52671 + Interview Questions in Chemistry in Class 11

1.	If 500cm^3 of hydrogen diffused in 16 minutes through a fine hole, how much time does the same volume of ozone (O_3) take for diffusion?
Answer» SOLUTION :78.4 MIN

Discussion

2.	If 500 ml of 0.4 M AgNO_(3) is mixed with 50 ml of 2 M NH_(3) solution then what is the concentration of [Ag(NH_(3))]^(+) in solution (K_(t), [Ag_(NH_(3))]^(+) = 10^(3), K_(f_(2)) [Ag(NH_(3))_(2)]^(+)= 10^(4))
Answer» `3.33 xx 10^(-7) M` `3.33 xx 10^(-5) M` `3 xx 10^(-4) M` `10^(-7) M` Solution :After mixing `[Ag^(+)] = 0.2M, [NH_(3)] = 1M` Due to very high value of `K_(f), Ag^(+)` is mainly CONVERTED into COMPLEX. `Ag_((aq))^(+)+2NH_(3(aq))hArr[Ag(NH_(3))_(2)]_((aq))^(+)` `{:(0.2,1,),(x,0.6,02):}` `{:([Ag(NH_(3))_(2)]_((aq))^(+)hArr,[Ag(NH_(3))]_((aq))^(+),+NH_(3(aq))),(0.2-y,y,0.6+y),(0.2,,0.6):}` `(1)/(K_(f_(2))) = (y xx 0.6)/(0.2) = (1)/(10^(4))` `y = [Ag(NH_(3))]^(+) = 3.33 xx 10^(-5) M`

Discussion

3.	if 500 mL of 0.4 M AgNO_3 is mixed with 500 mL of 2M NH_3 solution the what is the concentration ofAg (NH_3 ) ^(+)in solution?[Given :K_(f_1) [Ag (NH_3) ^(+)] =10 ^(3) , K _(f_2)[Ag (NH_3)_2^(+) ]= 10^(4) ]
Answer» ` 3.33 xx 10^(-7)M` ` 3. 33 xx 10^(-5 )M` ` 3 xx 10^(-4) M` ` 10 ^(-7) ` Solution :After MIXING ,` [AG^(+) ] =0.2 M, [NH_3]=1M` ` K_(f_1) xx K_(f_2)=10 ^(7) ` Due to high `K_f` value , most of the `Ag^(+) ` converted into` [Ag(NH_3)_2]^(+) ` `{:( Ag^(+) +,2NH_3 hArr, [Ag(NH_3)_2 ]^(+)), (0.2 M, 1M, 0), (, 1-04-0.6M, 0.2M):} ` ` {:([Ag(NH_3)_2]^(+) ,hArr ,Ag(NH_3)^(+), +NH_3) ,( 0.2 M, 0, 0.6M),( 0.2-y, y, 0.6+y),(~~0.2 , , ~~0.6):}` ` (1)/(10^(4) )= (yxx 0.6)/(0.2) =3y rArry =3.33 xx 10 ^(-5) M`

Discussion

4.	If 50ml of 0.2M KOH is added to 40 mlof 0.5 M HCOOH. the pH of the resulting solutions is (Ka = 1.8 xx 10^(-4) log 18= 1.26)
Answer» ` 3.74` ` 5.64` ` 7. 57 ` ` 3.42` Solution :In complete neutralisation ` THEREFORE" Acidic BUFFER pH " = pKa +log ""( S)/(A) ` ` = 4- log 1.8 + log"" ( 50 XX 0.2 )/(40 xx 0.5 -50 xx 0.2 ) ` ` =4-0.26 +log "" (10)/(20 - 10 )= 3.74`

Discussion

5.	If 50 kJ of energy is needed for muscular work to walk a distance of 1 km, then how much glucose one has to consume to walk a distance of 5km provided only 30% energy is available for muscular work. The enthalpy of combustion of glucose in 3000 kJ mol^(-1).
Answer» 75 g 30 g 180 g 150 g Solution :ENERGY consumed for walking a DISTANCE of 5km = `150 xx 5 = 750 kJ` Energy provided by 1 mol of GLUCOSE= 3000 kJ Actual energy provide = `3000 xx (30)/(100) = 900 kJ` 900 kJ of energy require glucose = 180 g 750 kJ of energy require glucose = `(180 xx 750)/(900) = 150 g`

Discussion

6.	If 5.0 g of Al react with 4.45 g of O_(2), empirical formula of aluminium oxide is
Answer» `Al_(2)O_(3)` `AlO_(2)` `Al_(2)O` `AlO_(3)` Solution :Al : O weight 5 : 4.45 MOLES = `(5)/(27):(4.45)/(16)` = 80 : 120 = 2 : 3

Discussion

7.	If 5 ml of methane is completely burnt the volume of oxygen required and the volume of CO_(2) formed under the same conditions are
Answer» 5 ML , 10 ml 10 ml , 5 ml 5 ml , 15 ml 10 ml , 10 ml ANSWER :A

Discussion

8.	If 40g of CaCO_3 is treated with 40g of HCl, which of the reactants will acts as limiting reagent?
Answer» `CaCO_3` HCl Both (a) and (b) None of these Solution :`underset("1 mole" (100g))(CaCO_3)+underset("2 moles" (73g))(2HCL) to CaCl_2+H_2O+CO_2` 100g of `CaCO_3` reacts with 73g of HCl 40g of `CaCO_3 " will reacts with " 73/100xx40=29.2g` of HCl SINCE `CaCO_3` iscompletely consumed and some AMOUNT (40-29.2=10.8g) ofHCl remains unreacted and hence, `CaCO_3` is limiting reagent.

Discussion

9.	If 4 g of NaOH dissolves in 36 g of H_(2)O, calculate the mole fraction of each component in the solution. Also, determine the molarity of solution (specific gravity of solution is 1 g mL^(-1)).
Answer» SOLUTION :NUMBER of moles of NaOH, `n_(NaOH)= (4)/(40) = 0.1` mol `{n=("Mass(g)")/("Molar mass")}` Similarly, `n_(H_(2)O)=(36)/(18)=2` mol Mole fraction of solute `X_(NaOH) = ("moles of NaOH")/("moles of NaOH" + "moles of "H_(2)O)` `X_(NaOH)=(0.1)/(0.1+2)=0.0476` `X_(H_(2)O)=(n_(H_(2)O))/(n_(NaOH)+n_(H_(2)O))` `=(2)/(0.1+2)=0.9524` Total mass of solution `=("mass of solute")+("mass of solvent")` `=4+36=40g` Volume of solution `=("Mass of solution")/("SPECIFIC gravity")` `=(40g)/(1g mL^(-1))=40 mL` Molarity `=("Moles of solute " xx 1000)/("Volume of solution(mL)")` `=(0.1xx1000)/(40) = 2.5M`

Discussion

10.	If 32 g of O_(2)contain 6 022 xx 10^23 molecules at NTP then 32 g of S, under same conditions, will contain,
Answer» `6.022 XX 10^(23)` S `3.011 xx 10^(23)` S `12.044 xx 10^(23) S` `1 xx 10^(23) S` ANSWER :A

Discussion

11.	If 3.1gm Phospherous is present in a sample ofCa_(3)(PO_(4))_(2) the what is the weight of oxygen in the sample?
Answer» Solution :Mol. WT of `Ca_(3)(PO_(4))_(2)` =310 gms. It contains 62g of phasphorus `:.` wt. of `Ca_(3)(PO_(4))_(2)` that contains 3.1 G of phosphorous `=(3.1xx310)/(62)`=15.5gm.

Discussion

12.	If 30 mL of H_(2) and 20 mL of O_(2) react to form water, what is left at the end of the experiment ?
Answer» 10 mL of `H_(2)` 5 mL of `H_(2)` 10 mL of `O_(2)` 5 mL of `O_(2)` Solution :`{:(H_(2)(g),+,1//2O_(2)(g),RARR,H_(2)O(g)),("1 MOL",,"1/ mol",,"1 mol"),("1 mL",,"1/2 mL",,"1 mL"),("30 mL",,"15 mL",,"30 mL"):}` VOLUME of `O_(2)` left uncreacted `=20-15=5 mL`

Discussion

13.	If 3 litre of 1 M Ag_(2)SO_(4) is mixed with 4 litre of 1M NaCl solution, then what will be the sum of molarity of all ions?
Answer» 7 M 1 M `2.42` M `1.28` M Answer :D

Discussion

14.	If 3-hexanone is reacted with NaBH_(4) followed by hydrolysis with D_(2)O, the product will be :
Answer» `CH_(3)CH_(2)CH(OD)CH_(2)CH_(2)CH_(3)` `CH_(3)CH_(2)CD(OH)CH_(2)CH_(2)CH_(3)` `CH_(3)CH_(2)CH(OH)CH_(2)CH_(2)CH_(3)` `CH_(3)CH_(2)OD(OD)CH_(2)CH_(2)CH_(3)` Answer :A

Discussion

15.	If 25 mL of CO_(2) diffuses out of a vessel in 75 seconds, what volumeof SO_(2) would diffuse out in the same time under the same conditions ?
Answer» Solution :`(r_(1))/(r_(2))=(v_(1)//t_(1))/(v_(2)//t_(2))=sqrt((M_(2))/(M_(1)))"or"(25//75)/(v_(2)//75)=sqrt((64)/(44))"or"(25)/(v_(2))=sqrt((64)/(44))"or" v_(2)=20.73 mL`

Discussion

16.	If 240g of carbon is taken in a container to convert it completely to CO_(2) but in industry it has taken found that 280g of CO was also formed along with CO_(2). Find the percentage yeild of CO_(2). The reactions occuring are: C + O_(2) rightarrow CO_(2), C + (1/2)O_(2) rightarrow CO
Answer» 0.25 0.5 0.75 1 Answer :B

Discussion

17.	If 25 ml 0.2 M Ca(OH)_2 is neutralized by 10 ml, 1 M HCl than the pH of solution is …..
Answer» 1.37 9 12 7 Solution :for base `CA(OH)_2` MILLIMOLE =`M_1V_1` `=2xxM_1xxV_1` `=2xx0.2 xx25=10` For HCl = `N_2V_2=10xx1` = 10 `THEREFORE` Mole of Acid = Moles of Base So pH = 7.0

Discussion

18.	If 240mL of a gas X diffuses through a porous membrane in 20 min whereas the same volume of methane diffuses in 10 min at the same temperature and pressure, the molar mass in g mol^(-1) of gas X is
Answer» 128 8 64 32 Answer :C

Discussion

19.	If 216g residue is obtained from 0.5 ml silver salt,
Answer» `N = 4` `n = 2` MOLAR MASS of salt `=718g//MOL` Molar of mass of sat `=388g mol` Solution :`0.5 xx n = (216)/(108)`mol of `Ag n = 4` molar mass `=58 +(165) n = 718g//mol`

Discussion

20.	If 200 mL of N//10 HCl were added to 1 g calcium carbonate, what would remain after the reaction ?
Answer» `CaCO_(3)` HCl Neither of the two Parth of both Solution :N//A

Discussion

21.	If 200 MeV energy is released in the fission of a single nucleus of ""_(92)^(235)U how many fissions must occur per second to produce a power of 1k W
Answer» `22222 "sec"^(-1)` `3.2 xx 10^(-11) "sec"^(-1)` `31.25 xx 10^(13) "sec"^(-1)` `31.25 xx 10^(12) "sec"^(-1)` SOLUTION :Energy released PER fission = 200 MeV `=200xx10^(6) eV=200xx10^(6)xx1.6xx10^(-19) J` `=3.2xx10^(-11) J` But ENREGY needed =1 kW `1xx10^(3) W=1xx10^(3) J s^(-1)` Number of fissions required `=("Energy required")/("Energyreleased per fission")` `=(1xx10^(3) J s^(-1))/(3.2xx10^(-11))=3.125 xx10^(13) s^(-1)`

Discussion

22.	If 20 ml of 2xx10^(-5) BaCl_(2) solution is mixed with 20 ml of 1xx10^(-5) M Na_(2)SO_(4) solution, will a ppt. form ? (K_(sp) "for" BaSO_(4) " is" 1.0xx10^(-10))
Answer» ANSWER :No

Discussion

23.	If 2-pentanone is reacted with NaBH_(4) follwed by hydrolysis with D_(2)O the product will be
Answer» `CH_(3)CH(OD)CH_(2)CH_(2)CH_(3)` `CH_(3)CD(OH)CH_(2)CH_(2)CH_(3)` `CH_(3)CH(OH)CH_(2)CH_(2)CH_(3)` `CH_(3)CD(OD)CH_(2)CH_(2)CH_(3)` Answer :A

Discussion

24.	If 2 moles of solute is dissolved in 500 g solvent then the molality of solution is ..........
Answer» 2.5 1 4 0.4 Answer :C::D

Discussion

25.	If 2 litres of butane is completely burnt the volume of CO_(2) obtained under the same conditions would be
Answer» 2 lit 4 lit 6 lit 8 lit Answer :D

Discussion

26.	If 1m solution of benzoic acid in benzene has a freezing point depression of 3.84 ^(@)C . (K_(f)=5.12^(@)C mol^(-1)kg) and boiling point elevation of 2.53^(@)C(K_(b) =2.53^(@)C "mol"^(-1) kg), then select the correct statement/s :lt brgtstatement I : there aredimar formation when under =going freezing Statement II : there are no change when undergoing boiling Statement III : reverse of I and II ltbr. Statement IV : dimer formation in freezing and boiling state
Answer» I, II II, III III, I only I Answer :a

Discussion

27.	If 1.50g of H_(2)C_(2)O_(4).2H_(2)O were heated to drive of the water of hydration, how much anhydrous H_(2)C_(2)O_(4) would remain?
Answer» 0.34g 0.92g 1.07g `1.50g` ANSWER :C

Discussion

28.	If 150cc of CO effused in 25 seconds, what volume of methane would effuse in the same time?
Answer» ANSWER :198.5cc

Discussion

29.	If 150 kJ of energy is needed for muscular work to walk a distance of one km , then how muchof glucoseone has to consumeto walk a distanceoffive km, provided only 30% energy is available for muscular work. Theenthalpy of combustion of glucoseis 3000kJ mol^(-1)
Answer» 75g 30g 180g 150g Solution :Energy consumed for walking a distance of5 km `= 150 xx5kJ =750 kJ` 1 mole of glucose , `C_(6)H_(12)O_(6) ( 180g)` gives THEORETICALLY energy `= 3000kJ` Actual energy available`= ( 30)/( 100) XX 3000 = 900 kJ` Thus, for 900kJ of energy , glucose required `= 180 g` `:. `For 750 kJ of energy , glucose required`= ( 180)/( 900) xx750 g = 150 g`

Discussion

30.	If 1.5 moles of oxygen combine with Al to form Al_(2)O_(3). The mass of Al in grams. (Atomic mass of Al = 27) used in the reaction is :
Answer» 2.7 54 40.5 81 Solution :`underset("2 mol")(2Al+)3//2underset("1.5 mol")(O_(2)RARR)underset("1 mol")(Al_(2)O_(3))` Mass of Al in grams USED `=2xx27=54` G

Discussion

31.	If 1.27 g Cu is obtained by reduction of one sample of Cu_(2)O then the amount of oxygen in sample is .......... g.
Answer» 16 8 1.6 0.16 Solution :MASS of Cu in SAMPLE of `Cu_(2)O=1.27g` Mass of O in sample `=16 g` If `Cu 127 g = O` is 16 g `:.` If Cu `1.27g=(?)` `:.(16xx1.27)/(127) = 0.16g` oxygen

Discussion

32.	If 1.26 g of oxalic acid is dissolved in 250 mL of solution, find its normality. The equivalent mass of oxalic acid is 63.
Answer» SOLUTION :N//A

Discussion

33.	If 11.1 mg of CaCl_(2) and 12 mg of MgSO_(4) are present in 2 L of water, what is its hardness (in gram CaCO_(3)/ppm)?
Answer» 5 10 15 20 Solution :`underset(40+35.5 times 2)(CaCl_(2)) equiv underset(40+12+48)(CaCO_(3))` `=111 times 10^(3)mg=100 times 10^(3)mg` `underset(underset(=120 times 10^(3)mg)(24+32+64))(MgSO_(4)) equiv underset(underset(=100 times 10^(3)mg)(40+12+40))(CaCO_(3))` `111 times 10^(3)" mg of "CaCl_(2)=100 times 10^(3)" mg of "CaCO_(3)` `11.1" mg of "CaCl_(2)=(100 times 10^(3) times 11.1)/(111 times 10^(3))mg` of ` CaCO_(3)=` 10 of `CaCO_(3)` SIMILARLY, `120 times 10^(3)" mg of "MgSO_(4)` `=100 times 10^(3)" mg of "CaCO_(3)` 12 mg of `MgSO_(4)=(100 times 10^(3))/(120 times 10^(3)) times 12" mg of "CaCO_(3)` `""=10" mg of "CaCO_(3)` In 2 L of water, total weight of `CaCO_(3)` `=10+10=20` mg In 1 L of water, total weight of `CaCO_(3)` `20/2mg=10mg` In `10^(6)` mg of water, total weight of `CaCO_(3)=10` mg So, in `10^(6)` part water, hardness of water in terms of `CaCO_(3)=10` ppm

Discussion

34.	If 11.1 mg of CaCl_2 and 12mg of MgSO_4are present in 2 litres of water, what is its hardness (in grams of CaCO_3/ppm)?
Answer» 5 10 15 20 Answer :B

Discussion

35.	If 10^(21) molecules are removed from 200 mg of CO_(2), the number of moles of CO_(2) left is
Answer» `2.88xx10^(-3)` `28.8xx10^(-3)` `0.288xx10^(-3)` `1.66xx10^(-2)` ANSWER :A

Discussion

36.	If 100mL of 1M HCl is added to 150mL of 1M NaOH, What is the final nature and concentration of resultant solution.
Answer» Solution :NUMBER of MILLIMOLES of acid `=100xx1=100` Number of millimoles of base `=150xx1=150` Base is in excess. Hence resultant solution is basic and concentration`=(150-100)/(250)=(50)/(250)=0.2M`

Discussion

37.	If 100 mL of the acid is neutralised by 100 mL of 4 M NaOH, the purity of concentrated HCl (sp. Gravity =1.2) is :
Answer» 0.12 0.98 0.73 0.43 Solution :N//A

Discussion

38.	If 100 ml hydrogen chloride is completely decomposed the volume of H_(2) formed will be (P and T are constant).
Answer» 20ml 200ml 100ml 50ml Solution :`2HCL RARR H_(2)+Cl_(2)`

Discussion

39.	If 100 mt. of acid 2NH_(2)O_(2) is allowed to react with KMnO_(4) solution till there is a light tinge of purple colour. The volume of oxygen produced at STP is
Answer» 2.24L 1.12 L 3.36L 4.48L Solution :11.2 VOL `H_2O_2 to 2N` 100 ML of 2N (i.e., 11.2 Vol) of `H_2O_2` produce 1.12 LT of Oxygen

Discussion

40.	If ten volumes of dihydrogen gases react with five volumes of dioxygen gases that, how many volumes of water vapour would be produced ?
Answer» Solution :`underset(2 volumes)(2H_(2(G))) + underset(1 volume)(O_(2(g))) rarr underset(2 volumes)(2H_(2)O)` Thus 2 volumes of `H_(2)`REACTS with 1 volume of `O_(2)` to produce 2 volumes of `H_(2)O_((g))`. `:.` 10 volumes of `H_(2)`WOULD react with 5 volumes of `O_(2)` to produce 10 volumes of `H_(2)O_((g))` , Thus 10 volumes of `H_(2)O` will be produced.

Discussion

41.	If 10 gm of a gas at atmospheric pressure is cooled from 273°C to 0°C keeping the volume constant, its pressure would become
Answer» 2 ATM 273 atm 1/273 atm 1/2 atm ANSWER :B

Discussion

42.	If 10^(-4) dm^(3) of water is introduced into a 1.0 dm^(3) flask at 300 K, how many moles of water are in the vapour phase when equilibrium is established ? (Given : Vapour pressure of H_(2)O at 300 K is 3170 Pa , R=8.314 JK^(-1)mol^(-1))
Answer» `4.46xx10^(-2)mol` `1.27xx10^(-3)mol` `5.5xx10^(-3)mol` `1.53xx10^(-2)mol` Solution :Vapour PRESSURE does not DEPEND upon the amount of WATER or size of the vessel. Hence, P=3170Pa. Also, `V=1 dm^(3)=10^(-3), T=300" K"` PV=nRT, `N=(PV)/(RT)=(3170xx10^(-3))/(8.314xx300)` `=1.27xx10^(-3)`

Discussion

43.	If 10^(-4) dm^(3) of water is introduced into a 1.0 dm^(3). Flask at 300 K, calculate the number of moles of water is in vapour phase when equililbrium is established ? (V.P. of H_(2)O at 300 K is 3170 Pa )
Answer» Solution :`P_(H_(2)O) = 3170 Pa = 3.17 xx 10^(-2)` atm From the ideal gas equation, PV = NRT NUMBER of moles, `n = (PV)/(RT)` ` = (3.17 xx 10^(-2) xx 1)/(0.0821 xx 300) = 1.27 xx 10^(-3)` mol

Discussion

44.	If 1 mole of CH_(3)COOH and 1 mole of C_(2)H_(5)OH are taken in 1 litre flask, 50% of CH_(3)COOH is converted into ester as, CH_(3)COOH_((l))+C_(2)H_(5)OH_((l))hArrCH_(3)COOC_(2)H_(5)(l)+H_(2)O_((l)) There is 33% conversion of CH_(3)COOH into ester, if CH_(3)COOH "and" C_(2)H_(5)OH have been taken initially in molar ratio x:1, find x.
Answer» Solution :`CH_(3)COOH_((l))+C_(2)H_(5)OH_((l))hArrCH_(3)COOC_(2)H_(5(l)+H_(2)O_((l))` `1-0.5 1-0.5 0.5 0.5` So, `K_(C)=(0.5xx0.5)/(0.5xx0.5)=1` Now let a moles of `CH_(3)COOH "and" b "moles of" C_(2)H_(5)OH` are TAKEN: `a-(a)/(3) b-(a)/(3) (a)/(3) (a)/(3)` So, `K_(c)=((a//3)XX(a//3))/(2a//3xx(b-(a)/(3))) or 2(b-(a)/(3))=(a)/(3)` or `2b=a` or `(a)/(b)=(2)/(1)`

Discussion

45.	If 1 mole H_(2) is reacted with 1 mole of the following compound. Which double bond will be hydrogenated ?
Answer» c b a d Answer :D

Discussion

46.	If 1 mL of water contains 20 drops, what is the number of water molecules in the one drop of water? (A = Avogadro's number)
Answer» `(0.5)/(18)`A `0.05`A `(0.05)/(18)`A 0.5 A Solution :c) `therefore` 18 mL = 18G of WATER contains = `20 xx 18` drops = A molecules `therefore` 1 drop contians = (A)/(20 xx 18)` molecules = `(0.05A)/(18)` molecules

Discussion

47.	If 1 gram of each of the following gases are taken at STP, which of the gases will occupy (a) greatest volume and (b) smallest volume ? CO,H_(2)O,CH_(4),NO
Answer» Solution :MOLAR VOLUME ofa gas, i.e., volume of 1 mole of the gas =22.7 L at STP 1 mole of CO=28 g, i.e., 28 g of CO have volume =22.7 L at STP `:.` 1 g of CO will have volume `=(22.7)/(28)` L at STP Similarly, `""1 g of H_(2)O" vapour"=(22.7)/(18)`L,1 g `CH_(4)=(22.7)/(16)"L",1 g NO=(22.7)/(30)"L"` Thus, 1 g of `CH_(4)` will occupy MAXIMUM volume and 1 g of NO will occupy minimum volume at STP.

Discussion

48.	If 1 kg of water contains 12 mg magnesium sulphate its degree of hardness is
Answer» 50 ppm 60 ppm 12 ppm 10 ppm Solution :`13 MG MgSO_(4) rArr 12XX10^(-3) mg of MgSO_(4)` `MgSO_(4)` HARDNESS `=(12xx10^(-3)g)/(10^(3)g)xx10^(6)g=12` ppm `rArr 12g of MgSO_(4)` in `10^(6)g` of water hardness in terms of `CaCO_(3)=12xx(100)/(12)=10` ppm

Discussion

49.	If 1 kg of water contains 12 mg of magnesium sulphate its degree of hardness is
Answer» 50 PPM 60 ppm 12 ppm 10 ppm Answer :D

Discussion

50.	If 1 g of each of the following gases are taken at STP, which of the gases will occupy (a) greatest volume and (b) smallest volume ?CO, H_(2)O, CH_(4), NO
Answer» SOLUTION :From Avogardro.s law, we know that Bolume of 1 mole of GAS = gram molecular mass = 22.4 L at STP. Volume of occupied by 28 g CO (1 MOL CO) = 22.4 L at STP. (`because` Molar mass of `CO=12+16=28 g mol^(-1)`) `terefore` Volume occupied by 1 g `CO=(22.4)/(28)` L at STP. Similarly, Volume occupied by 1 g `H_(2)O=(22.4)/(18)` L at STP.(`because` Molar mass of `H_(2)O = (2xx1)+16)=18 g mol^(-1)`) Volume occupied by 1 g `CH_(4)=(22.4)/(16)` L at STP.(`because` Molar mass of `CH_(4)=12+(4xx1)=16 g mol^(-1)`) Volume occupied by 1 g NO `= (22.4)/(30)` L at STP.(`because` Molar mass of NO `= 14+16 = 30 g mol^(-1)`) Hence, 1 g `CH_(4)` will occupy maximum volume and 1 g of NO will occupy minimum volume at STP.

Discussion

Explore topic-wise InterviewSolutions in Current Affairs.

If 500cm^3 of hydrogen diffused in 16 minutes through a fine hole, how much time does the same volume of ozone (O_3) take for diffusion?

If 500 ml of 0.4 M AgNO_(3) is mixed with 50 ml of 2 M NH_(3) solution then what is the concentration of [Ag(NH_(3))]^(+) in solution (K_(t), [Ag_(NH_(3))]^(+) = 10^(3), K_(f_(2)) [Ag(NH_(3))_(2)]^(+)= 10^(4))

if 500 mL of 0.4 M AgNO_3 is mixed with 500 mL of 2M NH_3 solution the what is the concentration ofAg (NH_3 ) ^(+)in solution?[Given :K_(f_1) [Ag (NH_3) ^(+)] =10 ^(3) , K _(f_2)[Ag (NH_3)_2^(+) ]= 10^(4) ]

If 50ml of 0.2M KOH is added to 40 mlof 0.5 M HCOOH. the pH of the resulting solutions is (Ka = 1.8 xx 10^(-4) log 18= 1.26)

If 50 kJ of energy is needed for muscular work to walk a distance of 1 km, then how much glucose one has to consume to walk a distance of 5km provided only 30% energy is available for muscular work. The enthalpy of combustion of glucose in 3000 kJ mol^(-1).

If 5.0 g of Al react with 4.45 g of O_(2), empirical formula of aluminium oxide is

If 5 ml of methane is completely burnt the volume of oxygen required and the volume of CO_(2) formed under the same conditions are

If 40g of CaCO_3 is treated with 40g of HCl, which of the reactants will acts as limiting reagent?

If 4 g of NaOH dissolves in 36 g of H_(2)O, calculate the mole fraction of each component in the solution. Also, determine the molarity of solution (specific gravity of solution is 1 g mL^(-1)).

If 32 g of O_(2)contain 6 022 xx 10^23 molecules at NTP then 32 g of S, under same conditions, will contain,

If 3.1gm Phospherous is present in a sample ofCa_(3)(PO_(4))_(2) the what is the weight of oxygen in the sample?

If 30 mL of H_(2) and 20 mL of O_(2) react to form water, what is left at the end of the experiment ?

If 3 litre of 1 M Ag_(2)SO_(4) is mixed with 4 litre of 1M NaCl solution, then what will be the sum of molarity of all ions?

If 3-hexanone is reacted with NaBH_(4) followed by hydrolysis with D_(2)O, the product will be :

If 25 mL of CO_(2) diffuses out of a vessel in 75 seconds, what volumeof SO_(2) would diffuse out in the same time under the same conditions ?

If 240g of carbon is taken in a container to convert it completely to CO_(2) but in industry it has taken found that 280g of CO was also formed along with CO_(2). Find the percentage yeild of CO_(2). The reactions occuring are: C + O_(2) rightarrow CO_(2), C + (1/2)O_(2) rightarrow CO

If 25 ml 0.2 M Ca(OH)_2 is neutralized by 10 ml, 1 M HCl than the pH of solution is …..

If 240mL of a gas X diffuses through a porous membrane in 20 min whereas the same volume of methane diffuses in 10 min at the same temperature and pressure, the molar mass in g mol^(-1) of gas X is

If 216g residue is obtained from 0.5 ml silver salt,

If 200 mL of N//10 HCl were added to 1 g calcium carbonate, what would remain after the reaction ?

If 200 MeV energy is released in the fission of a single nucleus of ""_(92)^(235)U how many fissions must occur per second to produce a power of 1k W

If 20 ml of 2xx10^(-5) BaCl_(2) solution is mixed with 20 ml of 1xx10^(-5) M Na_(2)SO_(4) solution, will a ppt. form ? (K_(sp) "for" BaSO_(4) " is" 1.0xx10^(-10))

If 2-pentanone is reacted with NaBH_(4) follwed by hydrolysis with D_(2)O the product will be

If 2 moles of solute is dissolved in 500 g solvent then the molality of solution is ..........

If 2 litres of butane is completely burnt the volume of CO_(2) obtained under the same conditions would be

If 1.50g of H_(2)C_(2)O_(4).2H_(2)O were heated to drive of the water of hydration, how much anhydrous H_(2)C_(2)O_(4) would remain?

If 150cc of CO effused in 25 seconds, what volume of methane would effuse in the same time?

If 150 kJ of energy is needed for muscular work to walk a distance of one km , then how muchof glucoseone has to consumeto walk a distanceoffive km, provided only 30% energy is available for muscular work. Theenthalpy of combustion of glucoseis 3000kJ mol^(-1)

If 1.5 moles of oxygen combine with Al to form Al_(2)O_(3). The mass of Al in grams. (Atomic mass of Al = 27) used in the reaction is :

If 1.27 g Cu is obtained by reduction of one sample of Cu_(2)O then the amount of oxygen in sample is .......... g.

If 1.26 g of oxalic acid is dissolved in 250 mL of solution, find its normality. The equivalent mass of oxalic acid is 63.

If 11.1 mg of CaCl_(2) and 12 mg of MgSO_(4) are present in 2 L of water, what is its hardness (in gram CaCO_(3)/ppm)?

If 11.1 mg of CaCl_2 and 12mg of MgSO_4are present in 2 litres of water, what is its hardness (in grams of CaCO_3/ppm)?

If 10^(21) molecules are removed from 200 mg of CO_(2), the number of moles of CO_(2) left is

If 100mL of 1M HCl is added to 150mL of 1M NaOH, What is the final nature and concentration of resultant solution.

If 100 mL of the acid is neutralised by 100 mL of 4 M NaOH, the purity of concentrated HCl (sp. Gravity =1.2) is :

If 100 ml hydrogen chloride is completely decomposed the volume of H_(2) formed will be (P and T are constant).

If 100 mt. of acid 2NH_(2)O_(2) is allowed to react with KMnO_(4) solution till there is a light tinge of purple colour. The volume of oxygen produced at STP is

If ten volumes of dihydrogen gases react with five volumes of dioxygen gases that, how many volumes of water vapour would be produced ?

If 10 gm of a gas at atmospheric pressure is cooled from 273°C to 0°C keeping the volume constant, its pressure would become

If 10^(-4) dm^(3) of water is introduced into a 1.0 dm^(3) flask at 300 K, how many moles of water are in the vapour phase when equilibrium is established ? (Given : Vapour pressure of H_(2)O at 300 K is 3170 Pa , R=8.314 JK^(-1)mol^(-1))

If 10^(-4) dm^(3) of water is introduced into a 1.0 dm^(3). Flask at 300 K, calculate the number of moles of water is in vapour phase when equililbrium is established ? (V.P. of H_(2)O at 300 K is 3170 Pa )

If 1 mole H_(2) is reacted with 1 mole of the following compound. Which double bond will be hydrogenated ?

If 1 mL of water contains 20 drops, what is the number of water molecules in the one drop of water? (A = Avogadro's number)

If 1 gram of each of the following gases are taken at STP, which of the gases will occupy (a) greatest volume and (b) smallest volume ? CO,H_(2)O,CH_(4),NO

If 1 kg of water contains 12 mg magnesium sulphate its degree of hardness is

If 1 kg of water contains 12 mg of magnesium sulphate its degree of hardness is

If 1 g of each of the following gases are taken at STP, which of the gases will occupy (a) greatest volume and (b) smallest volume ?CO, H_(2)O, CH_(4), NO