52671 + Interview Questions in Chemistry in Class 11

1.	The number of electrons involved in the reduction of nitrate ion to hydrazine is ........
Answer» Solution :`NO_(3)^(-) rarr N_2H_4` To BALANCE N atoms, multiple `NO_3^(-)` by 2,we have `2overset(+5)(NO_3^(-))rarroverset(-2)(N_2H_4)` `{:("Total O.N "= 2x×15 ,"Total O.N" = 2 xx -2),(=+10 ,=-4):}` To balance O.N. ADD `14e^(-) " to " ` L.H.S we have `2NO_(3)^(-)+ 14e^(-) rarr N_2H_4`

Discussion

2.	The numberof electrons involved in the half reaction Cr_(2)O_(7)^(2-)rarr2Cr^(3+) is
Answer» 3 6 5 10 Answer :B

Discussion

3.	The number of electrons in the atom which has 20 protons in the nucleus
Answer» 20 10 30 40 Solution :NUCLEUS of 20 PROTONS ATOM have 20 ELECTRONS

Discussion

4.	The number of electrons in [K^(40)]^(-1) are
Answer» 18 19 20 40 Solution :K (Z = 19) has 19 electrons. Number of electrons in `K^(-1)` is 19 + 1 = 20.

Discussion

5.	The number of electrons in one molecule of CO_2 are
Answer» 22 44 66 88 Solution :ONE MOLECULE of `CO_2` have 22 ELECTRONS.

Discussion

6.	The number of electrons in an atom with atomic number 105 having (n +l) = 8 is
Answer» 15 17 19 21 Solution :The electronic configuration of element with atomic number 105 is `1s^(2), 2s^(2) 2p^(6), 3s^(2) 3p^(6) 3d^(10), 4s^(2) 4p^(6) 4d^(10) 4F^(14), 5s^(2) 5p^(6) 5d^(10) 5f^(14), 6s^(2) 6p^(2) 6d^(3) 7s^(2)` For `5f, (n + L) = 5 + 3 = 8`, ELECTRONS present = 14 For `6d, (n + l) = 6 + 2 = 8`, Electrons present = 3

Discussion

7.	The number of different spatial arrangements for the orbital with 1 = 2 is
Answer» 1 3 5 7 Solution :`m_l =-L ` to `l=-2, -1 , 0 , + 1, +2`

Discussion

8.	The number of dichloro isomeric products possible of dichorination of neo-pentane is
Answer» Solution : 2,3,4,6, have chiral carbon this is have OPTICAL isomers. So FOUR optical isomers so TOTAL 5 + 4 = 9.

Discussion

9.	Total number of stereoisomers of the following compound is CHCl=CH-CH(CH_(3))C_(2)H_(5)
Answer» 2,2 1,1 1,2 2,1 Solution :DIASTEREOMERIC pair (cis and TRANS) = 1 Enantiomeric pair for ONE chiral centre (R and S) = 1

Discussion

10.	The number of d-electron retained in Fe^(2)("At no. of" Fe =26) ion is.
Answer» 3 4 5 6 Answer :D

Discussion

11.	The number of d-electrons retained in Fe^(3+) (At. No. of Fe = 26) ion is
Answer» 3 4 5 6 Answer :C

Discussion

12.	The number of d-electrons in Fe^(2=) (Z = 26)is notequal to the number p of electrons in which one of the following?
Answer» p-electronsinCl (Z= 17) d - electronsin FE (Z =26) p- electronsin Ne (Z =10) s- electronsin MTG (Z = 12) Solution :p-electronsinCl (Z= 17) `Fe^(2+) ` has 6 d-electrons. (Option - A) has 11 p - el electrons , which are not equal to six d-electrons in `Fe^(2-)`

Discussion

13.	Thenumber of d-electrons in Fe^(2+)(Z= 26)is notequal to thenumber of theelectronsin whichone ofthe following?
Answer» d- ELECTRONSIN Fe (Z= 26) p- electronsin Ne(Z = 10 ) s-electrons in Mg (Z= 12 ) p -electrons inC1 (Z =17) Solution :(a) E.C of Fe (Z=26) `= 1S^(2) 2S^(2)2p^(6)3s^(2)3p^(6)3D^(6)4s^(2)` `:. `E.C. of `Fe^(2+)= 1s^(2)2s^(2)2p^(6)3s^(2)3p^(6)3d^(6)` Ithas sixp- electrons. ( c) E.C. of Mg (Z=12)= `1s^(2)2s^(2)2p^(6)3s^(2)` It haseleven( 6+5)p-electrons . NowC1 haseleven p-elements but `Fe^(2+)` has six d- electrons. Thereforeoption (d)iscorrect.

Discussion

14.	The number of d-electrons in Fe^(2+) (Z = 26) is not equal to the number of electrons in which one of the following ?
Answer» d-electrons in Fe (Z = 26) p-electrons in Ne (Z = 10) s-electrons in Mg (Z = 12) p-electrons in CL (Z = 17) Solution :`._(26)Fe = 1s^(2) 2s^(2) 2P^(6) 3s^(2) 3P^(6) 3d^(6) 4s^(2)` (d - electrons = 6) `Fe^(2+) = 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(6) 3d^(6)` (d-electrons = 6) `._(10)Ne = 1s^(2) 2s^(2) 2p^(6)` (p-electrons = 6) `._(12)Mg = 1s^(2) 2s^(2) 2p^(6) 3s^(2)` (s-electron `= 2 + 2 + 2 = 6`) `._(17)Cl = 1s^(2) 2s^(2) 2p^(6) 3s^(2) 3p^(5)` (p-electrons `= 6 + 5= 11`)

Discussion

15.	The number of correct option is (a) P_(2)O_(5) gtZnO gtMgO gt Na_(2)O_(2) (acidic strenght) (b) TI_(2)O_(3) gt TI_(2)O gtGa_(2)O_(3) gt AI_(2)O_(3)(basic strenght) ( c) MnO gt P_(2)O_(5) gt CrO_(3) gt Mn_(2)O_(7) (ionic character) (d) H_(2)OgtHF gtNH_(3) (melting point) (e) H_(2)O gtHF gtNH_(3) (boiling point) .
Answer» Solution :(B) Wrong Correct ORDER `TI_(2)O gtTI_(2)O_(3) gtGa_(2)O_(3)` ` gtAI_(2)O_(3)` Wrong Correct order `H_(2)Ogt NH_(3) gtHF` .

Discussion

16.	The number of conformational isomers possible of n-butane about C_(2)-C_(3) bond
Answer» ONE FOUR Three Infinite Solution :Infinite DIHEDRAL ANGLES are possible.

Discussion

17.	The number of compounds showing enantiomers among the following compounds is Butan-2-ol, 2-Hydroxypropanoic acid, 2-Methylhexane, 2-Chlorobutane, 2-Bromo-2-chlorobutane, 2-Methylbutanoic acid, isopropyl chloride
Answer» SOLUTION :The COMPOUNDS having chiral CARBON and therefore, SHOWING enantiomers are: Butan-2-ol, 2-Hydroxypropanoic ACID, 2-Chlorobutane, 2-Bromo-2-chlorobutane.

Discussion

18.	The number of compounds which show tautomerism among the following is
Answer» ANSWER :6

Discussion

19.	The number of compounds which are more reactive towards electrophilic substitution than p-xylene? Benzene, Toluene, Mesitylene, o-xylene, m-xylene.
Answer» SOLUTION :ELECTROPHILIC SUBSTITUTION

Discussion

20.	The number of collisions depends on A) mean free pathB) pressure C) temperature
Answer» <P>A, C A,B B,C A, B, C SOLUTION :Frequency of COLLISIONS DEPENDS on `lambda, P , T`.

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21.	The number of cis-trans isomers with molecular formula C_2BrClFI is
Answer» SOLUTION :SIX

Discussion

22.	The number of chiral compounds produced upon monochlorination of 2-methylbutane is :
Answer» 2 4 6 8 Answer :B

Discussion

23.	The number of chain isomers for C_(5)H_(12) is
Answer» 1 2 3 4 Answer :C

Discussion

24.	The number of chain isomers possible for hydrocarbon C_(5)H_(12) is
Answer» 3 5 4 6 Solution :`C_(5)H_(12): UNDERSET("n-Pentane")(CH_(3)CH_(2)CH_(2)CH_(2)CH_(3))` `underset("2-Methylbutane (iso-Pentane)")(CH_(3)-underset(CH_(3))underset(\|)(C)H-CH_(2)-CH_(3))""underset("2,2-Dimethylpropane (neo-Pentane)")(CH_(3)-underset(CH_(3))underset(\|)OVERSET(CH_(3))overset(\|)(C)-CH_(3))`

Discussion

25.	The number of carbon monoxide molecular present in 1 dm^3 at N.T.P. is _________ .
Answer» `6.02xx10^(23)` `6.02xx10^(22)` `0.269xx10^(22)` `2.69xx10^(22)` SOLUTION :22.4 `dm^3` of 'CO' CONTAINS `6.02xx10^(23) ` at N.T.P. Hencenumber of CO MOLECULES PRESENT in 1 `dm^3` at N.T.P `=(6.02xx10^(23))/(22.4) = 2.69 xx10^(22)`

Discussion

26.	The number of C-C sigma bonds present in 1-butyne is
Answer» 2 3 4 5 Answer :B

Discussion

27.	The number of bridge bonds, the maximum number of planar atoms and the number of electrons involved in the formation of bridge bonds in diborane are x, y and z respectively, then (x+y–z) = ?
Answer» Solution :x = 2 (B-H-B bonds) y = 6 (`2B, 4H_(t)`atoms) `z=4 , x+y-z=2+6-4=4`

Discussion

28.	The number of bridge hydrogen atoms in diborane is
Answer» 1 2 3 4 Answer :B

Discussion

29.	Thenumber of atoms presents in 20 g of calciumwill equal to the number of atoms presents in (20 g Ca = (1)/(2) Ca) (Ca = (6.023 xx 10^(23))/(2) = 3.012 xx 10^(23))
Answer» `12 G C` `12.15 g Mg` `24.0 g C` `24.3 gMg` Solution :`24.3 g Mg = 1 mol, so 12.15 g = (1)/(2) mol`

Discussion

30.	The number of atoms presentin 0.1 mole of P_(4) (at mass = 31) are
Answer» `2.4 XX 10^(23)` atoms same as in 0.05 mole of `S_(8)` `6.02 xx 10^(22)` atoms same as in 3.1 g of phosphorus Solution :a) `therefore` 1 mole of `P_(4)` contains phosphorus atoms `=4 xx 6.02 xx 10^(23)` `therefore` 0.1 mole of `P_(4)` contains phosphorous atoms `=4 xx 6.02 xx 10^(23) xx 0.1` `=2.4 xx 10^(23)`atoms

Discussion

31.	The number of atoms present in one mole of an element is equal to Avogadro number. Which of the following element contains the greatest number of atoms ?
Answer» 4g He 49g Na 0.40g Ca 12g He Solution :To compare the number of atoms, we need to CALCULATE the moles as all are monatomic and HENCE, moles `XX N_(A) =` number of atoms. Moles of `4 G He = 4/4 = 1 ` mol `46 g Na = (46)/(23) = 2 `mol `0.40 g Ca =(0.40)/(40) = 0.1 mol` `12 g He = (12)/(4) = 3 `mol Here, 12 g He contains greatest number of atoms as it possess maximum number of moles

Discussion

32.	The number of atoms present in 16 g of oxygen is:
Answer» `6.02 XX 10^(11.5)` `3.01 xx 10^(23)` `3.01 xx 10^(11.5)` `6.02 xx 10^(23)` ANSWER :D

Discussion

33.	The number of atoms present in 142g of Chlorine is
Answer» `6xx110^(23)` `1.2xx10^(24)` `2.4xx10^(24)` `3.6xx10^(24)` ANSWER :C

Discussion

34.	The number of atoms present in 1 g of hydrogen is the same as that in 1 g of oxygen.
Answer» ANSWER :F

Discussion

35.	The number of atoms present in 1 g of hydrogen gas is the same as are present in
Answer» 4 g of Helium 32 g of Oxygen 7 g of Nitrogen 24 g of Carbon Solution :`2 g " ofHydrogen "= 6xx10^(23)" molecules of "H_2` `-=2xx6xx10^(23)" ATOMS of "H_2` `1 g " of HYDROGEN "-= 6xx10^(23)" atoms of Hydrogen "` (a) 4 g He `-= 6xx10^(23)" atoms of He"` (b) `32 g" of "O_2 -=2xx6xx10^(23)" atoms of oxygen"` `= 12xx10^(23)" atoms of oxygen"` ( C) `7 g " of " N_2 -= (2xx6xx10^(23)xx7)/(28)" atoms of " N_2` `=3xx10^(23)" atoms of " N_2` (d) `24 g " of " C -=(6xx10^(23)xx24)/(12)` `= 12xx10^(23)" atoms of carbon"` Correct answer is (a).

Discussion

36.	The number of atoms of hydrogen present in 1.5 mole of H_(2)O is
Answer» 1N 2N 3N 0.5N Answer :C

Discussion

37.	The number of atoms of 0.03 g of aluminium is nearly (Al = 27)
Answer» `6.68 xx10^(20)` `6.68xx10^(21)` `6.68 xx10^(22)` `6.68xx10^(23)` SOLUTION :The number of ATOMS in 0.3 g of AL `=(6.02xx10^(23))/(27) xx0.03` `= 0.668xx10^(21) = 6.68xx10^(20)`

Discussion

38.	The number of atoms is 100 g of a fcc crystal with density ="10.0 g/cm"^3 and cell edge equal to 200 pm is equal to
Answer» `5xx10^24` `5xx10^25` `6xx10^23` `2xx10^25` Solution :`RHO=(ZxxM)/(a^3XX10^(-30)xxN_0)` or `M=(10xx(200)^3xx10^(-30)xx6xx10^23)/4=12` Thus, 12 g CONTAIN=`N_0=6xx10^23` ATOMS `therefore` 100 g will contain `=(6xx10^23)/12xx100=5xx10^24`

Discussion

39.	The number of atoms in a face centred cubic unit cell is:
Answer» 4 3 2 1 Answer :A

Discussion

40.	The number of atoms in 4.25g of NH_(3) is approximately :
Answer» `1 XX 10^(23)` `2XX 10^(23)` `4 xx 10^(23)` `6 xx 10^(23)` SOLUTION :4.25 g of `NH_(3)` (= 0.25 mol) 1 mole of `NH_(3)` have atoms `= 4 xx 6.022 xx 10^(23)` 0.25 mole of `NH_(3)` have atoms `= 4 xx 0.25 xx 6.022 xx 10^(23)` `=6.022 xx 10^(23)`.

Discussion

41.	The number of atoms in 100g of a fcc crystal with density=10gcm^(-3) and cell edge as 200gm, is equal to
Answer» `3xx10^(25)` `5XX10^(24)` `1XX10^(25)` `2xx10^(25)` Solution :(b) We KNOW that, d `(Z.M)/(nxxa^(3))` `N=(4xx100)/(10xx(200xx10^(-10))^(3))` =`5xx10^(24)`

Discussion

42.	The number of atoms in 0.1 mole of triatomic gas is :
Answer» `6.026 xx 10^(22)` `1.806 xx 10^(23)` `3.6 xx 10^(23)` `1.8 xx 10^(22)` Solution :No. of atoms of `= N_(A) xx` No. of moles `xx 3` `= 6.022 xx 10^(23) xx 0.1 xx 3` `=1.806 xx 10^(23)`.

Discussion

43.	The number of atoms in 0.1 mole of a triatomic gas is (N_(A) = 6.02 xx 10^(23) "mol"^(-1))
Answer» `6.026 XX 10^(22)` `1.806 xx 10^(23)` `3.600 xx 10^(23)` `1.800 xx 10^(22)` Answer :B

Discussion

44.	The number of atoms in 0.004 g of magnesium is close to
Answer» 24 `2 xx 10^(20)` `10^(20)` `6.02 xx 10^(23)` Solution :`24.31 g` (gram atomic mass) of MG CONTAIN `6.022 xx 10^(23)` atoms.

Discussion

45.	The number of atoms collinear in H_(3)C-C-=C-C-=C-CH_(3) is
Answer» Four Six TEN Eight Solution :Six CARBON ATOMS present in the same PLACE.

Discussion

46.	The number of benzene isomers for C_(8)H_(10) ?
Answer» 1 2 3 4 Answer :D

Discussion

47.	The number of angular nodal planes are same in the orbitals:
Answer» 3P and 4p 3s and 4d 4s and 3p 4s and 3D SOLUTION :Angular NODES = `l`

Discussion

48.	The number of alkene (structural) isomers possible, each of which on hydrogenation gives 2-methyl pentane
Answer» SOLUTION :4-Structural ALKENES POSSIBLE

Discussion

49.	The number of alkali metals which is (are) radioactive.
Answer» SOLUTION :FR is RADIO ACTIVE.

Discussion

50.	How many structural isomers exist with the formula C_(4)H_(10)O?
Answer» 7 6 5 3 Answer :D

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

The number of electrons involved in the reduction of nitrate ion to hydrazine is ........

The numberof electrons involved in the half reaction Cr_(2)O_(7)^(2-)rarr2Cr^(3+) is

The number of electrons in the atom which has 20 protons in the nucleus

The number of electrons in [K^(40)]^(-1) are

The number of electrons in one molecule of CO_2 are

The number of electrons in an atom with atomic number 105 having (n +l) = 8 is

The number of different spatial arrangements for the orbital with 1 = 2 is

The number of dichloro isomeric products possible of dichorination of neo-pentane is

Total number of stereoisomers of the following compound is CHCl=CH-CH(CH_(3))C_(2)H_(5)

The number of d-electron retained in Fe^(2)("At no. of" Fe =26) ion is.

The number of d-electrons retained in Fe^(3+) (At. No. of Fe = 26) ion is

The number of d-electrons in Fe^(2=) (Z = 26)is notequal to the number p of electrons in which one of the following?

Thenumber of d-electrons in Fe^(2+)(Z= 26)is notequal to thenumber of theelectronsin whichone ofthe following?

The number of d-electrons in Fe^(2+) (Z = 26) is not equal to the number of electrons in which one of the following ?

The number of conformational isomers possible of n-butane about C_(2)-C_(3) bond

The number of compounds showing enantiomers among the following compounds is Butan-2-ol, 2-Hydroxypropanoic acid, 2-Methylhexane, 2-Chlorobutane, 2-Bromo-2-chlorobutane, 2-Methylbutanoic acid, isopropyl chloride

The number of compounds which show tautomerism among the following is

The number of compounds which are more reactive towards electrophilic substitution than p-xylene? Benzene, Toluene, Mesitylene, o-xylene, m-xylene.

The number of collisions depends on A) mean free pathB) pressure C) temperature

The number of cis-trans isomers with molecular formula C_2BrClFI is

The number of chiral compounds produced upon monochlorination of 2-methylbutane is :

The number of chain isomers for C_(5)H_(12) is

The number of chain isomers possible for hydrocarbon C_(5)H_(12) is

The number of carbon monoxide molecular present in 1 dm^3 at N.T.P. is _________ .

The number of C-C sigma bonds present in 1-butyne is

The number of bridge bonds, the maximum number of planar atoms and the number of electrons involved in the formation of bridge bonds in diborane are x, y and z respectively, then (x+y–z) = ?

The number of bridge hydrogen atoms in diborane is

Thenumber of atoms presents in 20 g of calciumwill equal to the number of atoms presents in (20 g Ca = (1)/(2) Ca) (Ca = (6.023 xx 10^(23))/(2) = 3.012 xx 10^(23))

The number of atoms presentin 0.1 mole of P_(4) (at mass = 31) are

The number of atoms present in one mole of an element is equal to Avogadro number. Which of the following element contains the greatest number of atoms ?

The number of atoms present in 16 g of oxygen is:

The number of atoms present in 142g of Chlorine is

The number of atoms present in 1 g of hydrogen is the same as that in 1 g of oxygen.

The number of atoms present in 1 g of hydrogen gas is the same as are present in

The number of atoms of hydrogen present in 1.5 mole of H_(2)O is

The number of atoms of 0.03 g of aluminium is nearly (Al = 27)

The number of atoms is 100 g of a fcc crystal with density ="10.0 g/cm"^3 and cell edge equal to 200 pm is equal to

The number of atoms in a face centred cubic unit cell is:

The number of atoms in 4.25g of NH_(3) is approximately :

The number of atoms in 100g of a fcc crystal with density=10gcm^(-3) and cell edge as 200gm, is equal to

The number of atoms in 0.1 mole of triatomic gas is :

The number of atoms in 0.1 mole of a triatomic gas is (N_(A) = 6.02 xx 10^(23) "mol"^(-1))

The number of atoms in 0.004 g of magnesium is close to

The number of atoms collinear in H_(3)C-C-=C-C-=C-CH_(3) is

The number of benzene isomers for C_(8)H_(10) ?

The number of angular nodal planes are same in the orbitals:

The number of alkene (structural) isomers possible, each of which on hydrogenation gives 2-methyl pentane

The number of alkali metals which is (are) radioactive.

How many structural isomers exist with the formula C_(4)H_(10)O?