underset("Methane")(CH_(4) + ) Cl_(2) OVERSET("light") underset(HCl)(to) underset("CHLORIDE") underset("methyl")(CH_(3)Cl) overset(Cl_(2)) underset(-HCl)(to) underset("chloride") underset("Methylidene")(CH_(2)Cl_(2))overset(Cl_(2))underset(HCl)(to) underset("CHLOROFORM") (CHCl_(3)) overset(Cl_(4)) underset(-HCl)(to) underset("Carbon tetra- chloride")(C Cl_(4))`

Discussion

29.	How may the conductivity of an intrinsic semiconductor by increased ?
Answer» Solution :The conductivity can be increased by DOPING either by ADDING electron rich impurities like that that of P, As etc. giving n -typesemicomductor or by adding electron deficit impurities like thatof B, Al etc. giving p -type semiconductor.

Discussion

30.	How may of the following reagents can be used to distinguish between hex-1-yne and hex-2-yne? (a). CuCl//NH_(3) (b). AgNO_(3)//NH_(3) (c). Na metal (d). Neutral FeCl_(3) (e). Fehling's reagent
Answer» ANSWER :3

Discussion

31.	How may of following reactions are hydrolysis reactions ?
Answer» ANSWER :7

Discussion

32.	How may octahedral voids are there in 1 mole of a compound having cubic close packed structure ?
Answer» SOLUTION :No. of OCTAHEDRAL VOIDS = No, if ATOMS in the pocking = 1 mole = ` 6.02 xx 10^(23)`

Discussion

33.	How may moles of oxygen are present in 400 cm^(3) sample of the gas at a pressure of 760 mm of Hg at a temperature of 310K. (The value of R 1 s 8.31 kP a dm^(-3) K^(-1) "mol"^(-1))
Answer» Solution :Here value of R is given in SI unit : pressure and VOLUME is expressed in Kpa and `DM^(3)` . Thus `P=760 mm 1013 kPa, v=400 cm^(3) =400xx10^(-3) dm^(3)` 04dm^(3)` According to ideal GAS equation. `pv=nRT` `n=(pv)/(RT)=(1013xx040)/(831xx310)=001572` `:. n=1 1*57xx10^(-2) "mol"`

Discussion

34.	How may atoms can be assigned to its unit cell if an element forms (i)body-centred cubic cell (ii) a face -cenrtred cubic cell.
Answer» Solution :Atoms per unit cell in a body-centred CUBIC cell = `8 xx 1/8` ( from corners) + 1 ( from body CENTRE )= 2 Atoms per unit in a FACE- centred cubic cell =` 8xx 1/8 ` ( from corners) + ` 6 xx 1/2` ( from CENTRES ) = 4

Discussion

35.	How may lonepairs and bond pairs are present in SO_(4)^(2-) and H_(3)O^(+)?
Answer» Solution :`SO_(4)^(2-)` contains 6 bond pairs and 10 LONEPAIRS `H_(3)O^(+)` contains 3 bond pairs and 1 lone PAIR

Discussion

36.	How many years would it take to spend Avogadro Number of rupees at the rate of 10 lakh rupees per second ?
Answer» Solution :Avogadro.s Number = `6.022 XX 10^23` If 10 lakh (`10^6`) rupees are spent every second, the number of SECONDS taken in spending `6.022 xx 10^(23)` rupees `=(6.022 xx 10^(23))/10^(6) = 6.022 xx 10^(17)` `therefore` 1 second = `3.169 xx 10^(-8) xx 6.022 xx 10^(17)` `=1.908 xx 10^(10)` YEARS Hence, it will take `1.908 xx 10^10` years to spend Avogadro number of rupees at the rate of 10 lakh rupees PER second.

Discussion

37.	How many water molecules present in Epsom salt.
Answer» SOLUTION :`MgSO_4. 7H_2O`

Discussion

38.	How many volume of Hydrogen chlorid form by combine with one volume of hydrogen and one volume of chloride
Answer» ANSWER :2 VOLUME

Discussion

39.	How many volume of ammonia produece by combine of one volume Nitrogen and three volume of Hydrogen ?
Answer» ANSWER :2 VOLUME

Discussion

40.	How many valence electrons are present around phosphorous is PCl_(5)?
Answer» SOLUTION :`P-15=1s^(2) 2s^(2) 2p^(6)//3S^(2)3p^(3)`. TEN electrons

Discussion

41.	How manyunpairedelectronsare presentin p -orbitalof oxygen?
Answer» 0 1 2 3 Answer :C

Discussion

42.	How many unpaired electrons are present in oxygen molecule ?
Answer» 0 1 2 3 Answer :C

Discussion

43.	How many unpaired electrons are present in divalent manganese ion ?
Answer» ANSWER :5

Discussion

44.	How many unpaired electrons are present in a ground state?
Answer» 6 4 2 0 Solution :N/a

Discussion

45.	How many unpaired electrons are in a Fe^(2+) ion in the ground state?
Answer» 0 2 4 6 Answer :C

Discussion

46.	How many unpaired electorns are present in the ground state of fe^(3+)(z=26),Mn^(2+)(Z=25) and argon(Z=18)?
Answer» Solution :`F to Fe^(3+)+3e^(-)` Fe(Z=26)`Fe^(3+)`=number of electrons=23 `1s^(2)2s^(2)2p^(6)3P^(6)3D^(6)4s^(2)`for Fe atom. `1s^(2)2s^(2)2p^(6)3s^(6)3d^(5) for Fe^(3+)ion.` So,it CONTAIN 5 unpaired electrons. `Mn toMn^(2+)+2e^(-)` Number of unpaired electrons in `Mn^(2+)=5` AR(Z=18)Electronic configuration is `1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)` All ORBITALS are completely filled.So,no unpaired electrons in it.

Discussion

47.	How many unpaired electorns are present in the ground state of(i)Cr^(2+)(Z=24)(ii)Ne(Z=10)
Answer» Solution :(i)`Cr(Z=24)``1S^(2)2s^(2)2p^()3s^(2)3p^(6)3d^(5)4s^(1)` `Cr^(3+)-1s^(2)2s^(2)2p^()3s^(2)3p^(6)3d^(4)` It CONTAINS 4 UNPAIRED electrons. (ii)Ne(Z=10)`1s^(2)2s^(2)2p^(6)`.No unpaired electrons in it.

Discussion

48.	How many unit cells are present in a cube-shaped ideal crystal of NaCl of mass 1.00 g ? [Atomic mass:Na=23,Cl=35.5]
Answer» `2.57times10^(21)`unit CELLS `5.14times10^(21)`unit cells `1.28times10^(21)`unit cells Solution :No. of `NA^(+)Cl^(-)`units in ONE unit cell =4 Mass of 1 unit cell `=(4(23+35.5))/(6.02times10^(23))g=((58.5times4)/(6.02times10^(23)))g` No. of unit cells in 1 g `=(6.02times10^(23))/(58.5times4)=602/(58.5times4)=10^(21)=2.57times10^(21)`

Discussion

49.	How many unit cells are present in a cube shaped ideal crystal of NaCl of mass 1g ? (atomic masses : Na = 23, CI=35.5)
Answer» `1.7 XX 10^21)` UNIT cells `2.57 xx 10^(21)` unit cells `5.14 xx 10^(21)` unit CELL `1.28 xx 10^(21)` unit cell Answer :B

Discussion

50.	How many unit cells are present in a cube shaped ideal crystal of NaCl of mass 1.00 g ? Atomic masses : Na=23, Cl=3.55)
Answer» `1.28times10^(21)` `1.71times10^(21)` `5.14times10^(21)` `2.57times10^(21)` Solution :Mass of ONE unit cell (m)=`"VOLUME "times "density"` =`a^(3)timesd=a^(3)times(MZ)/(N_(0)a^(3))=(MZ)/(N_(0))` `therefore m=(58.5times4)/(6.02times10^(23))G` Number of unit CELLS in `1 g=1/m` `=(6.02times10^(23))/(58.4times4)=2.57times10^(21)`

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

How much PCl_(5) must be added to a one litre vessel at 250^(@)C in order to obtain a concentration of 0.1 mole of chlorine ? Equilibrium constant for the dissociation of PCl_(5) " at " 250^(@)C " is " 0.0414.

How much PCl_(5) must be added to a one litre vessel at 250^(@)C in order to obtain a 35 concentration of 0.1 mol of Cl_(2)? K_(c) for PCl_(5) hArr PCl_(3)+Cl_(2) is 0.0414 mol L^(-1)

How much oxygen is required for complete combustion of 560 g of ethene?

How much of lime, CaO can be obtained by the calcination of 400 gm of lime stone?

How much of 0.3 M ammoniumhydroxide should be mixed with 30 mL of 0.2 M solution of ammonium chloride to give a buffer solution of pH 10. Given pK_(b) for NH_(4)OH is 4.75.

How much of 0.3 M ammonium hydroxide should be mixed with 30 mL of 0.2 M solution of ammonium chloride to give buffer solutions of pH 8.65 and 10 (pK_b = 4.75) ?

How much of 0.3 MNH_(4) should be mixed with 30 mL of NH_(4)Cl to give a buffer solution of pH10.pk_(b)" for " NH_(4)OH "is " 4.75.

How much (NaN)_(3) must be weighed out to make 50 ml of an aqueous solution containing 70 mg of Na^(+) per mL?

How much nitrogen is evolved when one gm of NH_(4)Cl is heated with borax strongly ?

How much mass of sodium acetate is required to make 250 mL of 0.575 molaraqueous solution?

How much iron can be theoretically obtained by the reduction of 1 kg ofFe_2O_3 Atomic mass of Fe = 55.8.

How much hydrogen will be obtained from a mixture containing 8 grams of LiH and 21 grams of CaH_2

How much heat is reuired to convert 5.0 g of ice at -10.0^(@) C to liquid water at 15.0^(@) C ? (Assume heart capacities are indendent o ftemperature.)

How much heat energy must be supplied to change36 g of ice at 0^(@)C to Water at room temperature 25^(@)C? Data for Water DeltaH_("fusion")^(@)=9Kj//mol, c_(p("liquid"))=4JK^(-1)g^(-1)

How much gm of bleaching powder required for chlorination of 1000 lit water ?

How much gm water required to prepare 10% w/w solution of HCl by dissolving 36.5 gm HCl.

How much energy is required to ionise a hydrogen atom if the electron occupies n=5 orbit ? Compare your answer with the ionisation energy of hydrogen atom (energy required to remove the electron from n=1 orbit).

How much energy is required for the removal of the only electron present in the hydrogen atom ?

Calculate the ionisation energy of hydrogen atom as well as energy needed to promote its electron from first energy level to third energy level

How much energy is released when 6 mole of octane is burnt in air? GivenDelta H_(f)^(0) " for " CO_(2(g)), H_(2)O_((g)) and C_(8)H_(18(l)) respectively are -390, -240 and +160 KJ/mol

How much copper sulphate will be required to saturate 100g of a dilute aqueous solution of CuSO_(4) at 25^(@)C if 10g of the dilute solution leave on evaporation and drying 1.2g of anhydrous CuSO_(4) ? The solubility of CuSO_(4) in water at 25^(@)C is 25.

How much copper can be obtained from 100 g of CuSO_4

How much copper can be obtained from 100 g of copper sulphate (CuSO_(4))?

How much copper can be obtained from 100 g of copper sulphate (CuSO_(4)) ?

How much copper can be obtained from 100 g of anhydrous copper sulphate?

How much Ca(NO_(3))_(2) in mg must be present in 50 ml of a solution with 2.35 ppm of Ca?

How methane reacts with Cl_(2) in the presence of light ?

How may the conductivity of an intrinsic semiconductor by increased ?

How may of the following reagents can be used to distinguish between hex-1-yne and hex-2-yne? (a). CuCl//NH_(3) (b). AgNO_(3)//NH_(3) (c). Na metal (d). Neutral FeCl_(3) (e). Fehling's reagent

How may of following reactions are hydrolysis reactions ?

How may octahedral voids are there in 1 mole of a compound having cubic close packed structure ?

How may moles of oxygen are present in 400 cm^(3) sample of the gas at a pressure of 760 mm of Hg at a temperature of 310K. (The value of R 1 s 8.31 kP a dm^(-3) K^(-1) "mol"^(-1))

How may atoms can be assigned to its unit cell if an element forms (i)body-centred cubic cell (ii) a face -cenrtred cubic cell.

How may lonepairs and bond pairs are present in SO_(4)^(2-) and H_(3)O^(+)?

How many years would it take to spend Avogadro Number of rupees at the rate of 10 lakh rupees per second ?

How many water molecules present in Epsom salt.

How many volume of Hydrogen chlorid form by combine with one volume of hydrogen and one volume of chloride

How many volume of ammonia produece by combine of one volume Nitrogen and three volume of Hydrogen ?

How many valence electrons are present around phosphorous is PCl_(5)?

How manyunpairedelectronsare presentin p -orbitalof oxygen?

How many unpaired electrons are present in oxygen molecule ?

How many unpaired electrons are present in divalent manganese ion ?

How many unpaired electrons are present in a ground state?

How many unpaired electrons are in a Fe^(2+) ion in the ground state?

How many unpaired electorns are present in the ground state of fe^(3+)(z=26),Mn^(2+)(Z=25) and argon(Z=18)?

How many unpaired electorns are present in the ground state of(i)Cr^(2+)(Z=24)(ii)Ne(Z=10)

How many unit cells are present in a cube-shaped ideal crystal of NaCl of mass 1.00 g ? [Atomic mass:Na=23,Cl=35.5]

How many unit cells are present in a cube shaped ideal crystal of NaCl of mass 1g ? (atomic masses : Na = 23, CI=35.5)

How many unit cells are present in a cube shaped ideal crystal of NaCl of mass 1.00 g ? Atomic masses : Na=23, Cl=3.55)